number-formatting

When I set custom number format #0.#### , it works fine with whole numbers 123 & 123.23 , but it is not working with decimal numbers like 123.00 , as it is displaying this as 123. How can one set a correct number format so as not to display the . at the end? You can use conditional formatting to do this, in Excel 2007 and later, I believe. Format the cells with your custom format of #0.#### as you've already done. Then add custom formatting to use the General Format if the cell value has no decimal portion. In the Condtional Formatting dialog add a formula-based format. In the "Format values

A store number could be 1-4 digits. Store #26 would be 0026 in respect to how devices are named, but I'd like to give the techs the ease of being able to type 26 to get the same result. How can I take this variable and format it to always be 4 digits by appending the leading zeroes? ## Ask user for store number and affected AP number to query $Global:Store = Read-Host "Store Number "; $Global:apNumber= Read-Host "AP Number "; ## Clean up input for validity IF($store.length -le 4) { $store = } You would use -format operator: '{0:d4}' -f $variable https://ss64.com/ps/syntax-f-operator.html the

I'm working with a library that unfortunately uses boost::lexical_cast to convert from a double to a string . I need to be able to definitively mirror that behavior on my side, but I was hopping to do so without propagating boost . Could I be guaranteed identical behavior using to_string , sprintf , or some other function contained within the standard? The boost code ends up here: bool shl_real_type(double val, char* begin) { using namespace std; finish = start + #if defined(_MSC_VER) && (_MSC_VER >= 1400) && !defined(__SGI_STL_PORT) && !defined(_STLPORT_VERSION) sprintf_s(begin,

In Java, I am trying to parse a string of format "###.##" to a float. The string should always have 2 decimal places. Even if the String has value 123.00 , the float should also be 123.00 , not 123.0 . This is what I have so far: System.out.println("string liters of petrol putting in preferences is " + stringLitersOfPetrol); Float litersOfPetrol = Float.parseFloat(stringLitersOfPetrol); DecimalFormat df = new DecimalFormat("0.00"); df.setMaximumFractionDigits(2); litersOfPetrol = Float.parseFloat(df.format(litersOfPetrol)); System.out.println("liters of petrol before putting in editor: " +

I receive bytes from an RFID reader when presenting a card, but I'm unable to figure out how to derive the card ID from these bytes. For example, I have a card that has these numbers printed on it: 0007625328 116,23152 . I would expect that this is the ID of that card, right? For this card, I get the following bytes from the reader (in hexadecimal representation): <42><09><01><74><00><74><5A><70> . The decimal number 0007625328 translates to 0x00745A70 in hexadecimal representation. The number 116,23152 is actually a different representation of that same value (0007625328): 116 in decimal is

I've been searching for s9(5)v99 but got different information and not really clear. Could someone shows how or the formula to convert. thanks What you have shown us here is the PICTURE clause portion of a COBOL data declaration. COBOL data declarations are a bit odd and take some getting used to. Here is a link to an introductory tutorial on COBOL data declarations . This should get you started. The PICture clause you have given in your question is defining a numeric item with the following characteristics: S - Leading sign 9(5) - 5 decimal digits V - Implied decimal point 99 - 2 digits after

Typically, Rounding to 2 decimal places is very easy with printf("%.2lf",<variable>); However, the rounding system will usually rounds to the nearest even . For example, 2.554 -> 2.55 2.555 -> 2.56 2.565 -> 2.56 2.566 -> 2.57 And what I want to achieve is that 2.555 -> 2.56 2.565 -> 2.57 In fact, rounding half-up is doable in C, but for Integer only; int a = (int)(b+0.5) So, I'm asking for how to do the same thing as above with 2 decimal places on positive values instead of Integer to achieve what I said earlier for printing . It is not clear whether you actually want to " round half-up ", or

Possible Duplicate: JavaScript: formatting number with exactly two decimals Getting a bit muddled up using variables and now cant seem to get calculation to work at all!? $("#discount").change(function(){ var list = $("#list").val(); var discount = $("#discount").val(); var price = $("#price"); var temp = discount * list; var temp1 = list - temp; var total = parseFloat($(this).temp1()).toFixed(2); price.val(total); }); $(this).temp1() looks particularly out of place, I think you just meant to use the temp1 variable. Since it's already a number, you don't need to use parseFloat on it either: $(