module

How to run one python file in another file? [duplicate]

白昼怎懂夜的黑 提交于 2020-06-29 05:06:10
问题 This question already has answers here : How can I make one python file run another? [duplicate] (8 answers) Closed 20 days ago . import importlib importlib.import_module('file.py') error: ModuleNotFoundError: No module named 'file.py'; 'file' is not a package Is this a good way of running one file in another? If not, could you please tell me a better way? Thank you in advance! 回答1: If you want to import it as a module you should listen to the comments and do what they say (visit How to

cross module variable

风格不统一 提交于 2020-06-28 23:39:47
问题 from here I got an idea about how using variables from other modules. this all works fine with import foo as bar But I don't want to import my modules as "bar" I want to use it without any prefix like from foo import * Using this it´s impossible to modify variables from other modules. reading will work! any idea? suggestions? 回答1: As far as I know, there is no way to import a value from a module and have it readable and writable by the importing scope. When you just import foo in Python, it

How to import my own modules in python 3.6?

ⅰ亾dé卋堺 提交于 2020-06-27 10:41:40
问题 Let's say I have a file like: Project0\pizza.py Project0\make_pizza.py and pizza: def make_pizza(size,*toppings): print("\nMaking a " + str(size) + "-inch pizza with the following toppings:") for topping in toppings: print("- " + topping) and make_pizza: from pizza import make_pizza pizza.make_pizza(16, 'pepperoni') and as shown in the codes, I want to import pizza into make_pizza , but the IDE shows up an error that there is no module named pizza. How can I solve this problem and import

How to import my own modules in python 3.6?

£可爱£侵袭症+ 提交于 2020-06-27 10:39:52
问题 Let's say I have a file like: Project0\pizza.py Project0\make_pizza.py and pizza: def make_pizza(size,*toppings): print("\nMaking a " + str(size) + "-inch pizza with the following toppings:") for topping in toppings: print("- " + topping) and make_pizza: from pizza import make_pizza pizza.make_pizza(16, 'pepperoni') and as shown in the codes, I want to import pizza into make_pizza , but the IDE shows up an error that there is no module named pizza. How can I solve this problem and import

Can't figure out how to import modules in browser with javascript

别来无恙 提交于 2020-06-27 09:44:25
问题 This is a simple problem. I'm attempting to import modules from one javascript file to another, and then run it on Chrome. I'm using 2 javascript files and an html file, all in the same folder: first js file (testfile1.js): import {test} from 'testfile2.js'; test.func(); second js file (testfile2.js): let f = function() { console.log("TEST"); } let test = { func: f }; export test; The html file is plain, empty html file with a link to testfile1.js script in the header: <script type="text

VBA: New collection -> A module is not a valid type

流过昼夜 提交于 2020-06-27 08:56:15
问题 I'm trying to use a collection as part of a function, however I keep getting the error: "A module is not a valid type" on compile. Even if the function simply defines a collection, I get the same: Function CountUniqueTags() Dim table As Collection Set table = New Collection End Function This code is in a standard module, but the error implies I should be writing this in a class module, but Collection is a built-in class so I don't see the issue? 回答1: This was making me go crazy for a while,

Angular 9 Dynamically import modules with dynamic routes

China☆狼群 提交于 2020-06-26 12:15:25
问题 I want to import angular modules dynamically with variable string routes from backend service. For example my backend service sends to me this response when app is starting(using APP_INITIALIZER). { "hostname": "a-tenant", "modules": { "home": { "class": "HomeAModule", "path": "home-a.module", }, }, }, My app structure is: So i want to import a module like this const path = `./tenants/${response.hostname}/home/${response.modules.home.path}`; import(path).then(m => m[response.modules.home

Access graphics from drawable folder of a dynamic feature module from main module

眉间皱痕 提交于 2020-06-26 05:50:16
问题 I'm getting my feet wet with dynamic module split API delivery in order to break up my game app into Instant and Installable versions. I've been following the Codelabs tutorial here https://codelabs.developers.google.com/codelabs/on-demand-dynamic-delivery/index.html#0. Unfortunately it uses Kotlin for the MainActivity code, which is less specific than Java, but still fairly followable if you've done a Kotlin tutorial. The example includes accessing a text tile in an 'assets' folder in an

How should I export multiple groups of classes/interfaces from a package

☆樱花仙子☆ 提交于 2020-06-17 13:23:06
问题 I have a typescript package where I have 2 groups of classes/interfaces: writeAPI and readAPI. Both API's have identically named classes, for example there is a writable 'Node' and a readable 'Node'. I would like to prevent to add the group in the name of the class, like so: 'WritableNode', 'ReadableNode'. Is it possible to create a package that can be consumed by another package as follows: 1) import * as myAPIs from "myAPIs" const readableNode = new myAPIs.readable.Node() const writableNode

Two version of same dependency - lower version getting ignored

允我心安 提交于 2020-06-13 06:19:51
问题 I have a project in which two dependencies uses different version of same library. For instance, my project has dependency A and dependency B . A and B , both uses a common library/dependency X , but of different versions. A has v1 version of X and B has v2 version of X . So now when I add A & B as dependencies in my project, there are 2 versions of X in my project's go.sum . I was expecting, the respective versions will be referred at run time by A and B . But it is not the case. Somehow