nodemon

问题 I want my typescript files to be compiled on every file saving with the command tsc . How do I combine the tsc command with the command that nodemon runs in the build:live script "scripts": { "start": "npm run build:live", "build:live": "nodemon --watch '*.ts' --exec 'ts-node' app.ts", } this script causes nodemon to call itself twice or three times: "build:live": "nodemon --watch '*.ts' --exec 'ts-node app.ts & tsc'", 回答1: This looks like it will achieve what you're looking for: "start":

问题 I am trying to setup a simple express server. I am using nodemon to start my development server But my app keeps crashing because it does not recognize the "babel-node" command. The error output is [nodemon] 2.0.7 [nodemon] to restart at any time, enter `rs` [nodemon] watching path(s): *.* [nodemon] watching extensions: js,json [nodemon] starting `babel-node index.js` 'babel-node' is not recognized as an internal or external command, operable program or batch file. [nodemon] app crashed -

问题 file is not uploading in nodejs it shows error which is: nodemon app crashed - waiting for file changes before starting... nodejs code: var path = require('path'); var express = require('express'); var multer = require('multer'); var app = express(); var Storage = multer.diskStorage({ destination: './public/uploads/', filename: (req, file, cb) => { cb(null, file.fieldname+"-"+Date.now()+path.extname(file.orignalname)); } }) var upload = multer({ storage: Storage }).single('file'); app.use

问题 I am trying to run nodemon index.js in my terminal but I am getting the following error which I have absolutely no idea what it means as for me is very unclear. Can please anyone explain to me how to solve this? index.js const express = require('express'); const morgan = require('morgan'); const bodyParser = require('body-parser'); const mongoose = require('mongoose'); var app = express(); var router = require('./services/router'); mongoose.connect('mongodb://localhost:apiAuth'); app.use

问题 I use nodemon as a dev-dependency in node. Suddenly, in CLI it shows: [nodemon] restarting due to changes... when I am changing the code. Then I have globally installed nodemon but it still isn't working. It is not working on any project-- not a single project. Any help? I have attached a screenshot of my CLI: 回答1: It's probably because starting updates a file that the server is watching, therefore triggering a restart event in an infinite loop. Nodemon supports the --watch and --ignore

问题 I'm developing a discord bot for discord at the moment, and to run the bot, I have a few different files. I've run into some problems along the way that all ended up having the same fix, or at least the only fix that I could come up with. That fix would be, instead of running them in my main file (index.js), I could just run 3 separate batch files using nodemon (https://www.npmjs.com/package/nodemon). I currently have 3 batch files to do so. Those batch files look like this: nodemon index.js

问题 nodemon always worked for me. I always did nodemon server and it would run the server file and watch for updates and node would restart. But now when I do it, I get this in the cmd (I use windows): Usage: nodemon [nodemon options] [script.js] [args] See "nodemon --help" for more. I tried uninstalling and reinstalling nodemon globally but still get the feedback. now I have to restart the server with regular node on every update. EDIT:: This is what it looke like when i type in dir and press

问题 I am trying to improve the DEV experience in my Node. To do that, I want to: a) restart my server when server-side code is changed b) refresh the browser when client-side code is changes. In an effort to accomplish this, I began integrating nodemon and browserSync into my gulp script. In my gulp script, I have the following task: gulp.task('startDevEnv', function(done) { // Begin watching for server-side file changes nodemon( { script: input.server, ignore:[input.views] }) .on('start',

问题 I am trying to improve the DEV experience in my Node. To do that, I want to: a) restart my server when server-side code is changed b) refresh the browser when client-side code is changes. In an effort to accomplish this, I began integrating nodemon and browserSync into my gulp script. In my gulp script, I have the following task: gulp.task('startDevEnv', function(done) { // Begin watching for server-side file changes nodemon( { script: input.server, ignore:[input.views] }) .on('start',

问题 I am trying to improve the DEV experience in my Node. To do that, I want to: a) restart my server when server-side code is changed b) refresh the browser when client-side code is changes. In an effort to accomplish this, I began integrating nodemon and browserSync into my gulp script. In my gulp script, I have the following task: gulp.task('startDevEnv', function(done) { // Begin watching for server-side file changes nodemon( { script: input.server, ignore:[input.views] }) .on('start',