mode

问题 I've been using the excellent answer here to find the mode for groups with data table. However, I'd also like to find the number of occurrences of the modal value of x for each group of variable y. How can I do this? Edit: there is a faster way to find mode than in the answer linked above. I can't find the answer I got it from (please edit and link if you do), but it uses this function (and finds multiple modes if they exist): MultipleMode <- function(x) { ux <- unique(x) tab <- tabulate

问题 I am trying to solve this problem: where U is here: s=c*e(t)+e_dot(t) and e(t)=theta(t)-thetad(t) and e_dot(t)=theta_dot(t)-thetad_dot(t) where thetad(theta desired)=sin(t)-- i.e signal to be tracked! and thetad_dot=cos(t),J=10,c=0.5,eta=0.5 I tried first with odeint- it gave error after t=0.4 that is theta(solution of above differential equation) fell flat to 0 and stayed thereafter. However when I tried to increase mxstep to 5000000 I could get somewhat correct graph till t=4.3s. I want to

问题 In the book "The Algorithm Design Manual" by Skiena, computing the mode (most frequent element) of a set, is said to have a Ω( n log n ) lower bound (this puzzles me), but also (correctly i guess) that no faster worst-case algorithm exists for computing the mode. I'm only puzzled by the lower bound being Ω( n log n ). See the page of the book on Google Books But surely this could in some cases be computed in linear time (best case), e.g. by Java code like below (finds the most frequent

问题 I'd like to know what is difference from the configuration point of view as well as theoretical point of view? Do these two modes use different port numbers? or any other difference? 回答1: My 2 cents. Single node setup (standalone setup) By default, Hadoop is configured to run in a non-distributed or standalone mode, as a single Java process. There are no daemons running and everything runs in a single JVM instance. HDFS is not used. You don't have to do anything as far as configuration is

问题 I now to ways to detect weather php script runs in cli or web server mode: if (defined('STDIN')) or: if (isset($argc)) Do they equally reliable or one of them is more ? 回答1: Neither. Check the value returned from php_sapi_name() . 回答2: $_SERVER['REQUEST_METHOD'] won't be set, due to the lack of a HTTP request. I think defined( 'STDIN' ) or isset( $argc ) are reliable too, though. If it was up to me, I'd probably go with the defined( 'STDIN' ), as I can imagine someone accidentally setting a

问题 I'm trying to write a java method which finds all the modes in an array. I know there is a simple method to find the mode in an array but when there are more than one single mode my method outputs only one of them. I've tried to find a way but am nit sure how to approach this problem. Can anyone help me out to find all the modes in the array? Thanks. Yes here is my code which outputs only one mode even if multiple modes exist. public static int mode(int a[]){ int maxValue=0, maxCount=0; for

问题 I successfully added dark mode to my site using This fiddle JS: $('#mode').change(function(){ if ($(this).prop('checked')) { $('body').addClass('dark-mode'); } else { $('body').removeClass('dark-mode'); } }); However, when refreshing the page the theme switches back obviously. I can't find out how to use sessionstorage to keep dark mode over the domain. Can someone help me? Thanks! 回答1: You can use local storage for storing the data function darkmode(){ $('body').addClass('dark-mode');

问题 I successfully added dark mode to my site using This fiddle JS: $('#mode').change(function(){ if ($(this).prop('checked')) { $('body').addClass('dark-mode'); } else { $('body').removeClass('dark-mode'); } }); However, when refreshing the page the theme switches back obviously. I can't find out how to use sessionstorage to keep dark mode over the domain. Can someone help me? Thanks! 回答1: You can use local storage for storing the data function darkmode(){ $('body').addClass('dark-mode');

问题 I'm looking for an elegant way of determining which element has the highest occurrence (mode) in a C++ ptr array. For example, in {"pear", "apple", "orange", "apple"} the "apple" element is the most frequent one. My previous attempts have failed EDIT: The array has already been sorted. int getMode(int *students,int size) { int mode; int count=0, maxCount=0, preVal; preVal=students[0]; //preVall holds current mode number being compared count=1; for(int i =0; i<size; i++) //Check each number in

问题 How do I find the mode (most frequent value in an array) using a simple for loop? The code compiles with a wrong output. Here is what I have: public static void mode(double [] arr) { double mode=arr[0]; for(int i = 1; i<arr.length; i++) { if(mode==arr[i]) { mode++; } } return mode; } 回答1: First I sort the array by order and then I count occurrences of one number. No hashmaps only for loop and if statements. My code: static int Mode(int[] n){ int t = 0; for(int i=0; i<n.length; i++){ for(int j