modulo

问题 In a c program i was trying the below operations(Just to check the behavior ) x = 5 % (-3); y = (-5) % (3); z = (-5) % (-3); printf(\"%d ,%d ,%d\", x, y, z); gave me output as (2, -2 , -2) in gcc . I was expecting a positive result every time. Can a modulus be negative? Can anybody explain this behavior? 回答1: C99 requires that when a/b is representable: (a/b) * b + a%b shall equal a This makes sense, logically. Right? Let's see what this leads to: Example A. 5/(-3) is -1 => (-1) * (-3) + 5%(

问题 I have seen this question asked a lot but never seen a true concrete answer to it. So I am going to post one here which will hopefully help people understand why exactly there is \"modulo bias\" when using a random number generator, like rand() in C++. 回答1: So rand() is a pseudo-random number generator which chooses a natural number between 0 and RAND_MAX , which is a constant defined in cstdlib (see this article for a general overview on rand() ). Now what happens if you want to generate a

问题 I don\'t really understand how modulus division works. I was calculating 27 % 16 and wound up with 11 and I don\'t understand why. I can\'t seem to find an explanation in layman\'s terms online. Can someone elaborate on a very high level as to what\'s going on here? 回答1: The result of a modulo division is the remainder of an integer division of the given numbers. That means: 27 / 16 = 1, remainder 11 => 27 mod 16 = 11 Other examples: 30 / 3 = 10, remainder 0 => 30 mod 3 = 0 35 / 3 = 11,

问题 I have numbers like 1100, 1002, 1022 etc. I would like to have the individual digits, for example for the first number 1100 I want to have 1, 1, 0, 0. How can I get it in Java? 回答1: To do this, you will use the % (mod) operator. int number; // = some int while (number > 0) { print( number % 10); number = number / 10; } The mod operator will give you the remainder of doing int division on a number. So, 10012 % 10 = 2 Because: 10012 / 10 = 1001, remainder 2 Note: As Paul noted, this will give