nested

Python unit test for nested if statement

折月煮酒 提交于 2019-12-11 11:37:48
问题 So I've been posting unit test questions because I'm trying to get good at them. I'll try to be as clear as possible. Below I have a nested if statement, I want to mock the input for the difficulty variable and check for the stdout if the condition is met. here is my run code.. def main(): print("''''''''''''''''''''''''''''''''''''") print("''''''''''''''''''''''''''''''''''''") print("''' \t\t\t\t '''") print("''' \t\t\t\t '''") print("''' \t Pirate Games\t\t '''") print("''' \tStart a new

Spring Programmatic transaction within transaction

人盡茶涼 提交于 2019-12-11 11:37:44
问题 I have written below code doing below activities I created one transaction using Spring classes. Inserted one row. Created other transaction. Inserted another row. committed outer transaction. Rolledback inner transaction. TransactionStatus trxstsOuter= dsTrxMngr.getTransaction(null); jdbcTemplate.update("insert into kau_emp values(6,'xyz' )"); TransactionStatus trxstsInner= dsTrxMngr.getTransaction(null); jdbcTemplate.update("insert into kau_emp values(7,'pqr' )"); dsTrxMngr.commit

Python iterating through nested dictionaries

拈花ヽ惹草 提交于 2019-12-11 11:16:04
问题 First of all, here is the question and the code written: def family_lineage(familytree, lineage): '''(dict, list of strs) -> boolean Return True if lineage specifies a list of names who are directly related in a chain of parent-child relationships, and NOT child-parent, parent-grandchild..etc, beginning from the first generation listed. >>> trace_lineage({'Gina': {'Sam': {'Tina': {}}, 'Li': {}}, 'Guy': {}}, ['Gina']) True >>> trace_lineage({'Gina': {'Sam': {'Tina': {}}, 'Li': {}}, 'Guy': {}},

Django Rest Framework nested object response

亡梦爱人 提交于 2019-12-11 10:58:42
问题 I am new to Django Rest Framework, I am trying to implement Comment System API, I have model like this class Comment(models.Model): parent_id = models.IntegerField() user = models.ForeignKey(User) content = models.CharField(max_length=1000,blank=True) likes = models.IntegerField(default=0) active = models.BooleanField(default=True) created = models.DateTimeField(auto_now=False,auto_now_add=True) updated = models.DateTimeField(auto_now=True,auto_now_add=False) where parent_id is used for

F# nested List.iter calls

做~自己de王妃 提交于 2019-12-11 10:06:48
问题 I have an F# function and I want to try varying some of the parameters and testing all such combinations. Is this the right approach? (The parentheses get a bit dense...): let MyFunc a b c x y z = ... q let UploadResult a b c x y z q = ... () let a = 5.0 let b = 0 let c = System.DateTime.Today let xList = [-1.0; 0.0; 1.0] let yList = [2; 4; 6; 8; 10] let zList = [0.1; 0.001] xList |> List.iter (fun x -> (yList |> List.iter (fun y -> (zList |> List.iter (fun z -> MyFunc a b c x y z |>

How to parse json file in angular2 using multiple ngFor?

旧巷老猫 提交于 2019-12-11 10:05:20
问题 I am trying to parse following json file.Json File is getting read successfully. but I want to render all the data inside this json file.thus I was using nested ngFor to do this.but I am facing this error: EXCEPTION: Cannot find a differ supporting object '[object Object]' in [comp in ParserComponent@2:13] I have included ngFor directive in too. I want to access all the data recursively. is there any way to do this? Thanks in advance 1. Json File [{ "_id": "5694f0aab4d9a8e41f399491", "name":

Excel formula has too many arguments

无人久伴 提交于 2019-12-11 10:04:59
问题 I created the below formula to run of a series of customer numbers saved in text format. =IFERROR(IF(AND((LEFT($J3,3)="028"),$N3=11),"NI Landline",IF(AND((LEFT($J3,2)="07"),$N3=11),"Mobile","Other Number")),"Other Number") Breakdown: =IFERROR( IF(AND((LEFT($J3,3)="028"),$N3=11), "NI Landline", IF(AND((LEFT($J3,2)="07"),$N3=11), "Mobile", "Other Number")), "Other Number") This formula works fine but I needed to amend it slightly to differentiate the numbers a bit further, so I amended it to

Find a key in a python dictionary and return its parents

佐手、 提交于 2019-12-11 09:38:29
问题 I have a nested dictionary that has a list of folders, like this one where 2013_09_10 is the root folder: {'2013_09_10': {'master.tex': None, 'master.log': None, 'master.pdf': None, 'Makefile': None, 'pieces': {'rastin.tex': None, '02 Human Information Processing.txt': None, 'p1.tex': None, 'p3.tex': None, '03 Models and Metaphors.txt': None, 'p2.tex': None}, 'master.aux': None, 'front_matter.tex': None}} What I' trying to accomplish is, given the name of a file (for example p1.tex), print

Nested IFs to pad numbers with zeroes [duplicate]

不羁岁月 提交于 2019-12-11 09:37:28
问题 This question already has answers here : Add leading zeroes/0's to existing Excel values to certain length (7 answers) Closed 4 years ago . I am looking to pad a columns with zero's so that I can later concatenate it's value. It needs to 4 characters, so I am trying to use a Nested If Statement. =IF(LEN(G2)=3,"0" & G2),IF(LEN(G2)=2,"00" & G2,G2) I only get '#Value'. Where am I going wrong? 回答1: Don't reinvent the wheel: there is already a built-in function do to this. =TEXT(G2,"0000") Now, to

Error: evaluation nested too deeply: infinite recursion / options(expressions=)? in R3.3.2

一曲冷凌霜 提交于 2019-12-11 09:27:29
问题 I'm trying to use a function in order to read in different models. Using the code below without a function works. When I use the function and call it, I will get the error Error: evaluation nested too deeply: infinite recursion / options(expressions=)? Can anyone tell me why? x=rnorm(1000)+sin(c(1:1000)/100)#random data+ sinus superimposed plot <- function(model){ par(mfrow=c(2,2))# plot window settings plot(model) lines(filter(model,rep(1/30,30)),col='red') plot(filter(model,rep(1/30,30)))