modulo

Recognizing when to use the modulus operator

血红的双手。 提交于 2019-11-27 02:38:12
I know the modulus (%) operator calculates the remainder of a division. How can I identify a situation where I would need to use the modulus operator? I know I can use the modulus operator to see whether a number is even or odd and prime or composite, but that's about it. I don't often think in terms of remainders. I'm sure the modulus operator is useful, and I would like to learn to take advantage of it. I just have problems identifying where the modulus operator is applicable. In various programming situations, it is difficult for me to see a problem and realize "Hey! The remainder of

Check if a number is divisible by 3 [closed]

人盡茶涼 提交于 2019-11-27 01:04:04
Write code to determine if a number is divisible by 3. The input to the function is a single bit, 0 or 1, and the output should be 1 if the number received so far is the binary representation of a number divisible by 3, otherwise zero. Examples: input "0": (0) output 1 inputs "1,0,0": (4) output 0 inputs "1,1,0,0": (6) output 1 This is based on an interview question. I ask for a drawing of logic gates but since this is stackoverflow I'll accept any coding language. Bonus points for a hardware implementation (verilog etc). Part a (easy): First input is the MSB. Part b (a little harder): First

Find if variable is divisible by 2

ε祈祈猫儿з 提交于 2019-11-27 00:24:55
问题 How do I figure out if a variable is divisible by 2? Furthermore I need do a function if it is and do a different function if it is not. 回答1: Use modulus: // Will evaluate to true if the variable is divisible by 2 variable % 2 === 0 回答2: Seriously, there's no jQuery plugin for odd/even checks? Well, not anymore - releasing "Oven" a jQuery plugin under the MIT license to test if a given number is Odd/Even. Source code is also available at http://jsfiddle.net/7HQNG/ Test-suites are available at

Modulo of negative numbers [duplicate]

拟墨画扇 提交于 2019-11-26 23:19:58
问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: Mod of negative number is melting my brain! I was wondering if there was a nicer algorithm for what I'm trying to do: wrapIndex(-6, 3) = 0 wrapIndex(-5, 3) = 1 wrapIndex(-4, 3) = 2 wrapIndex(-3, 3) = 0 wrapIndex(-2, 3) = 1 wrapIndex(-1, 3) = 2 wrapIndex(0, 3) = 0 wrapIndex(1, 3) = 1 wrapIndex(2, 3) = 2 wrapIndex(3, 3) = 0 wrapIndex(4, 3) = 1 wrapIndex(5, 3) = 2 I came up with function wrapIndex(i, i_max) { if(i

Modulus operation with negatives values - weird thing?

强颜欢笑 提交于 2019-11-26 23:02:23
问题 Can you please tell me how much is (-2) % 5 ? According to my Python interpreter is 3, but do you have a wise explanation for this? I've read that in some languages the result can be machine-dependent, but I'm not sure though. 回答1: By the way: most programming languages would disagree with Python and give the result -2 . Depending on the interpretation of modulus this is correct. However, the most agreed-upon mathematical definition states that the modulus of a and b is the (strictly positive

Loop through WordPress posts, and wrap each X post in a DIV

时光毁灭记忆、已成空白 提交于 2019-11-26 22:24:31
问题 Note: This is a self Q&A When building asymmetrical grid layouts in WordPress, it's common that you'd want to wrap each X post in a div, like so: div post post /div div post post /div div post post /div I'd like to avoid using a modulo operator as it gets confusing quickly. 回答1: Most people do this with a modulo operator, but it gets awkward to do it if no posts are found, or and even division occurs on the last post. I've expanded on the answer provided here by @The Shift Exchange to do it

How to make a modulo operation in objective-c / cocoa touch?

北慕城南 提交于 2019-11-26 22:00:24
I have two CGFloat values, and want to calculate the modulo result. Or in other words: I want to know what's left if valueA is placed as much as possible into valueB. So I just tried: CGFloat moduloResult = valueB % valueA; the compiler complains about the % and tells me: "invalid operands to binary %". Any idea? mouviciel % is for int or long , not float or double . You can use fmod() or fmodf() from <math.h> instead. Better is <tgmath.h> as suggested by the inventor of CGFloat . If I remember correctly modulo requires 2 ints as its input so you'd need something like: CGFloat moduloResult =

How does modulus operation works with float data type?

徘徊边缘 提交于 2019-11-26 21:42:39
问题 I m trying to find out a simple modulus operation on float data type. float a=3.14f; float b=10f; result=a%b; I m getting result= 3.14 Another example using decimal data types: decimal p=10; decimal q=40; result=p%q; getting answer=20. I am not understanding how does modulus works? 回答1: From the C# language spec on floating point remainder. In the case of x % y if x and y are positive finite values. z is the result of x % y and is computed as x – n * y , where n is the largest possible

C# ModInverse Function

[亡魂溺海] 提交于 2019-11-26 20:57:28
问题 Is there a built in function that would allow me to calculate the modular inverse of a(mod n)? e.g. 19^-1 = 11 (mod 30), in this case the 19^-1 == -11==19; 回答1: Since .Net 4.0+ implements BigInteger with a special modular arithmetics function ModPow (which produces “ X power Y modulo Z ”), you don't need a third-party library to emulate ModInverse. If n is a prime, all you need to do is to compute: a_inverse = BigInteger.ModPow(a, n - 2, n) For more details, look in Wikipedia: Modular

Python-style integer division & modulus in C

笑着哭i 提交于 2019-11-26 20:34:00
问题 In Python and Ruby, signed integer division truncates towards negative infinity, and signed integer modulus has the same sign the second operand: >>> (-41) / 3 -14 >>> (-41) % 3 1 However, in C and Java, signed integer division truncates towards 0, and signed integer modulus has the same sign as the first operand: printf("%d\n", (-41) / 3); /* prints "-13" */ printf("%d\n", (-41) % 3); /* prints "-2" */ What is the simplest and most efficient way in C to perform the same kind of division and