nested

Find key in nested associative array

由 馋奶兔 提交于 2019-12-02 07:27:19
问题 The other day I asked a question related to this, and I got an answer, but it did not do what I wanted. Here is the method I have for traversing a multidimensional associative array, checking whether a key is in the array (from the answer to my previous question): private function checkKeyIsInArray($dataItemName, $array) { foreach ($array as $key => $value) { // convert $key to string to prevent key type convertion echo '<pre>The key: '.(string) $key.'</pre>'; if ((string)$key ==

How to get the inner most type of a n-nested vector?

由 戏子无情 提交于 2019-12-02 06:59:06
I need to get the inner type of a n-nested vector. For Example: type a; //base_type of a = type std::vector<type> b; //base_type of b = type std::vector<std::vector<type>> c;//base_type of c = type and so on. I tried using a wrapper, but this results in a compiler error. template<typename T1> struct base_type : T1::value_type { }; template<typename T1> struct base_type<std::vector<T1>> { using type = typename base_type<T1>::value_type; }; Both of your cases are wrong. Your base case should be the non- vector case. For a non- vector , there is no ::value_type . You just want the type: template

How to call a method on an object in a nested form in Ruby on Rails 3?

由 旧巷老猫 提交于 2019-12-02 06:52:26
问题 I have these two models class Invoice < ActiveRecord::Base has_many :items accepts_nested_attributes_for :items ... end class Item < ActiveRecord::Base belongs_to :invoice def total price * quantity end ... end and this nested (!) form that posts to both models: <h1>Add an Invoice</h1> <%= form_for @invoice do |f| %> <p> <%= f.label :recipient %> <%= f.text_field :recipient %> </p> <p> <%= f.label :date %> <%= f.text_area :date %> </p> <h2>Items</h2> <p> <%= f.fields_for(:items) do |f| %> <%=

Limitation of JPA 1.0 using @IdClass with *nested* composite primary keys?

由 无人久伴 提交于 2019-12-02 06:45:48
问题 Given the following example (departments - projects): A department has the following properties (composite primary key): @Entity @IdClass(DeptId.class) public class Department { @Id @Column(name="number") private Integer number; @Id @Column(name="country") private String country; @Column(name="name") private String name; @OneToMany(mappedBy="dept") private Collection<Project> projects; ... } Here the PK class: public class DeptId implements Serializable { private Integer number; private

Loop through multi-dimensional array and remove certain keys

由 为君一笑 提交于 2019-12-02 06:25:02
问题 I've got a nested tree structure which is based on the array below: Array ( [1] => Array ( [id] => 1 [parent] => 0 [name] => Startpage [uri] => 125 [basename] => index.php [child] => ) [23] => Array ( [id] => 23 [parent] => 0 [name] => Events [uri] => 0 [basename] => [child] => Array ( [24] => Array ( [id] => 24 [parent] => 23 [name] => Public news [uri] => 0 [basename] => [child] => Array ( [27] => Array ( [id] => 27 [parent] => 24 [name] => Add [uri] => 100 [basename] => news.public.add.php

Nesting parallelizations in Spark? What's the right approach?

由 北城以北 提交于 2019-12-02 06:23:14
问题 NESTED PARALLELIZATIONS? Let's say I am trying to do the equivalent of "nested for loops" in Spark. Something like in a regular language, let's say I have a routine in the inside loop that estimates Pi the way the Pi Average Spark example does (see Estimating Pi) i = 1000; j = 10^6; counter = 0.0; for ( int i =0; i < iLimit; i++) for ( int j=0; j < jLimit ; j++) counter += PiEstimator(); estimateOfAllAverages = counter / i; Can I nest parallelize calls in Spark? I am trying and have not

Nested User Controls - how to best get a reference to an ancestor control

由 Deadly 提交于 2019-12-02 05:41:55
I realize that a whole lot of code cannot fit here, but I am asking for general direction or pointer. I have .NET user controls nested six deep for an interactive gadget with (outer to inner) of : wrapper, tabs, panels, lists, rows, items. I am trying to get a reference to an ancestor control from a nested control. Specifically, I have this code in the code behind of a embedded "great great grand child" control. It works, but it is very ugly: MyTab _myTab = this.Parent.Parent.Parent.Parent.FindControl(thisTab) as MyTab; which equals {ASP.controls_appname_widget_mywidget_mytab_ascx} and is

adding keys in nested dictionary in python

由 大兔子大兔子 提交于 2019-12-02 05:29:53
问题 elements = {'hydrogen': {'number': 1, 'weight': 1.00794, 'symbol': 'H'}, 'helium': {'number': 2, 'weight': 4.002602, 'symbol': 'He'}} Add an is_noble_gas boolean entry to the hydrogen and helium dictionaries. 回答1: elements = {'hydrogen': {'number': 1, 'weight': 1.00794, 'symbol': 'H'}, 'helium': {'number': 2, 'weight': 4.002602, 'symbol': 'He'}} noble_dict = { "hydrogen": False, "helium": True } for noble in noble_dict: elements[ noble ][ "is_noble_gas" ] = noble_dict[ noble ] {'helium': {

recursive function for extract elements from deep nested lists/tuples

由 独自空忆成欢 提交于 2019-12-02 05:29:40
问题 I want to write a function that extracts elements from deep nested tuples and lists, say I have something like this l = ('THIS', [('THAT', ['a', 'b']), 'c', ('THAT', ['d', 'e', 'f'])]) And I want a flat list without 'THIS' and 'THAT': list = ['a', 'b', 'c', 'd', 'e', 'f'] Here's what I have so far: def extract(List): global terms terms = [] for i in word: if type(i) is not str: extract(i) else: if i is not "THIS" and i is not "THAT": terms.append(i) return terms But I keep getting list = ['d'

How to search nested list grid and give lettered coordinates in Python? [closed]

由 拥有回忆 提交于 2019-12-02 04:57:54
I'm new to python and struggling quite a bit to get this going. This is my task: The Six-Letter Cipher is a method of encoding a secret message that involves both substitution and transposition. The encryption starts by randomly filling a 6  6 grid with the alphabet letters from A to Z and the digits from 0 to 9 (36 symbols in total). This grid must be known to both the sender and receiver of the message. The rows and columns of the grid are labelled with the letters A, B, C, D, E, F. Write a Python program that implements the six-letter cipher method. Your program should: 1. Create a 6x6
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