multiplication

Pandas/Python multiply columns by row

我与影子孤独终老i 提交于 2019-12-02 16:57:04
问题 Apologies if this is a simple question. I have two dataframes each with the same columns. I need to multiply each row in the second dataframe by the only row in the first. Eventually there will be more columns of different ages so I do not want to just multiply by a scalar. I have used df.multiply() and continue to get NaN for all values presumably because the two df are not matched in length. Is there a way to multiply each row in one dataframe by a singular row in another? age 51200000.0

Multidimensional array multiplication

心不动则不痛 提交于 2019-12-02 13:14:49
Suppose I want a code in PHP that replicates matrix multiplication, where my matrices look like: $matrix_1 = array(array(1,2), array(3,4)) The number of subarrays ( 2 ) is equivalent to the number of columns in the matrix, whereas the number of elements in each subarray ( 2 ) represents the number of rows in the matrix. The code would need to: Account for matrices of different dimensions. Recognise when two matrices cannot be multipled (where the number of columns in matrix A is not the same as the number of rows in matrix B). Possibly account for scalar multiplication, where each element of a

Pandas/Python multiply columns by row

人走茶凉 提交于 2019-12-02 11:49:28
Apologies if this is a simple question. I have two dataframes each with the same columns. I need to multiply each row in the second dataframe by the only row in the first. Eventually there will be more columns of different ages so I do not want to just multiply by a scalar. I have used df.multiply() and continue to get NaN for all values presumably because the two df are not matched in length. Is there a way to multiply each row in one dataframe by a singular row in another? age 51200000.0 70000000.0 SFH 0 0.75 0.25 . age 51200000.0 70000000.0 Lambda 91.0 0.000000e+00 0.000000e+00 94.0 0

Raising a matrix to the power method JAVA

大兔子大兔子 提交于 2019-12-02 11:21:09
I am having a really hard time creating a method to raise a matrix to the power. I tried using this public static int powerMethod(int matrix, int power) { int temp = matrix ; for (int i = power; i == 1; i--) temp = temp * matrix ; return temp ; but the return is WAYYY off. Only the first (1,1) matrix element is on point. I tried using that method in a main like so // Multiplying matrices for (i = 0; i < row; i++) { for (j = 0; j < column; j++) { for (l = 0; l < row; l++) { sum += matrix[i][l] * matrix[l][j] ; } matrix[i][j] = sum ; sum = 0 ; } } // Solving Power of matrix for (i = 0; i < row;

Floating-point division in bash

久未见 提交于 2019-12-02 11:00:19
I'm trying to convert whatever numbers the user inputs into 2 decimal places. For instance What is the total cost in cents? 2345 output: 23.45 this is the code i have so far percentage=20 #cannot change numerical value must convert into 0.20 echo -n "What is the total cost? "; read cost_in_cents echo "scale 1; $cost_in_cents" | bc I'm also going to be doing some multiplication with percentage, how can i also convert the percentage into a float (0.20) Perhaps it's nostalgia for reverse polish notation desk calculators, but I'd use dc rather than bc here: dc <<<"2 k $cost_in_cents 100 / p"

write a javascript multiplication function that will return two separate results

霸气de小男生 提交于 2019-12-02 10:48:12
问题 As you can see from the embed below... my script is only returning one result(500). How can I rewrite my code so that I get both results? Thank you in advance for your advice. function multiplier() { var number = 25; var multiplier20 = 20; if (number && multiplier20); { return number * multiplier20; } var multiplier1 = 1; if (number && multiplier1); { return number * multiplier1; } } multiplier(); EDIT: hey guys thanks for the help. but I figured out what the problem was... I am not supposed

Multiplication of two 16-bit numbers - Why is the result 32-bit long? [closed]

∥☆過路亽.° 提交于 2019-12-02 10:03:01
If I multiplie two 16-bit numbers, the result will be 32-bit long. But why is this so? What is the clear explanation for this? And for my right understanding: The calculation for this is: n-bit number multiplied with a m-bit number gives a (n+m) bit number? (2 n - 1)*(2 m - 1) = 2 n+m - 2 n - 2 m + 1 -(2 n + 2 m ) is like clearing the bits at index n and m , which does not affect much the result compared to 2 n+m , so you need n+m bits to represent the result. For example 1111 2 *1111 2 = 11100001 2 (15*15 = 225) In general, (b n - 1)*(b m - 1) = b n+m - b n - b m + 1 , so multiply an n-digit

JavaScript simple calculation

时光毁灭记忆、已成空白 提交于 2019-12-02 09:56:25
I'm pretty sure I'm being stupid but why isn't this working!? form.find( '.per_time' ).on( 'change', function() { var price = parseInt( form.find( '.section-price' ).attr('data-price'), 10 ) ; var multiplier = parseInt( $( this ).val(), 10 ); var newprice = (price / 7) * multiplier; form.find( '.section-price .price' ).html( newprice ) }) It's this line I'm concerned about: var newprice = (price / 7) * multiplier; The calculation is not dividing by 7, it only calculates price * multiplier ? This code also seems to be dictating what happens but I'm pretty sure it's jsut a shorter version of the

Strange multiplication result

北战南征 提交于 2019-12-02 08:59:54
In my code I have this multiplications in a C++ code with all variable types as double[] f1[0] = (f1_rot[0] * xu[0]) + (f1_rot[1] * yu[0]); f1[1] = (f1_rot[0] * xu[1]) + (f1_rot[1] * yu[1]); f1[2] = (f1_rot[0] * xu[2]) + (f1_rot[1] * yu[2]); f2[0] = (f2_rot[0] * xu[0]) + (f2_rot[1] * yu[0]); f2[1] = (f2_rot[0] * xu[1]) + (f2_rot[1] * yu[1]); f2[2] = (f2_rot[0] * xu[2]) + (f2_rot[1] * yu[2]); corresponding to these values Force Rot1 : -5.39155e-07, -3.66312e-07 Force Rot2 : 4.04383e-07, -1.51852e-08 xu: 0.786857, 0.561981, 0.255018 yu: 0.534605, -0.82715, 0.173264 F1: -6.2007e-07, -4.61782e-16,

How do I move the result of a mul of two floats in x86 assembly?

元气小坏坏 提交于 2019-12-02 08:46:19
问题 I am currently trying to multiply two floats, one that comes from a float vector (address stored in ebx) and against the value I stored in ecx. I have confirmed that the input values are correct, however, if I multiply 32 and 1, for example, the value in EAX changes to 00000000 and the one in EDX to 105F0000. From my understanding of MUL, this happens because it is storing the high order bits of the result in EDX and the low order ones in EDX. Question is, how do I move the result into an