multidimensional-array

问题 I have an array looking like this: Array( ['some_first_category'] => Array( ['some_first_name'] => Array( [0]=>'first@email.com', [1]=>'second@email.com', [2]=>'third@email.com', [3]=>'fourth@email.com' ) ['some_second_name'] => Array ( [1]=>'first@email.com', [2]=>'second@email.com') ['some_third_name'] => Array( [1]=>'first@email.com', [2]=>'second@email.com', [3]=>'third@email.com', [4]=>'fourth@email.com' ) ['some_second_category'] => Array( ['some_first_name'] => Array( [0]=>'first@email

问题 Good morning, given the below data structure (in JSON for ease of reading) [ { "parent": "root", "active": "1", "label": "Index", "route": "/", "children": [ { "parent": "/", "active": "1", "label": "Products", "route": "/products", "children": [ { "parent": "/products", "active": "0", "label": "Test", "route": "/test" } ] } ] }, { "parent": "root", "active": "1", "label": "404", "route": "/404" }, { "parent": "root", "active": "1", "label": "Login", "route": "/login" } ] I am having major

问题 I am mainly interested in the viability of shrinking such an array. I'm working on a project where I have used single malloc() calls to each create individual moderately large 2D arrays. (Each only few tens of MiB, at the largest.) The thing is that over the life of one of the arrays, its content dramatically shrinks in size (by more than half). Obviously, I could just leave the array size alone for the life of the program. (It's only a x MiB on a system with GiB of RAM available.) But, we

问题 I am using Ruby on Rails 3.2.2 and Ruby 1.9.2. Given the following multidimensional Array : [["value1", "value1_other"], ["value2", "value2_other"], ["value3", "value3_other"]] I would like to get ( note : I would like to "extract" only the first value of all "nested" Array s): ["value1", "value2", "value3"] How can I make that in a smart way? 回答1: You can use Array#collect to execute a block for each element of the outer array. To get the first element, pass a block that indexes the array.

问题 How to convert an int[,] to byte[] in C#? Some code will be appreciated EDIT: I need a function to perform the following: byte[] FuncName (int[,] Input) 回答1: Since there is very little detail in your question, I can only guess what you're trying to do... Assuming you want to "flatten" a 2D array of ints into a 1D array of bytes, you can do something like that : byte[] Flatten(int[,] input) { return input.Cast<int>().Select(i => (byte)i).ToArray(); } Note the call to Cast : that's because

问题 I have a 2 dimension list of type string I'm trying to convert it to int. Things I've tried so far: [[float(i) for i in lst[j] for j in lst] with a for loop: for i in range(len(lst)): for j in range(len(lst[i])): lst[i][j]=float(lst[i][j]) 回答1: >>> nums = [['4.58416458379', '3.40522046551', '1.68991195077'], ['3.61503670628', '5.64553650642', '1.39648965337'], ['8.02595866276', '8.42455003038', '7.93340754534']] >>> [[float(y) for y in x] for x in nums] [[4.58416458379, 3.40522046551, 1

问题 I need to find a specific key in an array, and return both its value and the path to find that key . Example: $array = array( 'fs1' => array( 'id1' => 0, 'foo' => 1, 'fs2' => array( 'id2' => 1, 'foo2' => 2, 'fs3' => array( 'id3' => null, ), 'fs4' => array( 'id4' => 4, 'bar' => 1, ), ), ), ); search($array, 'fs3'); // Returns ('fs1.fs2.fs3', array('id3' => null)) search($array, 'fs2'); // Returns ('fs1.fs2', array('id2' => 1, ... )) I've been able to recurse through the array to find the

问题 I need to find a specific key in an array, and return both its value and the path to find that key . Example: $array = array( 'fs1' => array( 'id1' => 0, 'foo' => 1, 'fs2' => array( 'id2' => 1, 'foo2' => 2, 'fs3' => array( 'id3' => null, ), 'fs4' => array( 'id4' => 4, 'bar' => 1, ), ), ), ); search($array, 'fs3'); // Returns ('fs1.fs2.fs3', array('id3' => null)) search($array, 'fs2'); // Returns ('fs1.fs2', array('id2' => 1, ... )) I've been able to recurse through the array to find the

问题 Suppose I have 1x1x1x1x... array and wish to convert it to scalar? How do I do it? squeeze does not help. import numpy as np matrix = np.array([[1]]) s = np.squeeze(matrix) print type(s) print s matrix = [[1]] print type(s) print s s = 1 print type(s) print s 回答1: You can use the item() function: import numpy as np matrix = np.array([[[[7]]]]) print(matrix.item()) Output 7 回答2: Numpy has a function explicitly for this purpose: asscalar >>> np.asscalar(np.array([24])) 24 This uses item() in

问题 EveryBody.. i want to create one 8*8 dimensional array in objective c.. ( [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], [0, 0, 0, 0, 0, 0, 0, 0], ) like that.. And also use as one of the object can moved in it.. Like want to move MOVE_ARRAY = array([0, 0], [0, 2]) And also check the array's any position like 5*6 or 4*3 any.. So, Can any one help me about how