numbers

What is your advice on: compensation of accumulated error in bulk math operations on collections of Money objects. How is this implemented in your production code for your locale? theory behind rounding in accountancy. any literature on topic. I currently read Fowler . He mentions Money type, it's typcal structure (int, long, BigDecimal), but says nothing on strategies. Older posts on money-rounding ( here , and here ) do not provide a details and formality I need. Thoughts I found in the inet relate to "Round half even" as the best way to balance error. Thanks for help. There are many

I currently use this pipe {{ product.productPrice | number:'.2-2' }} And result is 1,000,000.00 but I want to remove the .00 How do you do that? Use this : {{product.productPrice | number: '1.0-0'}} 1.0-0 means: at least one digit before decimal point, 0 digits after decimal point. https://angular.io/api/common/DecimalPipe 来源： https://stackoverflow.com/questions/45955101/decimal-pipe-in-angular-2-commas-only-no-decimal-places

I would like to ask how I can get the length of digits in an Integer. For example: $num = 245354; $numlength = mb_strlen($num); $numlength should be 6 in this example. Somehow I can't manage it to work? Thanks EDIT: The example code above --^ and its respective method mb_strlen(); works just fine. Maybe: $num = 245354; $numlength = strlen((string)$num); Some math sometime helps. Everything you need is to invoke floor(log10($num) + 1) with check for 0. $num = 12357; echo $num !== 0 ? floor(log10($num) + 1) : 1; Basically it does the logarithm with base 10 then makes floor of it and adds 1. More

This question already has an answer here: How do I get a TextBox to only accept numeric input in WPF? 30 answers i want to create a textbox in WPF that only accept numbers... i've reaserched and people say to use keypress event or masked textbox, but they are in windows forms... Maciek For WPF: private void textBox1_PreviewTextInput(object sender, TextCompositionEventArgs e) { if (!char.IsDigit(e.Text, e.Text.Length - 1)) e.Handled = true; } For Windows Forms: private void textBox1_KeyPress(object sender, KeyPressEventArgs e) { if (!char.IsDigit(e.KeyChar) ) e.Handled = true; } 来源： https:/

Is there a better, more elegant (and/or possibly faster) way than boolean isNumber = false; try{ Double.valueOf(myNumber); isNumber = true; } catch (NumberFormatException e) { } ...? Edit : Since I can't pick two answers I'm going with the regex one because a) it's elegant and b) saying "Jon Skeet solved the problem" is a tautology because Jon Skeet himself is the solution to all problems. I don't believe there's anything built into Java to do it faster and still reliably, assuming that later on you'll want to actually parse it with Double.valueOf (or similar). I'd use Double.parseDouble

I am kind of new in the fortran proramming. Can anyone please help me out with the solution. i am having a problem of generating integer random number in the range [0,5] in fortran random number using random_seed and rand What about: program rand_test use,intrinsic :: ISO_Fortran_env real(REAL32) :: r(5) integer :: i(5) ! call init_random_seed() would go here call random_number(r) ! Uniform distribution requires floor: Thanks to @francescalus i = floor( r*6._REAL32 ) print *, i end program francescalus To support the answer by Alexander Vogt, I'll generalize. The intrinsic random_number(u)