numbers

I have a number assigned to a variable, like that: var myVar = 1234; Now I want to get the second digit (2 in this case) from that number without converting it to a string first. Is that possible? So you want to get the second digit from the decimal writing of a number. The simplest and most logical solution is to convert it to a string : var digit = (''+myVar)[1]; or var digit = myVar.toString()[1]; If you don't want to do it the easy way, or if you want a more efficient solution, you can do that : var l = Math.pow(10, Math.floor(Math.log(myVar)/Math.log(10))-1); var b = Math.floor(myVar/l);

This is weird. This is what happens at the JavaScript console in Chrome (version 42.0.2311.135, 64-bit). > 0 < 0 > 00 < 0 > 0.0 < 0 > 00.0 X Uncaught > SyntaxError: Unexpected number Firefox 37.0.2 does the same, although its error message is: SyntaxError: missing ; before statement There's probably some technical explanation regarding the way JavaScript parses numbers, and perhaps it can only happen when tinkering at the console prompt, but it still seems wrong. Why does it do that? The expressions 0.0 and 00.0 are parsed differently. 0.0 is parsed as a numeric literal 1 00.0 is parsed as: 00

After going through the previous develop's trainwreck of code I realized I need to move all of the money based columns to not use floating point math. On the Java side this means using BigDecimal but when using Hibernate/JPA and MySQL 5 what would be the appropriate MySQL data type to make that column? Abimaran Kugathasan DECIMAL and NUMERIC. The recommended Java mapping for the DECIMAL and NUMERIC types is java.math.BigDecimal. The java.math.BigDecimal type provides math operations to allow BigDecimal types to be added, subtracted, multiplied, and divided with other BigDecimal types, with

I have this code in C where I've declared 0.1 as double. #include <stdio.h> int main() { double a = 0.1; printf("a is %0.56f\n", a); return 0; } This is what it prints, a is 0.10000000000000001000000000000000000000000000000000000000 Same code in C++, #include <iostream> using namespace std; int main() { double a = 0.1; printf("a is %0.56f\n", a); return 0; } This is what it prints, a is 0.1000000000000000055511151231257827021181583404541015625 What is the difference? When I read both are alloted 8 bytes? How does C++ print more numbers in the decimal places? Also, how can it go until 55

I have a variable of decimal type and I want to check the number of digits before decimal point in it. What should I do? For example, 467.45 should return 3 . Solution without converting to string (which can be dangerous in case of exotic cultures): static int GetNumberOfDigits(decimal d) { decimal abs = Math.Abs(d); return abs < 1 ? 0 : (int)(Math.Log10(decimal.ToDouble(abs)) + 1); } Note, that this solution is valid for all decimal values UPDATE In fact this solution does not work with some big values, for example: 999999999999998 , 999999999999999 , 9999999999999939 ... Obviously, the

I am developing an application using oracle 11g, Java(struts2) and Hibernate. I have table named mytemp with column mytemp_id which is of type NUMBER(22,0). In my mytemp.hbm.xml file id is as given below <id name="mytempId" type="big_decimal"> <column name="MYTEMP_ID" precision="22" scale="0" /> <generator class="sequence"> <param name="sequence">MYTEMP_TEMP_ID_SEQ</param> </generator> </id> In my Oracle database sequence named "MYTEMP_TEMP_ID_SEQ" is created and working fine in Oracle. Now when I try to insert record using hibernate, it gives me following error org.hibernate.id