numberformatexception

NumberFormatException invalid int “”

由 ↘锁芯ラ 提交于 2019-12-04 06:23:51
问题 I am trying to take the input values from EditText and I want to save it to sqlite Database. I dont know how to use the logcat [also please explain how can I read the errors from the LogCat]. MainActivity.java: package com.example.database; import android.support.v7.app.ActionBarActivity; import android.text.Editable; import android.app.Activity; import android.content.Context; import android.database.sqlite.SQLiteDatabase; import android.database.sqlite.SQLiteDatabase.CursorFactory; import

Getting a NumberFormatException from a numerical EditText field

由 与世无争的帅哥 提交于 2019-12-04 05:46:49
问题 I'm trying to create a for -loop to add views to a layout. The for -loop is working fine (I tried it with initialized variables) but I need to get an integer from an EditText . I used a try-catch and LogCat tells me the following... java.lang.NumberFormatException: invalid int "". The website developers.android.com says this is from incorrectly converting a string to an integer, but I don't understand how I could be incorrectly getting the data from the EditText . This is my code... public

Clojure not catching NumberFormatException

由 核能气质少年 提交于 2019-12-04 03:28:30
问题 In the following code, Clojure (1.2) is printing the wrong message: (try (let [value "1,a"] (map #(Integer/parseInt %) (.split value ","))) (catch NumberFormatException _ (println "illegal argument"))) This should print "illegal argument", but instead it prints a (1#<NumberFormatException java.lang.NumberFormatException: For input string: "a"> . What am I doing wrong? Is this because of the lazy sequence returned by map ? How should it be written? 回答1: The try special form only catches

storing a string arraylist into a double arraylist?

由 廉价感情. 提交于 2019-12-03 09:01:22
I have a string arraylist with numbers like ["51,073","51,074","51,073"] now i want to convert this into a Double ArrayList and calculate the sum of the numbers in the array list. Here is the code : private ArrayList<String> totals = new ArrayList<>(); private ArrayList<Double> demototal = new ArrayList<>(); String total = itemData.getString(ParseBarcode.KEY_TOTAL); totals.add(total); /*converting all values from totals array to Double and add to arraylist demototal*/ for (int i = 0; i < totals.size(); i++) { final String value = totals.get(i); double total_ary = Double.parseDouble(value);

Convert hex color value ( #ffffff ) to integer value

由 青春壹個敷衍的年華 提交于 2019-12-03 04:06:23
问题 I am receiving hex color values from a server (in this form, #xxxxxx , example #000000 for black) How do I convert this to an integer value? I tried doing Integer.valueOf("0x" + passedColor.substring(1, passedColor.length())) to get an even more hextastic 0x000000 result, but this isn't intepreted as an int here, any other suggestions? I receive an error: 08-03 21:06:24.673: ERROR/AndroidRuntime(20231): java.lang.NumberFormatException: unable to parse '0x00C8FBFE' as integer I am using the

Input of big number to avoid NumberFormatException

由 我的未来我决定 提交于 2019-12-02 23:33:26
问题 I have to control input from 1 to 9999999999 (that represents the registration number of school) The primitive type long can only hold up to about 2.000.000.000, how can i store numbers of this size? 回答1: According to this, the long data type can hold values from -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807, using 64 bits. It should be able to hold 9,999,999,999. Are you sure that you are treating that value as a long in all places? 来源： https://stackoverflow.com/questions/9198523

NumberFormatException when trying to parse Strings from .getText();

由 我的未来我决定 提交于 2019-12-02 20:31:43
问题 Exception in thread "AWT-EventQueue-0" java.lang.NumberFormatException: For input string: "Total: 8.78" at sun.misc.FloatingDecimal.readJavaFormatString(Unknown Source) at java.lang.Double.parseDouble(Unknown Source) at PizzaOrder$BtnClicked.<init>(PizzaOrder.java:298) at PizzaOrder$BtnClicked.<init>(PizzaOrder.java:295) at PizzaOrder.addListeners(PizzaOrder.java:102) at PizzaOrder.<init>(PizzaOrder.java:76) at PizzaDriver$1.run(PizzaDriver.java:46) at java.awt.event.InvocationEvent.dispatch

NumberFormatException - Android

由 ﹥＞﹥吖頭↗ 提交于 2019-12-02 18:24:31
问题 I've uploaded my Android app to the Market today, and I received 4 errors regarding NumberFormatException,Double.parseDouble and Double.valueOf . Here's the Logcat I see in the Developer Console: java.lang.RuntimeException: Unable to start activity ComponentInfo{can.you.drive/can.you.drive.do_drive}: java.lang.NumberFormatException at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1816) at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1837) at

Convert hex color value ( #ffffff ) to integer value

由 十年热恋 提交于 2019-12-02 16:27:56
I am receiving hex color values from a server (in this form, #xxxxxx , example #000000 for black) How do I convert this to an integer value? I tried doing Integer.valueOf("0x" + passedColor.substring(1, passedColor.length())) to get an even more hextastic 0x000000 result, but this isn't intepreted as an int here, any other suggestions? I receive an error: 08-03 21:06:24.673: ERROR/AndroidRuntime(20231): java.lang.NumberFormatException: unable to parse '0x00C8FBFE' as integer I am using the Android SDK for their setBackgroundColor(int color) function, which takes - as you might have guessed -

android number format exception

由 情到浓时终转凉″ 提交于 2019-12-02 16:02:14
问题 I get the following exception java.lang.NumberFormatException: Invalid int: "" It is happening when you try to store a value into shared preferences whilst nothing has been inserted into the input field. This is because i am parsing the input as an int (as i need to do a subtraction with the figure) This isn't much of a problem as the app will work however just incase someone using the app wants to be wierd and try and press the save button without entering any data I dont want it to insert.
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