nested

I have a nested list looking like this: [['Vienna','2012', 890,503,70],['London','2014', 5400, 879,78], ['London','2014',4800,70,90],['Bern','2013',300,450,678], ['Vienna','2013', 700,850,90], ['Bern','2013',500,700,90]] What I want to do is summing every integervalue in the sublist with another sublist if city and year are equal. I first thought of a dictionary with city and year as key, but it caused problems sorting it. Then I had: {('Vienna','2012'):[890,503,70],('Bern','2013'):[800,1150,768],...} I also tried something like this: [sum(x) for x in zip(*list) if x[0] == x[0]] but of course

I need to use a nested for loop in Java to make a triangle like this ******** ******* ****** ***** **** *** ** * Heres my code: for (int i=8; i>0; i--) { for (int j=0; j<i; j++) { System.out.print('#'); } System.out.println(""); } I get a triangle but not the one i want. Instead, my triangle looks like this: ******** ******* ****** ***** **** *** ** * You'll need the outer loop to count the 8 rows. The inner loop would output the *'s for each row. The row count of the outer loop will tell you how many spaces to output versus *'s. Try this public static void main(String[] args) { triangle(8); }

I am stuck with this question, can you solve the challenge? Here we go! We represent scores of players across a sequence of matches in a two level dictionary as follows: {'match1':{'player1':57, 'player2':38}, 'match2':{'player3':9, 'player1':42}, 'match3':{'player2':41, 'player4':63, 'player3':91}} Each match is identified by a string, as is each player. The scores are all integers. The names associated with the matches are not fixed (here they are 'match1','match2','match3'), nor are the names of the players. A player need not have a score recorded in all matches. Define a Python function

I am working on a program that keeps inventory of vehicles, so I created a struct for it. It also needs to keep a list of the drivers, so I created a nested struct for that. Here's the code: struct Vehicle { string License; string Place; int Capacity; struct Driver { string Name; int Code; int Id; } dude; }; I ask for user input and then put the structs in a vector using this function: void AddVehicle(vector<Vehicle> &vtnewV) { Vehicle newV; Vehicle::Driver dude; cout << "Enter license plate number: " << endl; cin >> newV.License; cout << "Enter the vehicle's ubication: " << endl; cin >> newV

I'm learning programming in Python and I'm stuck with a syntax error in the line 8 in the following code x = int(input('Add x:\n')) y = int(input('Add y:\n')) if x == y : print('x and y are equal') else : if x < y : print('x is less than y') else x > y : print('x is greater than y') I just don't see what's wrong there. The full error is: Traceback (most recent call last): File "compare.py", line 8 else x > y : ^ SyntaxError: invalid syntax else takes no condition. It's just else: , nothing more; the block is executed when the if condition (and any elif conditions) didn't match. Use elif if you