mysql

Disable access for database

我只是一个虾纸丫 提交于 2021-02-07 14:51:21
问题 I created a MySQL server. Now the user login has access to all databases. I want this user not to have access (so can't do anything) to 3 databases: information_schema mysql phpmyadmin So the user can use all databases except these 3. How can I get this done? 回答1: A brief version of how to do this (which is mostly explained in the link I posted above): You need to REVOKE that user's GLOBAL privileges - this is because MySQL's privilege system is top-down. If they have a GLOBAL privilege to

Disable access for database

半腔热情 提交于 2021-02-07 14:51:09
问题 I created a MySQL server. Now the user login has access to all databases. I want this user not to have access (so can't do anything) to 3 databases: information_schema mysql phpmyadmin So the user can use all databases except these 3. How can I get this done? 回答1: A brief version of how to do this (which is mostly explained in the link I posted above): You need to REVOKE that user's GLOBAL privileges - this is because MySQL's privilege system is top-down. If they have a GLOBAL privilege to

Disable access for database

守給你的承諾、 提交于 2021-02-07 14:50:31
问题 I created a MySQL server. Now the user login has access to all databases. I want this user not to have access (so can't do anything) to 3 databases: information_schema mysql phpmyadmin So the user can use all databases except these 3. How can I get this done? 回答1: A brief version of how to do this (which is mostly explained in the link I posted above): You need to REVOKE that user's GLOBAL privileges - this is because MySQL's privilege system is top-down. If they have a GLOBAL privilege to

Using 'LIKE' with the result of a SQL subquery

牧云@^-^@ 提交于 2021-02-07 14:37:39
问题 The following query is working absolutely fine for me: SELECT * From Customers WHERE Customers.ContactName = (SELECT FirstName FROM Employees as E, orders as O WHERE <condition> LIMIT 1); However, if i use LIKE instead of = to compare with the result of the subquery, I'm not getting any results. How do I use LIKE '%%' in the above query? 回答1: First, this query should not be working fine: SELECT * From Customers WHERE Customers.ContactName = (SELECT FirstName from Employees as E, orders as O

Using 'LIKE' with the result of a SQL subquery

人走茶凉 提交于 2021-02-07 14:32:01
问题 The following query is working absolutely fine for me: SELECT * From Customers WHERE Customers.ContactName = (SELECT FirstName FROM Employees as E, orders as O WHERE <condition> LIMIT 1); However, if i use LIKE instead of = to compare with the result of the subquery, I'm not getting any results. How do I use LIKE '%%' in the above query? 回答1: First, this query should not be working fine: SELECT * From Customers WHERE Customers.ContactName = (SELECT FirstName from Employees as E, orders as O

PHP & MySql check if table is empty

房东的猫 提交于 2021-02-07 14:31:23
问题 I'm a bit of a noob- and I'm having a hard time... I need a bit of of code that searches a db table to find the row that matches the $id variable. There's a field in that table 'description' that I need to grab. If it's null, I need to show one message, if not another. Here's the code I have (I know I need to add the mysqli escape string, just doing this real quick from memory): $query = "SELECT description FROM posts WHERE id = $id"; $result = mysqli_query($dbc, $query); $row = mysqli_fetch

PHP & MySql check if table is empty

帅比萌擦擦* 提交于 2021-02-07 14:30:35
问题 I'm a bit of a noob- and I'm having a hard time... I need a bit of of code that searches a db table to find the row that matches the $id variable. There's a field in that table 'description' that I need to grab. If it's null, I need to show one message, if not another. Here's the code I have (I know I need to add the mysqli escape string, just doing this real quick from memory): $query = "SELECT description FROM posts WHERE id = $id"; $result = mysqli_query($dbc, $query); $row = mysqli_fetch

PHP & MySql check if table is empty

你说的曾经没有我的故事 提交于 2021-02-07 14:30:27
问题 I'm a bit of a noob- and I'm having a hard time... I need a bit of of code that searches a db table to find the row that matches the $id variable. There's a field in that table 'description' that I need to grab. If it's null, I need to show one message, if not another. Here's the code I have (I know I need to add the mysqli escape string, just doing this real quick from memory): $query = "SELECT description FROM posts WHERE id = $id"; $result = mysqli_query($dbc, $query); $row = mysqli_fetch

How to use order by in Laravel when it uses CASE WHEN?

 ̄綄美尐妖づ 提交于 2021-02-07 13:58:18
问题 I can use orderBy method in Laravel like this: $posts = Post::orderBy('id', 'DESC')->get(); Ok, what about when there is CASE in the ORDER BY clause? Like this: ORDER BY CASE WHEN id.PinRequestCount <> 0 THEN 5 WHEN id.HighCallAlertCount <> 0 THEN 4 WHEN id.HighAlertCount <> 0 THEN 3 WHEN id.MediumCallAlertCount <> 0 THEN 2 WHEN id.MediumAlertCount <> 0 THEN 1 END desc, How can I write this ^ in Laravel? 回答1: Try this: ->orderByRaw( "CASE WHEN <CONDITION> THEN < > ELSE < > END DESC" ) 回答2:

How do I store the location of an image in a database?

泪湿孤枕 提交于 2021-02-07 13:24:06
问题 I have a list of colors, with textures that I want to show to particular users, so I need to load the image of the colors that a particular user has, the color's information is contained in a ObjecDTO and one of the properties is its image path. My question is how should I store the image path in the database, are there any special rules, for example since the database and the image file are on the same server should I store a complete file URL, or a relative url, what characters should I