nested

Python - Nested List to Tab Delimited File?

柔情痞子 提交于 2019-12-21 04:26:06
问题 I have a nested list comprising ~30,000 sub-lists, each with three entries, e.g., nested_list = [['x', 'y', 'z'], ['a', 'b', 'c']]. I wish to create a function in order to output this data construct into a tab delimited format, e.g., x y z a b c Any help greatly appreciated! Thanks in advance, Seafoid. 回答1: with open('fname', 'w') as file: file.writelines('\t'.join(i) + '\n' for i in nested_list) 回答2: >>> nested_list = [['x', 'y', 'z'], ['a', 'b', 'c']] >>> for line in nested_list: ... print

Python - Nested List to Tab Delimited File?

假如想象 提交于 2019-12-21 04:26:01
问题 I have a nested list comprising ~30,000 sub-lists, each with three entries, e.g., nested_list = [['x', 'y', 'z'], ['a', 'b', 'c']]. I wish to create a function in order to output this data construct into a tab delimited format, e.g., x y z a b c Any help greatly appreciated! Thanks in advance, Seafoid. 回答1: with open('fname', 'w') as file: file.writelines('\t'.join(i) + '\n' for i in nested_list) 回答2: >>> nested_list = [['x', 'y', 'z'], ['a', 'b', 'c']] >>> for line in nested_list: ... print

“Embedded” data.frame in R. What is it, what is it called, why does it behave the way it does?

北城以北 提交于 2019-12-21 03:43:20
问题 I have the following data structure in R: df <- structure( list( ID = c(1L, 2L, 3L, 4L, 5L), var1 = c('a', 'b', 'c', 'd', 'e'), var2 = structure( list( var2a = c('v', 'w', 'x', 'y', 'z'), var2b = c('vv', 'ww', 'xx', 'yy', 'zz')), .Names = c('var2a', 'var2b'), row.names = c(NA, 5L), class = 'data.frame'), var3 = c('aa', 'bb', 'cc', 'dd', 'ee')), .Names = c('ID', 'var1', 'var2', 'var3'), row.names = c(NA, 5L), class = 'data.frame') # Looks like this: # ID var1 var2.var2a var2.var2b var3 # 1 1 a

How to get nested dictionary key value with .get()

雨燕双飞 提交于 2019-12-21 03:42:14
问题 With a simple dictionary like: myDict{'key1':1, 'key2':2} I can safely use: print myDict.get('key3') and even while 'key3' is not existent no errors will be thrown since .get() still returns None. Now how would I achieve the same simplicity with a nested keys dictionary: myDict={} myDict['key1'] = {'attr1':1,'attr2':2} The following will give a KeyError: print myDict.get('key1')['attr3'] This will go through: print myDict.get('key1').get('attr3') but it will fail with adn AttributeError:

Backbone parsing json response

自作多情 提交于 2019-12-21 02:33:49
问题 I've been using Backbone for a total of 3 days now, and I can see that this has been asked about quite a lot, but honestly I'm just not getting it. I've been banging my head against the wall trying to get a basic app running parsing nested json and I just can't seem to work it out. It all works if I flatten out the json response, and remove the nested elements, but that's not how I will receive it. I've tried some examples with Backbone relational, but I'm really stuck here, a total backbone

Nested collection fields in Sonata Admin (2.3)

ε祈祈猫儿з 提交于 2019-12-20 16:46:49
问题 I'm having problems creating my form for creating a course. This is a part of my database scheme for which I'm trying to create a form: So which I'm trying to do is create a course where I can create sessions and dates (moment) attached to that session. It should look something like this: In my CourseAdmin class I have: protected function configureFormFields(FormMapper $formMapper) { $formMapper ->add('name', 'text', array('label' => 'Naam')) ->add('description', 'textarea', array('label' =>

Update nested map dynamodb

﹥>﹥吖頭↗ 提交于 2019-12-20 13:32:30
问题 I have a dynamodb table with an attribute containing a nested map and I would like to update a specific inventory item that is filtered via a filter expression that results in a single item from this map. How to write an update expression to update the location to "in place three" of the item with name=opel,tags include "x1" (and possibly also f3)? This should just update the first list elements location attribute. ( "inventory": [ { "location": "in place one", # I want to update this "name":

Nested django templates

谁说我不能喝 提交于 2019-12-20 12:42:21
问题 This seems like a pretty basic thing to do but although I've been using Django for around a year, I've never run into this scenario yet. In a lot of templating/web frameworks, template inheritance works a bit differently, in that usually it behaves more like wrappers, so if you have childtemplate.html, parenttemplate.html, and grandparenttemplate.html, then the finally rendering usually looks something like: grandparent header parent header child header child content parent content parent

How to operate on nested dictionary in python 3.x?

ぐ巨炮叔叔 提交于 2019-12-20 08:08:31
问题 I am stuck with this question, can you solve the challenge? Here we go! We represent scores of players across a sequence of matches in a two level dictionary as follows: {'match1':{'player1':57, 'player2':38}, 'match2':{'player3':9, 'player1':42}, 'match3':{'player2':41, 'player4':63, 'player3':91}} Each match is identified by a string, as is each player. The scores are all integers. The names associated with the matches are not fixed (here they are 'match1','match2','match3'), nor are the

Sum nested lists based on condition in Python

梦想的初衷 提交于 2019-12-20 07:48:02
问题 I have a nested list looking like this: [['Vienna','2012', 890,503,70],['London','2014', 5400, 879,78], ['London','2014',4800,70,90],['Bern','2013',300,450,678], ['Vienna','2013', 700,850,90], ['Bern','2013',500,700,90]] What I want to do is summing every integervalue in the sublist with another sublist if city and year are equal. I first thought of a dictionary with city and year as key, but it caused problems sorting it. Then I had: {('Vienna','2012'):[890,503,70],('Bern','2013'):[800,1150