nsstring

I knew a instance method of NSString. - (NSRange)rangeOfString:(NSString *)aString My source string looks like this: "abcdEFGhi" When I use [srcStr.rangeOfString:@"efg"]; , there is no substring was found. How can I solve this problem? There is one more version of rangeOfString method you could use that. - (NSRange)rangeOfString:(NSString *)aString options:(NSStringCompareOptions)mask So use as below [srcStr rangeOfString:@"efg" options:NSCaseInsensitiveSearch]; I think you're looking for: [srcStr rangeOfString:@"efg" options:NSCaseInsensitiveSearch]; 来源： https://stackoverflow.com/questions

How can I calculate the number of differences between two NSStrings. Example: NSString 1 = "this is a string" NSString 2 = "Tihs isa string" should return: 4 (one for the capital "T", one for the "i", the "h" and for the missing space) Bart Kiers What you're looking for is the Levenshtein Distance . An implementation in Objective-C: ------------------------------------------------------------------------ // // NSString-Levenshtein.h // // Created by Rick Bourner on Sat Aug 09 2003. // rick@bourner.com @interface NSString(Levenshtein) // calculate the smallest distance between all words in

This question already has an answer here: How to detect if NSString is null? 5 answers I want to check weather a NSString is null or not. Im assigning from an JSON array. After assigning that string value is <null> . Now I want to check this string is null or not. So I put like this if (myStringAuthID==nil) but this if statement always false. How I can check a string for null. Please help me Thanks Mirko Catalano Like that: [myString isEqual: [NSNull null]]; There are three possible interpretations of "null" NSString: someStringPtr == nil (id)someStringPtr == [NSNull null] someStringPtr.length

原子性：并发编程中确保其操作具备整体性，系统其它部分无法观察到中间步骤，只能看到操作前后的结果。 决定编译器生成的getter和setter是否原子 （natomic） 操作。 i 因此， atomic 效率较低，因为要保证操作完整，线程相对安全； nonatomic 不加同步，多线程并发访问效率高，但线程不安全。 由于锁定机制开销较大，一般 iOS 开发中会使用 nonatomic。 atomic 也不是绝对的线程安全。当多个线程同时调用 setter 和 getter 时，就会导致获取的值不一样。 兼顾线程安全和效率的方案 要想线程绝对安全，就要使用 @synchronized 同步锁。 // 同步锁 -(NSString *)name{ @synchronized(self) { return _name; } } -(void)setName:(NSString *)name{ @synchronized(self) { _name = name; } } 但是由于同步锁有等待操作，会降低代码效率。 为了兼顾线程安全和提升效率，可采用 GCD 并发队列进行优化。getter 使用同步派发，setter 使用异步栅栏。 // 并发队列 _queue = dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT,0);

I am reading a plist key (NSArray with n NSDictionaries): let regionsToMonitor = NSBundle.mainBundle().infoDictionary["Regions"] as Array<Dictionary<String,AnyObject>> now I iterate over it: for regionToMonitor in regionsToMonitor { and now I want to to get uuidString of the regionToMonitor in ObjC: NSString *uuidString = regionToMonitor[@"uuidString"]; in swift I try: let uuidString = regionToMonitor["uuid"]!.stringValue; the above does compile but the string is always nil in swift. regionToMonitor["uuid"] when used without !.stringValue works fine in println how do I get a valid Swift.String

I have a long NSString in which I m trying to replace special characters. Part of my string looks like this: "veau (c\u00f4telette)","veau (filet)","agneau (gigot)","agneau (c\u00f4telette)","b**\u0153**uf (hach\u00e9)","porc (hach\u00e9)" I would like to replace all the \u0153 with "oe". I've tried: [response stringByReplacingOccurrencesOfString:@"\u0153" withString:@"oe"]; but it doesn't work.... I don't understand why! The backslash is an escape character , so if you want to specify the actual backslash character in a string literal, you need to use two backslashes. NSString *new = [old