module

cordova - Failed: q is not supported

巧了我就是萌 提交于 2020-02-23 09:10:29
问题 When I build cordova this message view: Using "requireCordovaModule" to load non-cordova module "q" is not supported. Instead, add this module to your dependencies and use regular "require" to load it. How fix this problem? PS. I updated npm before this build problem. So it was not problem buildings before update. Sorry my English)) 回答1: Solved this problem by installing a lower version of cordova. Seems like every version of cordova that is > 8.1.1 breaks a number of plugins. For instance,

Use existing classes in prestashop module

隐身守侯 提交于 2020-02-04 22:58:08
问题 I am preparing a custom module for prestashop. I want to use in it some classes that exist in prestashop already (Orderdetail.php). How can I do this? Is the code below sufficient or do I need to include something else in addition? $order = new OrderDetail; 回答1: Yes, the native classes can be called like that. $order_detail = new OrderDetail(); However to use custom classes you need to include their files in the script you want to use them. include_once 'path_to_custom_class_file'; class

How to import a module from a directory outside of the `src` directory?

一个人想着一个人 提交于 2020-02-03 01:43:26
问题 I'm stuck when learning how to access a module. I'm trying to insert a folder other than src into src . It's not working and it gives me an error. Here this is my project tree. $ Project1 . |-- src | |-- main.rs | |--FolderinSrcFolder | |--folderinsrcmodule.rs | |--anothersrc | |--mod.rs | |-- rootmodule.rs |-- Cargo.toml |-- Cargo.lock How can I access anothersrc/mod.rs src/main.rs ? How can I access rootmodule.rs from src/main.rs ? I already read the Rust documentation. 回答1: Don't . Put all

How to send the OAuth request in Node

僤鯓⒐⒋嵵緔 提交于 2020-01-31 03:57:25
问题 I want to access the WS REST API in node.js. I have the oauth_consumer_key and the oauth_token and the API end point. The oauth_signature_method is HMAC-SHA1. How to send the OAuth request in Node? Is there a module/library to generate the request headers? What I expect is a function like: var httprequest = createRequest(url, method, consumer_key, token); UPDATE 10/14/2012. Adding the solution. I'm using the code below. var OAuth = require('oauth').OAuth; consumer = new OAuth('http://term.ie

Calling a Perl module from Python

会有一股神秘感。 提交于 2020-01-31 03:27:25
问题 my question is the inverse of this one. In particular, I've dozens of existing modules written in Perl, some are object oriented and others just export a group of functions. Now since I have to write certain scripts in python but still would like to call those Perl modules, I'm wondering 1) if it is achievable, and 2) if so, what would be the best way of doing it Ideally, the Perl modules would appear as "black boxes" to Python, so to speak. Something like: from perl_module import * return

Haskell import declaration

▼魔方 西西 提交于 2020-01-30 04:17:14
问题 I started to read about monad transformers and what puzzles me is Control.Monad.CatchIO 's import declaration which I see in many code examples: import "MonadCatchIO-transformers" Control.Monad.CatchIO (finally) What does this quoted token mean? I took a look at the Haskell 98 Report's section on import declarations, but this didn't help me understand. 回答1: Its a package-qualified import, which is a GHC extension. The string is a package name. See Package-qualified imports, from the ghc docs,

Inheritance vs class instance in python module import

放肆的年华 提交于 2020-01-29 19:15:15
问题 Apologies if this doesn't make sense, i'm not much of an experienced programmer. Consider the following code: import mymodule class MyClass: def __init__(self): self.classInstance = myModule.classInstance() and then ...... from mymodule import classInstance class MyClass(classInstance): def __init__(self): pass If I just wanted to use the one classInstance in MyClass, is it ok to import the specific class from the module and have MyClass inherit this class ? Are there any best practices, or

Inheritance vs class instance in python module import

核能气质少年 提交于 2020-01-29 19:15:11
问题 Apologies if this doesn't make sense, i'm not much of an experienced programmer. Consider the following code: import mymodule class MyClass: def __init__(self): self.classInstance = myModule.classInstance() and then ...... from mymodule import classInstance class MyClass(classInstance): def __init__(self): pass If I just wanted to use the one classInstance in MyClass, is it ok to import the specific class from the module and have MyClass inherit this class ? Are there any best practices, or

Inheritance vs class instance in python module import

北战南征 提交于 2020-01-29 19:12:50
问题 Apologies if this doesn't make sense, i'm not much of an experienced programmer. Consider the following code: import mymodule class MyClass: def __init__(self): self.classInstance = myModule.classInstance() and then ...... from mymodule import classInstance class MyClass(classInstance): def __init__(self): pass If I just wanted to use the one classInstance in MyClass, is it ok to import the specific class from the module and have MyClass inherit this class ? Are there any best practices, or

php7.1-zip installation under Ubuntu 18.04

感情迁移 提交于 2020-01-29 17:48:20
问题 as the title already explains I need to install the zip module from php 7.1 under Ubuntu 18.04. When every I use the command sudo apt-get install php7.1-zip and the follwing output. Reading package lists... Done Building dependency tree Reading state information... Done Some packages could not be installed. This may mean that you have requested an impossible situation or if you are using the unstable distribution that some required packages have not yet been created or been moved out of