models | 易学教程

orm练习题

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表关系图 models.py from django.db import models # Create your models here. class Teacher(models.Model): tid=models.AutoField(primary_key=True) tname=models.CharField(max_length=32) classes=models.ManyToManyField("Klass") def __str__(self): return self.tname class Grade(models.Model): gid=models.AutoField(primary_key=True) gname=models.CharField(max_length=32) def __str__(self): return self.gname class Klass(models.Model): kid=models.AutoField(primary_key=True) kname=models.CharField(max_length=32) grade=models.ForeignKey("Grade",on_delete=models.CASCADE) def __str__(self): return self.kname class

What are the Laravel naming conventions for controllers/models/views?

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问题 I remember hearing you should name your controllers, models and views in a special way. Either singular or plural. I don't remember which ones to name what though, and i can't find anything about it in the doc. I'm guessing it's like this: Controllers are plural Views are plural Models are singular Am i on the right track? I understand it's just a convention and you don't have to follow them, but i still want to know what the right way is. 回答1: In ASP.NET MVC, I use the convention you

ASP .NET MVC 3 Models + stored procedures

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问题 Im, new in ASP MVC and I don't know how to create Models which base on stored procedures from my db. I have already database which works with another application, and my web page must use mentioned db. I would be gratefull if someone can show me some piece of code describing the proper way how to do that. (if I wasnt clear: I need to create ASP .NET Models which use stored procedures from my database and nothing more) txh in advance 回答1: @fgeorgiew are you just needing to know how to populate

Django, filter users by group in a model foreign key

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问题 I have a model for a blog post where the owner of the post is a foreign key to User. With that model any user can own a blog post. I would like to change it so that only the users in a certain group -let's call it 'bloggers'- can own a blog post object. Ideally it should appear in the admin too, I mean in the blog post admin right now the menu for 'owner' lists all the users, it should only list the ones in the 'bloggers' group. How do I do that with Django 1.3? 回答1: Use limit_choices_to

Nested list in qml: data models in models

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问题 I am trying to implement a nested comment system in a QML interface. I have a model in C++ (subclassed from QAbstractListModel) in which each item in the model returns two values: one is a QString and the other is a QVariantMap with roleName "dataMap". This works fine with a QML ListView. Now each QVariantMap contains an item "data" which further contains a QVariantList "children". Now this lists basically other QVariantMaps with the same structure. My idea to implement this was to use a

In ASP.NET MVC3, how should one render multiple PartialViews backed by multiple Models?

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In MVC3 Razor, how do you create a page with multiple forms, so that each form is a partial view rendered with its own model? We have been trying various forms of calling Html.RenderPartial(), passing in the partialview name as well as an instance of our models that we're accessing through the ViewBag, but every method we've tried seems to have serious issues, and so we must have a fundamental misunderstanding of how this is supposed to operate in an ideal world. We have found some SO responses on similar topics ( like this one ) recommending a "super model" that contains references to each of

Ruby on Rails: create records for multiple models with one form and one submit

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问题 I have a 3 models: quote, customer, and item. Each quote has one customer and one item. I would like to create a new quote, a new customer, and a new item in their respective tables when I press the submit button. I have looked at other questions and railscasts and either they don't work for my situation or I don't know how to implement them. quote.rb class Quote < ActiveRecord::Base attr_accessible :quote_number has_one :customer has_one :item end customer.rb class Customer < ActiveRecord:

How to setup admin approval a model's edits

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问题 I need a system where a regular user can edit a model but the edits don't actually happen until they are approved by an administrator. I found a gem called paper_trail that does had model versioning but doesn't support specifically what I want to do. I'm wondering how other people have handled this problem. I should add that there are also associations that I would like to be able for the user to edit at the same time. They aren't very complicated, for example one is aliases. The more

Abstract base class model vs Proxy model in Django

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I am building a control panel that will have multiple sub-applications in Django. One of my models is an application , which will have important settings like name , description , install_path and id (so that I can associate specific settings and configuration values to this application. Right now I'm struggling with trying to figure out how to declare this particular model. Each application will do something completely different than each other application. One might manage specific CMS settings and another may handle password resets for our development environment. The goal is to get the

nested has_many :through in rails 3

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I know Rails doesn't support nested has_many :through relationships, though there's been talk and an open ticket about a patch since as early as Rails 2. I did come across a plugin that's pretty slick, but the master branches don't work with Rails 3 and I'm hesitant to use it for mission critical tasks in the app hence the lack of active recent development. So -- what's the best way to deal with these relations. class Author < ActiveRecord::Base has_many :contracts has_many :products, :through => :contracts class Product < ActiveRecord::Base has_many :contracts has_many :orders has_many