nested-routes

问题 I am having a hard time making the slug from Friendly_id in a nested route when editing and creating? the routes look great for show. http://0.0.0.0:3000/test/tester2 This is the URL I am getting when i try to edit tester2 is: http://0.0.0.0:3000/2/tester2/edit What i would like to see is: http://0.0.0.0:3000/test/tester2/edit Here is my code. team.rb class Team < ActiveRecord::Base extend FriendlyId friendly_id :name, use: :slugged has_many :videos ... end video.rb class Video < ActiveRecord

问题 I get this error whenever the app is running, though is not causing me problems in current development (i think) I would like to understand this error and know where it comes, because I'm completely lost, I can't even post relevant code. But i'll try.. So these are the main routes (appModule): const routes: Routes = [ {path:'home', component:HomeComponent, canActivate:[AuthGuardService]}, {path:'detail/:id', component:DetailComponent}, {path: 'register', component: RegisterComponent}, {path:

问题 I get this error whenever the app is running, though is not causing me problems in current development (i think) I would like to understand this error and know where it comes, because I'm completely lost, I can't even post relevant code. But i'll try.. So these are the main routes (appModule): const routes: Routes = [ {path:'home', component:HomeComponent, canActivate:[AuthGuardService]}, {path:'detail/:id', component:DetailComponent}, {path: 'register', component: RegisterComponent}, {path:

来源： https://stackoverflow.com/questions/27712947/nested-resources-in-devise

来源： https://stackoverflow.com/questions/27712947/nested-resources-in-devise

问题 I want my lazy-loaded module in their children components to be parameterizly loaded in one <router-outlet></router-outlet> . My app.routing.module is const routes: Routes = [ { path: 'dashboard', component: DashboardComponent }, { path: 'reports', loadChildren: () => import('./reports/reports.module').then(m => m.ReportsModule) } { path: 'patients', loadChildren: () => import('./patients/patients.module').then(m => m.PatientsModule) }, { path: 'consultant', loadChildren: () => import('.

问题 I want my lazy-loaded module in their children components to be parameterizly loaded in one <router-outlet></router-outlet> . My app.routing.module is const routes: Routes = [ { path: 'dashboard', component: DashboardComponent }, { path: 'reports', loadChildren: () => import('./reports/reports.module').then(m => m.ReportsModule) } { path: 'patients', loadChildren: () => import('./patients/patients.module').then(m => m.PatientsModule) }, { path: 'consultant', loadChildren: () => import('.

问题 I have created an angular application version 7 and project structure is like this. app module have app-routing.module.ts and dashboard module have dashboard-routing module.ts. In dashboard module, the layout component route has child components namely home and admin. Here is my code: AppModule import { AppRoutingModule } from './app-routing.module'; import { DashboardModule } from './dashboard/dashboard.module'; import { AppComponent } from './app.component'; import { LoginComponent } from '

问题 I have created an angular application version 7 and project structure is like this. app module have app-routing.module.ts and dashboard module have dashboard-routing module.ts. In dashboard module, the layout component route has child components namely home and admin. Here is my code: AppModule import { AppRoutingModule } from './app-routing.module'; import { DashboardModule } from './dashboard/dashboard.module'; import { AppComponent } from './app.component'; import { LoginComponent } from '

问题 I have created an angular application version 7 and project structure is like this. app module have app-routing.module.ts and dashboard module have dashboard-routing module.ts. In dashboard module, the layout component route has child components namely home and admin. Here is my code: AppModule import { AppRoutingModule } from './app-routing.module'; import { DashboardModule } from './dashboard/dashboard.module'; import { AppComponent } from './app.component'; import { LoginComponent } from '