numberformatexception

问题 Code : I have TriangleSummer class which has class variable static BufferedReader reader = new BufferedReader(new InputStreamReader(System.in)); My main function is public static void main(String args[]) throws IOException { int noOfTestCases = Integer.parseInt(reader.readLine()); for(int i=0;i<noOfTestCases;i++){ int noOfEntries = Integer.parseInt(reader.readLine()); System.out.println(computeMaxSum(noOfEntries)); } } Relevant part of my computeMaxSum() method is public static int

问题 This question already has answers here : What is a NumberFormatException and how can I fix it? (9 answers) Closed 1 year ago . I am trying to create a udf to take two strings as parameters; one in DD-MM-YYYY format (e.g. "14-10-2019") and the other in float format (e.g. "0.000"). I want to convert the float-like string to an int and add it to the date object to get another date which I want to return as a string. def getEndDate = udf{ (startDate: String, no_of_days : String) => val num_days =

问题 This question already has answers here : What is a NumberFormatException and how can I fix it? (9 answers) Closed 1 year ago . I am trying to create a udf to take two strings as parameters; one in DD-MM-YYYY format (e.g. "14-10-2019") and the other in float format (e.g. "0.000"). I want to convert the float-like string to an int and add it to the date object to get another date which I want to return as a string. def getEndDate = udf{ (startDate: String, no_of_days : String) => val num_days =

问题 When I run this program i get the error Exception in thread "main" java.lang.NumberFormatException: empty String. Is it possible to make this work by throwing the exception some how or must I use a try catch statement? private double[] scores3 = new double[5]; Scanner keyboard = new Scanner(System.in); public void enterData() { double score; double numberMin = 0; double numberMax = 100; do{ System.out.println("Enter the student's third test score"); while (!keyboard.hasNextDouble()) {

问题 I am learning bit manipulation in java. So,I am converting binary string to integers bytes and short. Here is my program :- byte sByte,lByte; // 8 bit short sShort,lShort; // 16 bit int sInt,lInt; // 32 bit sByte= (byte)(int)Integer.valueOf("10000000", 2); //Smallest Byte lByte= (byte) ~sByte; sShort= (short)(int)Integer.valueOf("1000000000000000", 2); //Smallest Short lShort = (short) ~sShort; sInt = (int) (int)Integer.valueOf("10000000000000000000000000000000", 2); //Smallest Int lInt= (int

问题 I get the following error from the gps: Fatal Exception: java.lang.NumberFormatException Invalid double: "-٣٣٫٩٣٨٧٤" Now this is from a error that I got from a user via Fabric. It looks like arabic so I'm guessing it only happens if you have the language set to that, or your sim card? Is it possible to force the gps to send characters in the 0-9 range? Or can I somehow fix this? 回答1: Try this: String number = arabicToDecimal("۴۲"); // number = 42; private static final String arabic = "\u06f0

问题 I get the following error from the gps: Fatal Exception: java.lang.NumberFormatException Invalid double: "-٣٣٫٩٣٨٧٤" Now this is from a error that I got from a user via Fabric. It looks like arabic so I'm guessing it only happens if you have the language set to that, or your sim card? Is it possible to force the gps to send characters in the 0-9 range? Or can I somehow fix this? 回答1: Try this: String number = arabicToDecimal("۴۲"); // number = 42; private static final String arabic = "\u06f0

来源： https://stackoverflow.com/questions/63864600/trying-to-convert-string-into-a-double-but-getting-numberformatexception

问题 This code must validate input data from the findActions() method: try { System.out.println(findActions(lookingArea.substring(0, right)));// always printing valid number string Integer.parseInt(findActions(lookingArea.substring(0, right)));// checking for number format } catch(NumberFormatException exc) { System.out.println(exc); } But I always have java.lang.NumberFormatException: For input string: "*number*" that is so strange, because checking with System.out.println(findActions(lookingArea

问题 This code must validate input data from the findActions() method: try { System.out.println(findActions(lookingArea.substring(0, right)));// always printing valid number string Integer.parseInt(findActions(lookingArea.substring(0, right)));// checking for number format } catch(NumberFormatException exc) { System.out.println(exc); } But I always have java.lang.NumberFormatException: For input string: "*number*" that is so strange, because checking with System.out.println(findActions(lookingArea