openid

I'm using .Net Open ID ( http://code.google.com/p/dotnetopenid/ ) I'm trying to add OpenId to a website we are using. I'm running the MVC sample out of the box and recieve the following error when selecting Yahoo/Google. No OpenID endpoint found. The error happens on this line of code return openid.CreateRequest(Request.Form["openid_identifier"]).RedirectingResponse.AsActionResult(); What does this error mean? And are there any common trouble-shooting things we can try? Just to add the value in - Request.Form["openid_identifier"] https://www.google.com/accounts/o8/id First, check to make sure

前言： PHP实现QQ快速登录，罗列了三种方法 方法一： 面向过程，回调地址和首次触发登录写到了一个方法页面【因为有了if做判断】， 方法二，三： 面向对象 1.先调用登录方法，向腾讯发送请求， 2.腾讯携带本网站唯一对应参数OPENID,ACCESSTOKEN，返回到对应回调页面， 3.回调页面接受到腾讯的参数后，通过这个两个参数，再发出对应的请求，如查询用户的数据。 4.腾讯做出对应的操作，如返回这个用户的数据给你 即使你没看懂，也没关系，按照我下面的流程来，保证你可以实现。 前期准备： 使用人家腾讯的功能，总得和人家打招呼吧！ QQ互联首页：http://connect.qq.com/ 进入网址后，按如下操作来： 一.进入官网 二.申请创建【网站】应用 三.按要求填写资料 注意网站地址：填写你要设置快速登录的网址，eg:http://www.test.com; 回调地址:填写你发送QQ快速登陆后，腾讯得给你信息，这个信息往此页面接受。eg:http://www.test.com/accept_info.php 【详细的申请填写，请见官方提示，这里不做赘述】 四.申请成功后，完善信息 最终要求，获得APP_ID ，APP_KEY 五.代码部分： 在你对应的PHP文件内写入，如下 方法一， 面向过程法 使用方法：配置$app_id，$app_secret，$my_url后

身份认证即服务(IDaaS ：Identity as a Service) ，也被称为身份和访问管理作为一种服务，使用的是一种云计算的基础设施来安全地管理用户身份和访问实施。在其最基本的层面上，IDaaS可以为云端或内部部署的系统实现单点登录(SSO)。但是它远远不止这些，还包括：访问资源的分配和移除、管理和分析等。 根据 Gartner 2016年的报道显示，IDaaS领域的主流厂商包括有：Okta、微软和Centrify，同时OneLogin、Ping Identity、SailPoint、科纬迅软件服务(Covisint)、Salesforce、灯塔安全(Lighthouse Security，隶属于IBM)和易安信(EMC)/RSA也迅速“登场”了。虽然各公司都能提供IDaaS，但是由于其特征集和功能上的差异，使得某种解决方案较之其他的方案更优于适合某个特定的组织。 来自DocuSign的首席信息官 Eric Johnson 认为，**IDaaS的解决方案将成为你用来访问所有重要的业务应用的一种集中化的机制。正确地选择此类解决方案是非常必要的，这是因为任何停机/掉线都将会导致组织的重大业务中断。**因此当你在判定哪一种IDaaS是最适合你的时候，考虑诸如解决方案的集成能力、单点登录(SSO)方面的体验与安全等方面的因素都是很重要的。 如下这十个问题是由IDaaS的客户

When someone logs into a site using Open ID, what goes on behind the scene? can someone explain to me the work flow/steps of what happens during a typical login from a partner open ID site? (like this site) i.e. when I login at myopenid, what is passed into this site? how does SO know it was a correct login? Patrick Desjardins What is OpenId? OpenID is an open, decentralized , free framework for user-centric digital identity. OpenID takes advantage of already existing internet technology (URI, HTTP, SSL, Diffie-Hellman) and realizes that people are already creating identities for themselves

//获取小程序用户openid 返回值为json字符串 public function GetOpenid() { $request = I('param.'); //获取微信小程序传过来的code $js_code = $request['code']; $curl = curl_init(); //使用curl_setopt() 设置要获得url地址 $url = ' https://api.weixin.qq.com/sns/jscode2session?appid= ' . $this->appid . '&secret=' . $this->secret . '&js_code=' . $js_code . '&grant_type=' . $this->grant_type; curl_setopt($curl, CURLOPT_URL, $url); //设置是否输出header curl_setopt($curl, CURLOPT_HEADER, false); //设置是否输出结果 curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1); //设置是否检查服务器端的证书 curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false); //使用curl_exec(

For years I have used OpenID delegation to log in to Stack Overflow (among other sites) using my own URI as OpenID but having Google handle the authentication. I use the technique described in this Stack Overflow question ; so, my custom OpenID http://tupelo-schneck.org/robert resolves to an HTML page containing this: <link href="https://www.google.com/accounts/o8/ud" rel="openid2.provider" /> <link href="https://www.google.com/profiles/schneck" rel="openid2.local_id" /> Now, however, I have logged into Stack Overflow and had Google tell me " Important notice: OpenID2 for Google accounts is

I'm using Janrain's PHP-OpenID 2.1.3 , and I've managed to get it working with all the providers I have tried except for Google and Yahoo. The major difference here seems to be that Google and Yahoo, unlike most other providers, don't use a user-specific URL, but rather have the user discovery framework all on their end - which throws the default Janrain framework for a loop then it tries to begin the auth request. From what I've seen it looks like it's probably the YADIS discovery that is throwing the error, which should be able to be bypassed since the discovery is on Google or Yahoo's end,