model-view-controller

问题 Below is my code snippet that I am trying to execute in Spring batch: @Bean public Job ioSampleJob() throws Exception { return this.jobBuilderFactory.get("DKSHSpringBatchApplication") .incrementer(new RunIdIncrementer()) .start(step1()).next(step2()) .next(step3()).next(step4()).build(); } Can anyone please help how I can execute my batch job. It was working fine initially but after several run it is just giving the old response. 来源： https://stackoverflow.com/questions/61042136/why-does

问题 I am trying to validate input data and if the validation is true, go to the next view. However, I can see my code is not existing the present page. Controller: public ActionResult ForgotLoginId() { return View(); } [HttpPost] [ValidateAntiForgeryToken] public ActionResult ForgotLoginId(Testing ForgotLIDAuthentication) { if (ModelState.IsValid) { using(SUPRTestingDBEntities2 db = new SUPRTestingDBEntities2()) { if (obj != null) { Session["LoginID"] = obj.EmailID.ToString(); Session["EmailID"]

问题 I am trying to validate input data and if the validation is true, go to the next view. However, I can see my code is not existing the present page. Controller: public ActionResult ForgotLoginId() { return View(); } [HttpPost] [ValidateAntiForgeryToken] public ActionResult ForgotLoginId(Testing ForgotLIDAuthentication) { if (ModelState.IsValid) { using(SUPRTestingDBEntities2 db = new SUPRTestingDBEntities2()) { if (obj != null) { Session["LoginID"] = obj.EmailID.ToString(); Session["EmailID"]

问题 Disclaimer: I'm very new to JavaFX and Model-View-Controller design principles. Here's my basic situation: I have a ScreenManager similar to the one outlined in this tutorial. Using the screen manager, I switch between several FXML screens using basic action handling on the screen buttons. The problem is that one of these is a game screen with a map. I'll be drawing a tile-based map onto this game screen, so I went with a TilePane in my FXML file(if there's a better way to draw tiles to an

问题 Need access model constant in blade not with full path class PaymentMethod extends Model { const PAYPAL_ACCOUNT = 'paypal_account'; const CREDIT_CARD = 'credit_card'; and in blade {{ App\Classes\Models\PaymentMethod::CREDIT_CARD }} work but {{ PaymentMethod::CREDIT_CARD }} throws Class 'PaymentMethod' not found 回答1: You may use aliases: in your config\app.php under aliases section : aliases => [ .... 'PaymentMethod' => App\Classes\Models\PaymentMethod::class ] then use it in your balde file {

问题 Closed . This question needs details or clarity. It is not currently accepting answers. Want to improve this question? Add details and clarify the problem by editing this post. Closed 9 days ago . I have class - AbstractOrder - it have basic realization and fields. And also i have three another which extends AbstractOrder - EmployeeOrder, StudentOrder, PostgraduateOrder, but have additional field - id. I would like to create a single validation class for all 3 entities. Here is my code. So,

问题 My problem originally was how to make fields show of a Foreignkey that is in ModelForm. I have solved this problem with this code but I can't get it to work. The following models make my code class DocAide(models.Model): id = models.AutoField(primary_key=True) pulse = models.DecimalField('Pulse', max_digits=3, decimal_places=0, blank=True, null=True) weight = models.DecimalField('Weight (kg)', max_digits=3, decimal_places=0, blank=True, null=True) bp_sys = models.DecimalField('BP Sys', max

问题 I'm trying to embrace Swift's value types more in my application design, but I'm having some beginner difficulties. I know those generally don't go over well in the StackOverflow format for being opinion-based, but I think there are best-practices here that are probably not particularly subjective. I understand all the theoretical benefits of structs, about avoiding shared mutable state, the copying behaviour that makes it easy to implement "undo", etc., but I have a hard time using it in

问题 i have written a code with a condition in global asax but what is happening is when the condition becomes true the codes goes infinity loops and runs there and there the code is as follows:::In Route.Config public class RouteConfig { public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("favicon.ico"); routes.IgnoreRoute("favicon-zurich.ico"); routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.MapRoute( name: "Default", url: "{controller}/{action}/{id}", /

问题 Hi I have grid with inline editing when i want to click cell to update i can see my timepicker and i can select value but when i pass next cell value is disappearing and not select or changing anything How can i solve it? @( Html.Kendo().Grid<MockUpForeNet.Controllers.CardDetailController.Days>() .Name("timegrid") .DataSource(d => d.Ajax().Read("TimeGridBinding", "CardDetail", new { rule = rule }).Update("UpdateTime","CardDetail").Model(keys => { keys.Id(k => k.DayId); keys.Field(c => c