numbers

I need to transform ordinary numbers to Roman numerals with php and I have this code: <?php function roman2number($roman){ $conv = array( array("letter" => 'I', "number" => 1), array("letter" => 'V', "number" => 5), array("letter" => 'X', "number" => 10), array("letter" => 'L', "number" => 50), array("letter" => 'C', "number" => 100), array("letter" => 'D', "number" => 500), array("letter" => 'M', "number" => 1000), array("letter" => 0, "number" => 0) ); $arabic = 0; $state = 0; $sidx = 0; $len = strlen($roman); while ($len >= 0) { $i = 0; $sidx = $len; while ($conv[$i]['number'] > 0) { if

I want to use C++ with complex numbers. Therefore I included #include <complex> . Now my question is: How do I declare a variable?(so what is the format called for let's say: 1 + i ?) Thanks in advance :-) // 1 + 2i std::complex<double> c(1, 2); The constructor of std::complex has two parameters: The first, wich has the real part of the number. The second, wich has the imaginary part of the number. For example: std::complex<float> my_complex(1,1); //1 + 1i Also, C++11 introduces user defined literals , wich allows us to implement (Or be implemented by the standard library, as in this C++14

The problem requires to generate the n-th element of a sequence that is similar to Fibonacci sequence. However, it's a bit tricky because n is very large (1 <= n <= 10^9). The answer then modulo 1000000007. The sequence is defined as follows: Using generating function, I obtain the following formula: If I use the sequence approach then the answer can be modulo, but it run extremely slow. In fact, I got time limit exceed many times. I also tried to use a table to pre-generate some initial values (cache), still it was not fast enough. In addition, the maximum number of elements that I can store

I have the following code: Double i=17.31; long j=(long) (i*100); System.out.println(j); O/P : 1730 //Expected:1731 Double i=17.33; long j=(long) (i*100); System.out.println(j); O/P : 1732 //Expected:1733 Double i=17.32; long j=(long) (i*100); System.out.println(j); O/P : 1732 //Expected:1732{As expected} Double i=15.33; long j=(long) (i*100); System.out.println(j); O/P : 1533 //Expected:1533{as Expected} I have tried to Google but unable to find reason.I am sorry if the question is trivial. None of the answers seem to deal with why 17.32 acted different. 1. Why it occurred The difference in

This question already has an answer here: What is the JavaScript >>> operator and how do you use it? 7 answers the following function is designed to implement the indexOf property in IE. If you've ever had to do this, I'm sure you've seen it before. if (!Array.prototype.indexOf){ Array.prototype.indexOf = function(elt, from){ var len = this.length >>> 0; var from = Number(arguments[1]) || 0; from = (from < 0) ? Math.ceil(from) : Math.floor(from); if (from < 0) from += len; for (; from < len; from++){ if (from in this && this[from] === elt) return from; } return -1; }; } I'm wondering if it's

Why won't my input resize when I change the type to type="number" but it works with type="text" ? EXAMPLE Email: <input type="text" name="email" size="10"><br/> number: <input type="number" name="email" size="10"> Seem like the input type number does not support size attribute or it's not compatible along browsers, you can set it through CSS instead: input[type=number]{ width: 80px; } Updated Fiddle Incorrect usage. Input type number it's made to have selectable value via arrows up and down. So basically you are looking for "width" CSS style. Input text historically is formatted with