number-formatting

If I have the following decimal point numbers: Double[] numbers = new Double[] {1.1233, 12.4231414, 0.123, 123.3444, 1.1}; for (Double number : numbers) { System.out.println(String.format("%4.3f", number)); } Then I get the following output: 1.123 12.423 0.123 123.344 1.100 What I want is: 1.123 12.423 0.123 123.344 1.100 The part that can be a bit confusing is that String.format("4.3", number) the 4 represents the length of the entire number(including the decimal), not just the part preceding the decimal. The 3 represents the number of decimals. So to get the format correct with up to 4

This program is basically working with text files, reading the data & performing functions: while(s.hasNext()){ name= s.next(); mark= s.nextDouble(); double percent= (mark / tm )*100 ; System.out.println("Student Name : " +name ); System.out.println("Percentage In Exam: " +percent+"%"); System.out.println(" "); } I would like to format the percent value to 2 decimal places but since it's inside a while loop I cannot use the printf. Elliot's answer is of course correct, but for completeness' sake it's worth noting that if you don't want to print the value immediately, but instead hold the

I'm validating user input from a form. I parse the input with NumberFormat , but it is evil and allow almost anything. Is there any way to parse number more strict? E.g. I would like to not allow these three inputs, for an integer, but Numberformat allow all of them: NumberFormat nf = NumberFormat.getNumberInstance(); nf.setParseIntegerOnly(true); Number numberA = nf.parse("99.731"); // 99 (not what the user expect) Number numberB = nf.parse("99s.231"); // 99 (invalid) Number numberC = nf.parse("9g9"); // 9 (invalid) System.out.println(numberA.toString()); System.out.println(numberB.toString()

I am go to generate an excel file from SSRS, and I want to format the number like this... 15 is displayed as 15 14.3453453 is displayed as 14.35 12.1 is displayed as 12.1 0 is displayed as 0 1 is displayed as 1 I can apply this in Excel but unable to apply in SSRS [=0]0;[=1]1;0.## Does anyone can suggest another way for me? Thanks! Manish Mishra am assuming that you want to know how to format numbers in SSRS Just right click the TextBox on which you want to apply formatting, go to its expression . suppose its expression is something like below =Fields!myField.Value then do this =Format(Fields

In a previous question , I asked whether whether a convenient wrapper exists inside base R to format numbers as percentages. This elicited three responses: Probably not. Such a wrapper would be too narrow to be useful. It is better that useRs learn how to use existing tools, such as sprintf , which can format numbers in a highly flexible way. Such a wrapper is problematic, anyway, since you lose the ability to perform calculations on the object. Still, in my view the sprintf function is just a little bit too obfuscated for the R beginner to learn (except if they come from a C background).

i'm trying to convert numbers into localized strings. For integers and money values it's pretty simple, since the string is just a series of digits and digit grouping separators. E.g.: 12 345 678 901 (Bulgarian) 12.345.678.901 (Catalan) 12,345,678,901 (English) 12,34,56,78,901 (Hindi) 12.345.678.901 (Frisian) 12?345?678?901 (Pashto) 12'345'678'901 (German) i use the Windows GetNumberFormat function to format integers (and GetCurrencyFormat to format money values). But some numbers cannot be reasonably represented in fixed notation, and require scientific notation : 6.0221417930×10 23 or more

I have an array with numbers (coordinates) and I want to display those using JSON like so JSON.stringify(array); My array looks like: [{"x":-0.825,"y":0}, {"x":-1.5812500000000003,"y":-0.5625}, {"x":-2.2515625000000004,"y":-1.546875}] But I'm only interested in the first (lets say) 4 significant digits, i.e. [{"x":-0.825,"y":0}, {"x":-1.5813,"y":-0.5625}, {"x":-2.2516,"y":-1.5469}] Is there a way to easily ditch the remaining insignificant numbers? Native JSON.stringify accepts the parameter replacer , which can be a function converting values to whatever is needed: a = [0.123456789123456789]