min

Find both min and max together: algorithm should be faster but isn't

由 坚强是说给别人听的谎言 提交于 2019-12-06 13:39:13
问题 I'm trying to implement an algorithm to find the minimum and the maximum values among a set of longs in a file. My test file contains one billion longs. The algorithm works as expected but does not perform faster than the naive version. It should be significantly faster as the naive version performs roughly 2n comparisons, whereas this version performs 3n/2 comparisons. $ time ./findminmax_naive somelongs count: 1000000000 min: 0 max: 2147483647 real 0m24.156s user 0m4.956s sys 0m3.896s $

Inno Setup get Min and Max Integer values in Pascal Script

由 北战南征 提交于 2019-12-06 13:01:06
问题 I need to return min and max values of two Integers in many situations in my Pascal Script. But every time I need to create a TStringList , add my two or more Integers to it and convert it to an Array Of String and then get its min and max values using two of my functions called ArrayOfStringMax and ArrayOfStringMin. I like to have two functions like Min and Max to make this easier like unit Math in Delphi. For example, Log(IntToStr(Min(1000, 26))); Output should be 26 . Log(IntToStr(Max(45,

SQL Data Range Min Max category

由 旧城冷巷雨未停 提交于 2019-12-06 10:11:10
I want to determine the range of 2 categories. Category A and Category B. A starts from 1 to 15, B starts from 16 to 31 then A Again starts from 32 to 40. Now If run this query select min(range), max(range) from table group by category order by category it gives me Range of category A from 1 to 40 and Category B from 16 to 31. I want to break the Range and want to see the results Category A 1 to 15 Category B 16 to 31 Category A 32 to 40 How do I do that? Do I need a 3rd column? I know if i have 3rd column with new categories lets say C D E respectively, I can group by those and get the

min() operation on nested groupby in pandas

由 梦想与她 提交于 2019-12-06 07:19:44
I am just getting to know pandas and I can't get over a conceptual problem. My dataframe is as follows: df=pd.DataFrame({'ANIMAL':[1,1,1,1,1,2,2,2], 'AGE_D' : [3,6,47,377,698,1,9,241], 'AGE_Y' : [1,1,1,2,2,1,1,1]}) I would like to do a nested group within animal and age_y and then select the min on the subgroup. Desired output would be then: ANIMAL AGE_Y AGE_D 1 1 3 1 2 377 2 1 1 I can do this without nesting within animal, e.g. if my df2 = subset for ANIMAL=1 then df2.loc[df2.groupby('AGE_Y')['AGE_D'].idxmin()] But all the things I tried with nesting the animal in the group by were

Reproduce behavior MAX_VALUE and MIN_VALUE

由 回眸只為那壹抹淺笑 提交于 2019-12-06 06:59:47
问题 The following also applied to other MIN_VALUE and MAX_VALUE , but let's only focus on Integer for now. I know that in Java integers are 32-bit, with Integer.MAX_VALUE = 2147483647 (2 31 -1) and Integer.MIN_VALUE = -2147483648 (-2 31 ). When calculating with these values when you go beyond their bounds, the number wraps around / overflows. So when you do something like Integer.MAX_VALUE + 1 , the result is the same as Integer.MIN_VALUE . Here are some basic arithmetic calculations with MIN

find min and max values in a datatable using C# [duplicate]

由 半世苍凉 提交于 2019-12-06 03:42:55
问题 This question already has answers here : Closed 8 years ago . Possible Duplicate: How to select min and max values of a column in a datatable? I am searching for code that could find the min and max (or first and last values) from a column in a datatable. I have stored the datatable with four column values I want to find the min and max values from the third column(index 2) and display it to the user. I tried many ways but all are causing exceptions... Last i tried this code but even this is

MySQL return max value or null if one column has no value

由 霸气de小男生 提交于 2019-12-06 01:00:08
问题 I try to get the max value of a mysql select, but want to have it null/empty/0 if there is one row containing no timestamp. Table stats (simplyfied): ID CLIENT ORDER_DATE CANCEL_DATE 1 5 1213567200 2 5 1213567200 3 6 1210629600 1281736799 4 6 1210629600 1281736799 5 7 1201042800 1248386399 6 7 1201042800 7 8 1205449200 1271282399 I'm now looking to get the lowest order date (no problem, as it is never empty), and the maximum cancel date. If the client has already cancelled his subscription,

Return tuple with smallest y value from list of tuples

由 北慕城南 提交于 2019-12-05 17:43:00
问题 I am trying to return a tuple the smallest second index value (y value) from a list of tuples. If there are two tuples with the lowest y value, then select the tuple with the largest x value (i.e first index). For example, suppose I have the tuple: x = [(2, 3), (4, 3), (6, 9)] The the value returned should be (4, 3) . (2, 3) is a candidate, as x[0][1] is 3 (same as x[1][1] ), however, x[0][0] is smaller than x[1][0] . So far I have tried: start_point = min(x, key = lambda t: t[1]) However,

std::initializer_list<> and a Reference Parameter

由 Deadly 提交于 2019-12-05 17:22:52
I'm new to using initializer lists and I'm wondering if they work similar to other stl containers. By that I mean do they copy values? What I'm trying to do is a simple min() function like this: template <class T> T& minArgs(const std::initializer_list<T&>& Arguments) { const T* Smallest = Arguments.begin(); for (const T* I = begin(Arguments); I != end(Arguments); ++I) { if (*I < *Smallest) Smallest = I; } return *Smallest; } However when I call the function I get this from GCC: error: 'const' qualifiers cannot be applied to 'int&' I've been playing around with this and it seems initializer

jquery: set min max input in option type number

由 走远了吗. 提交于 2019-12-05 15:08:49
问题 I have this part of code <input type="number" min="2" max="10" step="2" id="contact" oninput="new_sum"> In the field I can insert a number > 10 and < 2. How can I limit it? 回答1: add an onchange function and set the value if it's out of the range. $(function () { $( "#numberBox" ).change(function() { var max = parseInt($(this).attr('max')); var min = parseInt($(this).attr('min')); if ($(this).val() > max) { $(this).val(max); } else if ($(this).val() < min) { $(this).val(min); } }); }); <script
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