object

Trim white spaces in both Object key and value recursively

由 安稳与你 提交于 2020-01-09 13:14:00
问题 How do you trim white spaces in both the keys and values in a JavaScript Object recursively? I came across one issue in which I was trying to "clean" a user supplied JSON string and send it into my other code for further processing. Let's say we've got a user supplied JSON string whose property key and value are of type "string". However, what's problematic in this case is that the keys and values are not as clean as desired. Say a { " key_with_leading_n_trailing_spaces ": " my_value_with

Trim white spaces in both Object key and value recursively

由 China☆狼群 提交于 2020-01-09 13:08:02
问题 How do you trim white spaces in both the keys and values in a JavaScript Object recursively? I came across one issue in which I was trying to "clean" a user supplied JSON string and send it into my other code for further processing. Let's say we've got a user supplied JSON string whose property key and value are of type "string". However, what's problematic in this case is that the keys and values are not as clean as desired. Say a { " key_with_leading_n_trailing_spaces ": " my_value_with

Core difference between object oriented and object based language

由 人走茶凉 提交于 2020-01-09 12:16:09
问题 I want to know what is the core difference between Object Oriented and Object based languages I have read many post all of them are saying two things Object-oriented language supports all the features of OOPs and Object-based language doesn't support all the features of OOPs like Polymorphism and Inheritance. They are giving example of javascript as object based and java as object oriented Like this post of stackoverflow Difference between object oriented and object based language But I want

mysqli : mysqli_result could not be converted to string

由 此生再无相见时 提交于 2020-01-09 12:08:01
问题 I know there have been asked lots of similair questions like this one, but I just can't translate it to my problem so thats why I ask again. The code used to work fine but since the mysql is going to be deprecated I wanted to translate to mysqli. I receive the following error when trying to read something from database: Catchable fatal error: Object of class mysqli_result could not be converted to string. It refers to line 12, which is echo $result; FULL CODE: $previd ="10"; $query="SELECT *

mysqli : mysqli_result could not be converted to string

由 扶醉桌前 提交于 2020-01-09 12:02:00
问题 I know there have been asked lots of similair questions like this one, but I just can't translate it to my problem so thats why I ask again. The code used to work fine but since the mysql is going to be deprecated I wanted to translate to mysqli. I receive the following error when trying to read something from database: Catchable fatal error: Object of class mysqli_result could not be converted to string. It refers to line 12, which is echo $result; FULL CODE: $previd ="10"; $query="SELECT *

jQuery compare two DOM object?

由 三世轮回 提交于 2020-01-09 10:25:12
问题 Clicking on an element: $('.my_list').click(function(){ var selected_object = $(this); $('.my_list').each(function(){ var current_object = $(this); if( selected_object == current_object ) alert('FOUND IT !'); }); }); I don't know why, but I don't get the alert message "FOUND IT !". 回答1: You can use the jQuery.is function: Check the current matched set of elements against a selector, element, or jQuery object and return true if at least one of these elements matches the given arguments. if

jQuery compare two DOM object?

由 谁说胖子不能爱 提交于 2020-01-09 10:21:09
问题 Clicking on an element: $('.my_list').click(function(){ var selected_object = $(this); $('.my_list').each(function(){ var current_object = $(this); if( selected_object == current_object ) alert('FOUND IT !'); }); }); I don't know why, but I don't get the alert message "FOUND IT !". 回答1: You can use the jQuery.is function: Check the current matched set of elements against a selector, element, or jQuery object and return true if at least one of these elements matches the given arguments. if

JVM性能优化一些概念简介

由 不羁岁月 提交于 2020-01-09 09:49:48
转自： https://www.iteye.com/blog/pengjiaheng-518623 https://www.iteye.com/blog/pengjiaheng-519471 数据类型 Java虚拟机中，数据类型可以分为两类： 基本类型 和 引用类型 。基本类型的变量保存原始值，即：他代表的值就是数值本身；而引用类型的变量保存引用值。“引用值”代表了某个对象的引用，而不是对象本身，对象本身存放在这个引用值所表示的地址的位置。 基本类型包括：byte,short,int,long,char,float,double,Boolean,returnAddress 引用类型包括： 类类型 ， 接口类型 和 数组 。 堆与栈 堆和栈是程序运行的关键，很有必要把他们的关系说清楚。 栈是运行时的单位，而堆是存储的单位 。 栈解决程序的运行问题，即程序如何执行，或者说如何处理数据；堆解决的是数据存储的问题，即数据怎么放、放在哪儿。 在Java中一个线程就会相应有一个线程栈与之对应，这点很容易理解，因为不同的线程执行逻辑有所不同，因此需要一个独立的线程栈。而堆则是所有线程共享的。栈因为是运行单位，因此里面存储的信息都是跟当前线程（或程序）相关信息的。包括局部变量、程序运行状态、方法返回值等等；而堆只负责存储对象信息。 为什么要把堆和栈区分出来呢？栈中不是也可以存储数据吗 ？ 第一

How to use Object.values with typescript?

由 白昼怎懂夜的黑 提交于 2020-01-09 08:51:30
问题 I am trying to form a comma separated string from an object, const data = {"Ticket-1.pdf":"8e6e8255-a6e9-4626-9606-4cd255055f71.pdf","Ticket-2.pdf":"106c3613-d976-4331-ab0c-d581576e7ca1.pdf"}; const values = Object.values(data).map(x => x.substr(0, x.length - 4)); const commaJoinedValues = values.join(','); console.log(commaJoinedValues); How to do this with TypeScript? getting an error file: severity: 'Error' message: 'Property 'values' does not exist on type 'ObjectConstructor'.' at: '216

Push Object in Array [duplicate]

由 笑着哭i 提交于 2020-01-09 03:55:08
问题 This question already has answers here : Push is overwriting previous data in array (3 answers) Closed 5 months ago . var p = { id: null }; for (var copyArray = [], i = 0; i < 3; i++) { copyArray.push(p); copyArray[i].id = (copyArray.length) - parseInt(1, 10); } console.log(copyArray); All id in copyArray is getting 2 value. Result CopyArray({id=2},{id=2},{id=2}) Doing normal push operation of object in array, and updating the index after insertion. But somehow all id's in the copy array are
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