operators

问题 #include <iostream> using namespace std; class NumDays { private: int hour; int day; void simplify(); public: NumDays() { day = 0; hour = 0; } void setData(int d, int h) { hour = h; day = d; simplify(); } int getHour() { return hour; } int getDay() { return day; } NumDays operator++(int); NumDays operator--(int); }; void NumDays::simplify() { hour = 8*day + hour; day = hour / 8; hour = hour % 8; } NumDays NumDays::operator++(int) { NumDays obj1; hour++; simplify(); return obj1; } NumDays

问题 I'm new to RxAndroid and trying to chain responses. I'm using this github API to retrieve data. Along with each issue there are comments link and events link associated with it which I want to fetch and update existing object with list of comments and events to form something like this. [ issue: { comments: [ { . . }, { . . } ] events : [ { . . }, { . . } ] ] ] I could retrieve initial response with following code GitHubService gitHubService = ServiceFactory.createServiceFrom(GitHubService

问题 I'm new to RxAndroid and trying to chain responses. I'm using this github API to retrieve data. Along with each issue there are comments link and events link associated with it which I want to fetch and update existing object with list of comments and events to form something like this. [ issue: { comments: [ { . . }, { . . } ] events : [ { . . }, { . . } ] ] ] I could retrieve initial response with following code GitHubService gitHubService = ServiceFactory.createServiceFrom(GitHubService

问题 I'm working on a physics engine and feel it would help having a better understanding of the speed and performance effects of performing many simple or complex math operations. A large part of a physics engine is weeding out the unnecessary computations, but at what point are the computations small enough that a comparative checks aren't necessary? eg: Testing if two line segments intersect. Should there be check on if they're near each other before just going straight into the simple math, or

问题 I believe there isn't any portable standard data type for 128 bits of data. So, my question is about how efficiently 64 bit operations can be carried out without loss of data using existing standard data-types. For example : I have following two uint64_t type variables: uint64_t x = -1; uint64_t y = -1; Now, how the result of mathematical operations such as x+y, x-y, x*y and x/y can be stored/retrieved/printed ? For above variables, x+y results in value of -1 which is actually a

问题 Just wondering where the rules for operators in C# are actually defined. E.g. where can I see the code which says that == checks the references of two objects? I can see the operator overloads in e.g. the String class but now i'm interested in seeing the 'base' case. Is it just something that the compiler explicitly knows what to do with and therefore there is no code which we can view using tools such as Reflector. 回答1: You can't see it in code (except maybe in the SSCLI, I haven't checked).

问题 This question already has answers here : Why is string “11” less than string “3”? [duplicate] (6 answers) Closed last month . Why does this happen with strings in javascript? 3<=255 true but '3'<='255' false Is it something to do with the operators or the use of strings? 回答1: I guess it is because it compare ascii values of chars and 3 had greater ascii value than 2. In string it compare char by char if 1 char is false it wont compare else 回答2: In first case you are comparing 2 Numbers, in

问题 Following up from my previous question, why is CShell so different from C? 4 - 3 + 1 = 2 in C. 4 - 3 + 1 = 0 in CShell. Any ideas? 回答1: Generally the traditional notation is left to right (left associative) in human papers. So for humans (which used this notation long before c, csh or even any notion of computers): 4 - 3 + 1 = (4 - 3) + 1 = 1 + 1 = 2 Why? I guess that the best answer is because. It's the same as with driving left or right side of road. It really doesn't matter which side as

问题 for example: var s = '3+3'; s.replace(/([\d.]+)([\+\-)([^,]*)/g, function(all, n1, operator, n2) { r = new Number(n1) ??? new Number(n2); return r; } ); note: not using eval() 回答1: Are Variable Operators Possible? Not possible out of the box, but he gives a nice implementation to do it, as follows. Code by delnan. var operators = { '+': function(a, b) { return a + b }, '<': function(a, b) { return a < b }, // ... }; var op = '+'; alert(operators[op](10, 20)); So for your implementation r =

问题 Updated Code that creates array, but ISNT outputting the min/max values. Why isnt this working and how do I get it to automatically remove the min/max value and then reoutput the array? <?php $url = 'https://www.googleapis.com/shopping/search/v1/public/products?key=thekey&country=US&q=nintendo+wii'; $data = curl_init($url); curl_setopt($data, CURLOPT_RETURNTRANSFER, TRUE); curl_setopt($data, CURLOPT_HEADER, 0); $product_result = curl_exec($data); curl_close($data); $arr = json_decode($product