methods

问题 I have created my menu with do~while(true); but every time the user insert a number, instead of running the program it shows the the menu again! what do you think? // my main method public static void main(String[] args) { DataReader reader = new DataReader(); // The reader is used to read data from a file // Load data from the file if(reader.loadData(args[0])) { // The filename is entered using a command-line argument vehicles= reader.getVehicleData(); // Store the arrays of Vehicle //

问题 I have created my menu with do~while(true); but every time the user insert a number, instead of running the program it shows the the menu again! what do you think? // my main method public static void main(String[] args) { DataReader reader = new DataReader(); // The reader is used to read data from a file // Load data from the file if(reader.loadData(args[0])) { // The filename is entered using a command-line argument vehicles= reader.getVehicleData(); // Store the arrays of Vehicle //

问题 In the following code, I import a csv file into Python's pandas library and display the first 5 rows, and query the 'shape' of the pandas dataframe. import pandas as pd data = pd.read_csv('my_file.csv') data.head() #returns the first 5 rows of the dataframe data.shape # displays the # of rows and # of columns of dataframe Why is it that the head() method requires empty parentheses after head but shape does not? Does it have to do with their types? If I called head without following it with

问题 I am trying to paginate Model result, but I am getting "Method paginate does not exist.". Here is my code: $user_dispatches = Dispatch::all()->where('user_id', Auth::id())->paginate(10); I need to get all records where users id equals current authenticated users id. Works well without paginate() method. 回答1: You need to remove all() : Dispatch::where('user_id', Auth::id())->paginate(10); When you're using all() you get all the rows from the table and get a collection. Then you're using

问题 I am trying to paginate Model result, but I am getting "Method paginate does not exist.". Here is my code: $user_dispatches = Dispatch::all()->where('user_id', Auth::id())->paginate(10); I need to get all records where users id equals current authenticated users id. Works well without paginate() method. 回答1: You need to remove all() : Dispatch::where('user_id', Auth::id())->paginate(10); When you're using all() you get all the rows from the table and get a collection. Then you're using

问题 I'm having a problem with C#, I'd like to get a pointer of a method in my code, but it seems impossible. I need the pointer of the method because I want to no-op it using WriteProcessMemory. How would I get the pointer? Example code main() { function1(); function2(); } function1() { //get function2 pointer //use WPM to nop it (I know how, this is not the problem) } function2() { Writeline("bla"); //this will never happen because I added a no-op. } 回答1: I know this is very old, but an example

问题 This question already has answers here : Undefined reference to static class member (7 answers) Closed 4 years ago . I have started programming with Java, I just achieved which I consider as a "good" level in matter of language knowledge. For fun I decided to start programming using C++, I'm fairly new to this language but I'm a fast learner and I think it's not that far from Java. I've created a test class which has a value and a name as attributes, and an objects counter as a global

问题 Due to the fact that you can not use $this-> inside a static functio, how are you supposed to access regular functions inside a static? private function hey() { return 'hello'; } public final static function get() { return $this->hey(); } This throws an error, because you can't use $this-> inside a static. private function hey() { return 'hello'; } public final static function get() { return self::hey(); } This throws the following error: Non-static method Vote::get() should not be called

问题 I learned java generics some time ago, but now I'm learning collections and found some code that I don't understand. Here is the code: static <E> List<E> nCopies(int n, E value) It is from class java.util.Collections . My question is why there is: <E> List<E> and not only List<E> Obviously I am missing something, can someone clarify this for me? 回答1: In <E> List<E> , the first <E> denotes that E is a type parameter . If you hadn't specified it, then Java would think the E in E value referred

来源： https://stackoverflow.com/questions/35949723/using-method-in-switch-case-statements