optimization

Adding thousand separator while printing a number [duplicate]

烂漫一生 提交于 2021-01-04 02:30:40
问题 This question already has answers here : How to print number with commas as thousands separators? (27 answers) Closed 7 years ago . I don't really know the "name" for this problem, so it might be a incorrect title, but the problem is simple, if I have a number for example: number = 23543 second = 68471243 I want to it make print() like this. 23,543 68,471,243 I hope this explains enough or else add comments. Any help is appreciated! 回答1: If you only need to add comma as thousand separator and

Scipy Optimize is only returning x0, only completing one iteration

青春壹個敷衍的年華 提交于 2021-01-03 06:12:39
问题 I am using scipy optimize to get the minimum value on the following function: def randomForest_b(a,b,c,d,e): return abs(rf_diff.predict([[a,b,c,d,e]])) I eventually want to be able to get the optimal values of (a) and (b) given the arguments (c,d,e). However, just to learn how to work the optimize function, I am trying to get the optimal value of (a) given the other arguments. I have the following code: res=optimize.minimize(randomForest_b, x0=45,args=(119.908500,65.517527,2.766103,29.509200)

Scipy Optimize is only returning x0, only completing one iteration

半世苍凉 提交于 2021-01-03 06:12:19
问题 I am using scipy optimize to get the minimum value on the following function: def randomForest_b(a,b,c,d,e): return abs(rf_diff.predict([[a,b,c,d,e]])) I eventually want to be able to get the optimal values of (a) and (b) given the arguments (c,d,e). However, just to learn how to work the optimize function, I am trying to get the optimal value of (a) given the other arguments. I have the following code: res=optimize.minimize(randomForest_b, x0=45,args=(119.908500,65.517527,2.766103,29.509200)

How to optimize a function that matches observations according to certain criteria

狂风中的少年 提交于 2020-12-30 04:20:30
问题 I am looking for a more efficient way of doing an operation with a given dataframe. library(purrr) library(dplyr) Here is a step by step description: First, there is the function possible_matches , that for each observation i in df , gives the index of rows that are possibly matchable to i , which are going to be used on the next step: possible_matches <- function(i, df) { k1 <- df$j[df$id_0 == df$id_0[i]] j2 <- setdiff(df$j, k1) k2 <- map(j2, ~ df$j[df$id_0[.] == df$id_0]) k3 <- map(k2, ~

How to optimize a function that matches observations according to certain criteria

泪湿孤枕 提交于 2020-12-30 04:09:55
问题 I am looking for a more efficient way of doing an operation with a given dataframe. library(purrr) library(dplyr) Here is a step by step description: First, there is the function possible_matches , that for each observation i in df , gives the index of rows that are possibly matchable to i , which are going to be used on the next step: possible_matches <- function(i, df) { k1 <- df$j[df$id_0 == df$id_0[i]] j2 <- setdiff(df$j, k1) k2 <- map(j2, ~ df$j[df$id_0[.] == df$id_0]) k3 <- map(k2, ~

How to optimize a function that matches observations according to certain criteria

帅比萌擦擦* 提交于 2020-12-30 04:09:41
问题 I am looking for a more efficient way of doing an operation with a given dataframe. library(purrr) library(dplyr) Here is a step by step description: First, there is the function possible_matches , that for each observation i in df , gives the index of rows that are possibly matchable to i , which are going to be used on the next step: possible_matches <- function(i, df) { k1 <- df$j[df$id_0 == df$id_0[i]] j2 <- setdiff(df$j, k1) k2 <- map(j2, ~ df$j[df$id_0[.] == df$id_0]) k3 <- map(k2, ~

How to optimize a function that matches observations according to certain criteria

痞子三分冷 提交于 2020-12-30 04:08:31
问题 I am looking for a more efficient way of doing an operation with a given dataframe. library(purrr) library(dplyr) Here is a step by step description: First, there is the function possible_matches , that for each observation i in df , gives the index of rows that are possibly matchable to i , which are going to be used on the next step: possible_matches <- function(i, df) { k1 <- df$j[df$id_0 == df$id_0[i]] j2 <- setdiff(df$j, k1) k2 <- map(j2, ~ df$j[df$id_0[.] == df$id_0]) k3 <- map(k2, ~

Is there a way to flush the entire CPU cache related to a program?

荒凉一梦 提交于 2020-12-29 12:08:36
问题 On x86-64 platforms, the CLFLUSH assembly instruction allows to flush the cache line corresponding to a given address. Instead of flushing the cache related to a specific address, would there be a way to flush the entire cache (either the cache related to the program being executed, or the entire cache), for example by making it full of dummy contents (or any other approach I would not be aware of): using only standard C++17? using standard C++17 and compiler intrinsics if necessary? What

Is there a way to flush the entire CPU cache related to a program?

亡梦爱人 提交于 2020-12-29 12:00:17
问题 On x86-64 platforms, the CLFLUSH assembly instruction allows to flush the cache line corresponding to a given address. Instead of flushing the cache related to a specific address, would there be a way to flush the entire cache (either the cache related to the program being executed, or the entire cache), for example by making it full of dummy contents (or any other approach I would not be aware of): using only standard C++17? using standard C++17 and compiler intrinsics if necessary? What

Is the compiler allowed to optimise out private data members?

≯℡__Kan透↙ 提交于 2020-12-29 04:59:50
问题 If the compiler can prove that a (private) member of a class is never used, including by potential friends, does the standard allow the compiler to remove this member from the memory footprint of the class? It is self-evident that this not possible for protected or public members at compile time, but there could be circumstances where it is possible regarding private data members for such a proof to be constructed. Related questions: Behind the scenes of public, private and protected (sparked