notsupportedexception

TypeError: decoding str is not supported

南楼画角 提交于 2019-12-22 04:06:28
问题 Im trying to make a attribute characteristic randomiser for my nephews board game and I'm trying to write the attributes to an external file so that he can use them later. when i am trying to write to the file it comes up with the error speedE = str('Speed -', str(speed)) TypeError: decoding str is not supported my code is adding the calculated attribute to the name of the attribute. I.E. ('Strength - ', strengthE) my code is ... import random char1 = open('Character1.txt', 'w') strength = 10

NHibernate Overcoming NotSupportedException

谁都会走 提交于 2019-12-21 12:34:16
问题 Does anyone know of any way to overcome NotSupportedException? I have a method against a User: public virtual bool IsAbove(User otherUser) { return HeirarchyString.StartsWith(otherUser.HeirarchyString); } And I want to do: _session.Query<User>.Where(x => loggedInUser.IsAbove(x)); But this throws a NotSupportedException. The real pain though is that using _session.Query<User>.Where(x => loggedInUser.HeirarchyString.StartsWith(x.HeirarchyString)); works absolutely fine. I don't like this as a

C#, Is there a better way to verify URL formatting than IsWellFormedUriString?

女生的网名这么多〃 提交于 2019-12-20 21:49:15
问题 Is there a better/more accurate/stricter method/way to find out if a URL is properly formatted? Using: bool IsGoodUrl = Uri.IsWellFormedUriString(url, UriKind.Absolute); Doesn't catch everything. If I type htttp://www.google.com and run that filter, it passes. Then I get a NotSupportedException later when calling WebRequest.Create . This bad url will also make it past the following code (which is the only other filter I could find): Uri nUrl = null; if (Uri.TryCreate(url, UriKind.Absolute,

NotSupportedException thrown in EndGetResponse(request.BeginGetResponse(null, null)))

喜夏-厌秋 提交于 2019-12-11 21:15:00
问题 I have the following code to make an asynchronous call synchronous. Please don't get into that this is bad, I know, and it needs to be done this way for only one particular request. The code throws an exception in Windows Phone 8 when the using (var response = request.EndGetResponse(request.BeginGetResponse(null, null))) is executing. The request is actually invoked in the UnhandledException event handler. Exception: NotSupportedException Message: Method is not supported Stacktrace: at System

NotSupportedException on IQuery's Enumerable when using statelesssession

梦想的初衷 提交于 2019-12-11 08:36:42
问题 when trying to use the Enumerable method on a named query, with a Stateless session, as shown in the example at: http://www.nhforge.org/doc/nh/en/#batch-statelesssession i am seeing a NotSupportedException. the stack trace is as below: System.NotSupportedException: Specified method is not supported. at NHibernate.Impl.StatelessSessionImpl.Enumerable(String query, QueryParameters parameters) at NHibernate.Impl.QueryImpl.Enumerable() here is a snippet of my code: IStatelessSession

An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext

烂漫一生 提交于 2019-12-05 09:53:21
I've got a problem with NotSupportedException, I'm getting: "An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext." partial class SupplyOfert : Model { public SupplyOfert(int id = 0) { if (id > 0) this.get(id); } public Supplier supplier { get { return this.Supplier; } set { this.Supplier = db.Suppliers.SingleOrDefault(s => s.id == value.id); } } public override bool get(int id) { SupplyOfert so = (SupplyOfert)db.SupplyOferts.SingleOrDefault(s => s.id == id).Copy(this, "Supplies"); this._Supplies = so._Supplies; so._Supplies

Automapper 3.0 - This type is not supported on this platform IMapperRegistry

荒凉一梦 提交于 2019-12-05 08:30:18
问题 I updated my project to use Automapper 3.0.0 and now my TFS build is not succeeding. The error is the following: " ...System.PlatformNotSupportedException: System.PlatformNotSupportedException: This type is not supported on this platform IMapperRegistry. " Is there anyone that can help me resolve this issue. In the mean time, I am going to revert to previous version since that one seems to work fine. 回答1: We had the same issue on our build server. MsTest seemed to remove DLLs it deemed

TypeError: decoding str is not supported

假装没事ソ 提交于 2019-12-05 04:10:24
Im trying to make a attribute characteristic randomiser for my nephews board game and I'm trying to write the attributes to an external file so that he can use them later. when i am trying to write to the file it comes up with the error speedE = str('Speed -', str(speed)) TypeError: decoding str is not supported my code is adding the calculated attribute to the name of the attribute. I.E. ('Strength - ', strengthE) my code is ... import random char1 = open('Character1.txt', 'w') strength = 10 strength += int(random.randint(1, 12) / random.randint(1,4)) speed = 10 speed += int(random.randint(1,

LINQ Lambda, Group by with list

人盡茶涼 提交于 2019-12-05 03:31:44
I'm having some trouble with finding the right syntax to accomplish the following: Is it possible with LINQ (Lambda Expression) to .GroupBy data and instead of using the usual .Sum() or .Count() I want the resulting data to be a List of Int. I defined my own class named: Filter_IDs. Its constructor needs two parameters: public int? type; // Represents the object_type column from my database public List<int?> objects; // Represents the object_id column from my database I want to load data from my database into this object. The following LINQ query should result in a List of Filter_IDs: The

try-with-resources are not supported at this language level - Android

感情迁移 提交于 2019-12-04 15:36:02
问题 I have a problem with "try-with-resources are not supported at this language level" in android in the following posted code, I tried to set language to 7 but it stills keeps giving me the same example plus it keeps giving me the option to change to language 7. public String ReadFile(String fileName) { try (BufferedReader br = new BufferedReader(new FileReader(fileName+".txt"))) { StringBuilder sb = new StringBuilder(); String line = br.readLine(); while (line != null) { sb.append(line); sb