multiple-columns

问题 I am looking to make a two-column navigation bar by using a single <ul> with six <li> items: <nav> <ul> <li>Home</li> <li>About</li> <li>Team</li> <li>Store</li> <li>Blog</li> <li>Contact</li> </ul> </nav>​ Three elements on one side, and three on the other; ordered vertically. Right now, it's easy to do when making two seperate <ul> elements and putting padding/margins between them: http://jsfiddle.net/Baumr/SJcjN/ — but that's not a great solution. Could also wrap <span> tags around each

问题 I want to divide my Rmarkdown document like in picture. One column for the first section then two columns in the other sections. used \onecolumn and \twocolumn but each section is created in a single page. Is there a solution to fix it? 回答1: This article has been published in a journal of the AMS. Fortunately, the rticle package supports the AMS journals. I use the standard template as generated by RStudio, change layout in the YAML header and use fancyhdr to redefine the pagestyle: layout:

问题 I have a list of countries in alphabetical order like: Albania Andorra Armenia Austria Azerbaijan Belarus Belgium Bosnia and Herzegovina Bulgaria Croatia Cyprus Czech Republic Denmark Estonia Finland France Georgia Germany Greece ... I'm displaying them in a list: <ul class="mylist"> <li>Albania</li> <li>Andorra</li> <li>Armenia</li> <li>Austria</li> <li>Azerbaijan</li> ... </ul> The list displays 4 columns on large displays: ul.mylist li { float: left; width: 25%; } and 2 on small displays:

问题 I am currently learning Flexbox Layout and I can not find a solution to my problem. I tried with justify-content and flex-basis but it does not work. Does anyone have the solution ? The result I would like : section { display: flex; margin: 0 auto; justify-content: space-between; } .column { width: 100%; background-color: #e2e2e2; padding: 1%; margin: 1%; flex-grow: 1; flex-shrink: 1; flex-basis: 0; } #first { flex-grow: 2; flex-shrink: 2; flex-basis: 0; } <section> <div class="column" id=

问题 I am trying to replace every row's values in 2 columns with a vector of length 2. It is easier to show you. First here is a some data. set.seed(1234) x<-data.frame(x=sample(c(0:3), 10, replace=T)) x$ab<-0 #column that will be replaced x$cd<-0 #column that will be replaced The data looks like this: x ab cd 1 0 0 0 2 2 0 0 3 2 0 0 4 2 0 0 5 3 0 0 6 2 0 0 7 0 0 0 8 0 0 0 9 2 0 0 10 2 0 0 Every time x=2 or x=3, I want to ab=0 and cd=1. My attempt is this: x[with(x, which(x==2|x==3)), c(2:3)] <- c

问题 I am trying to replace every row's values in 2 columns with a vector of length 2. It is easier to show you. First here is a some data. set.seed(1234) x<-data.frame(x=sample(c(0:3), 10, replace=T)) x$ab<-0 #column that will be replaced x$cd<-0 #column that will be replaced The data looks like this: x ab cd 1 0 0 0 2 2 0 0 3 2 0 0 4 2 0 0 5 3 0 0 6 2 0 0 7 0 0 0 8 0 0 0 9 2 0 0 10 2 0 0 Every time x=2 or x=3, I want to ab=0 and cd=1. My attempt is this: x[with(x, which(x==2|x==3)), c(2:3)] <- c

问题 how can i display two columns in a list box? 回答1: A list box wasn't designed to display multi-column data. Even the Windows Forms version doesn't directly support that kind of data display. Your requirements aren't clear, but the simplest way to go would be to use a GridView control. It gives you a lot of functionality out of the box, and you can expand it to more columns very easily. If you need more control over the look or functionality, you can use a DataList instead. To get the scrolling

问题 This is an extension to the question on returning the rows of a matrix that meet a condition in R. Say I have the matrix: one two three four [1,] 1 6 11 16 [2,] 2 7 12 17 [3,] 3 8 11 18 [4,] 4 9 11 19 [5,] 5 10 15 20 [6,] 1 6 15 20 [7,] 5 7 12 20 I want to return all rows, where matrix$two == 7 AND matrix$three == 12 as fast as possible. This is the way I know to do it: out <- mat[mat$two == 7,] final_out <- out[out$three == 12, ] There should obviously be a method to get the contents of

问题 I'm using R v. 3.2.1 and data.table v 1.9.6. I have a data.table like the example below, which contains some coded binary columns classed as character with the values "0" and "1" and also a string vector that contains phrases with some of the same words as the binary column names. My ultimate goal is to create a wordcloud using both the words in the string vector and also the positive responses in the binary vectors. To do this, I first need to convert the positive responses in the binary

问题 I have about 150 files containing 3 columns of x, y, z values and no header. x1 y1 z1 x2 y2 z2 x3 y3 z3 ... xn yn zn For our compress sensing algorithm, I need to have these values in one column only x1 y1 z1 x2 y2 z2 . . . xn yn zn How could I perform this batch operation for 150 files, without using MatLab? From my previous question, I believe this could be done by using sed. But batch processing 150 files effectively is beyond my ability. I am running on Win7 with cygwin installed. Any