merge

问题 I'am used to use git log --oneline --graph --decorate --all as alias git ll to see the graph of commits in terminal But a problem confuse me when every single time I merge my develop to master . The output of the command above may be like this: * 0d1bf7b (HEAD -> master) Fix typo * f843224 Merge 'develop' to 'master' |\ * | d673b76 (origin/master) Remove console.log for license information * | 5080afc Remove all http url in production * | f28e74b Merge branch 'develop' |\ \ * \ \ 75c5b90

问题 I'am used to use git log --oneline --graph --decorate --all as alias git ll to see the graph of commits in terminal But a problem confuse me when every single time I merge my develop to master . The output of the command above may be like this: * 0d1bf7b (HEAD -> master) Fix typo * f843224 Merge 'develop' to 'master' |\ * | d673b76 (origin/master) Remove console.log for license information * | 5080afc Remove all http url in production * | f28e74b Merge branch 'develop' |\ \ * \ \ 75c5b90

问题 Git will not let one push a branch that has a merge conflict. In our current situation, there are ~15 conflicting files, some of which are my code and some of which are other people's code. It is preferable that each person who changed code perform the merge on those particular files. How can we all work on our own files to complete the merge? Unmerged paths: both modified: foo.py # This I should fix both modified: bar.py # This Jeff Atwood should fix both added: bin/baz.py # This Joel

问题 Problem I'm trying to refactor a low-performing MERGE statement to an UPDATE statement in Oracle 12.1.0.2.0. The MERGE statement looks like this: MERGE INTO t USING ( SELECT t.rowid rid, u.account_no_new FROM t, u, v WHERE t.account_no = u.account_no_old AND t.contract_id = v.contract_id AND v.tenant_id = u.tenant_id ) s ON (t.rowid = s.rid) WHEN MATCHED THEN UPDATE SET t.account_no = s.account_no_new It is mostly low performing because there are two expensive accesses to the large (100M rows

问题 My data.frame DATA is k l g 1 A 2004 12 2 B 2004 3.4 3 C 2004 4.5 Another data.frame DATA2 is i d t 1 A 2012 22 2 B 2012 4.8 3 C 2012 5.6 I want to get 1 A 2004 12 1 A 2012 22 2 B 2004 3.4 2 B 2012 4.8 3 C 2004 4.5 3 C 2012 5.6 回答1: We can try rbindlist from data.table . Place the datasets in a list , rbind them with rbindlist and order by the first column. library(data.table) rbindlist(list(df1, df2))[order(k)] # k l g #1: A 2004 12.0 #2: A 2012 22.0 #3: B 2004 3.4 #4: B 2012 4.8 #5: C 2004

问题 My data.frame DATA is k l g 1 A 2004 12 2 B 2004 3.4 3 C 2004 4.5 Another data.frame DATA2 is i d t 1 A 2012 22 2 B 2012 4.8 3 C 2012 5.6 I want to get 1 A 2004 12 1 A 2012 22 2 B 2004 3.4 2 B 2012 4.8 3 C 2004 4.5 3 C 2012 5.6 回答1: We can try rbindlist from data.table . Place the datasets in a list , rbind them with rbindlist and order by the first column. library(data.table) rbindlist(list(df1, df2))[order(k)] # k l g #1: A 2004 12.0 #2: A 2012 22.0 #3: B 2004 3.4 #4: B 2012 4.8 #5: C 2004

问题 I need to merge line of a file using sed based on a pattern. eg: Input File: X1 A B C D E F \+ G H I J 1 \+ LK T PP E OO 2 X2 DDF F Y \+ J W Q .... OutPut Expected: X1 A B C D E F G H I J 1 LK T PP E OO 2 X2 DDF F Y J W Q .. I would like to equivalent of wat is possible in vi editor (:%s/\n+/ /g) Searching the web I found a solution, which logically should have worked sed -e '{:a; N; s/\n+/ /g; ta}' infile But this command defies my understanding and logic, and has produced output X1 A B C D

问题 There might be a *_join version for this I'm missing here, but I have two data frames, where The merging should happen in the first data frame, hence left_join I not only want to add columns, but also update existing columns in the first data frame, more specifically: replace NA's in the first data frame by values in the second data frame The second data frame contains more rows than the first one. Condition #1 and #2 make left_join fail. Condition #3 makes rows_update fail. So I need to do

问题 Want to merge 2 table and blank should fill with first table rows. DF1: Col1 Col2 Col3 A B C DF2: Col6 Col8 1 2 3 4 5 6 7 8 9 10 I am expecting result as below: Col1 Col2 Col3 Col6 Col8 A B C 1 2 A B C 3 4 A B C 5 6 A B C 7 8 A B C 9 10 回答1: Use assign, but then is necessary change order of columns: df = df2.assign(**df1.iloc[0])[df1.columns.append(df2.columns)] print (df) Col1 Col2 Col3 Col6 Col8 0 A B C 1 2 1 A B C 3 4 2 A B C 5 6 3 A B C 7 8 4 A B C 9 10 Or concat and replace NaN s by

问题 I have (more than) two dataframes: In [22]: df = pd.DataFrame({'database' : ['db1', 'db2', 'db3']}) In [23]: df1 = pd.DataFrame({'database' : ['db1', 'db2', 'db3']}) In [24]: df2 = pd.DataFrame({'database' : ['db2', 'db3', 'db4']}) In [25]: df1 Out[25]: database 0 db1 1 db2 2 db3 In [26]: df2 Out[26]: database 0 db2 1 db3 2 db4 What I want as output is dataframe in this format: Out[45]: database database 0 db1 1 db2 db2 2 db3 db3 3 db4 I manage to get it in this format like this: df1.index =