memory

问题 I notice that when running Espresso UI tests on an emulated device my system's memory usage increases indefinitely until I restart Android Studio and my emulated device. On inspection I can see that my Android Studio and emulated device memory usage remain constant, yet overall memory usage increases. However I cannot see where the additional memory is assigned in my system monitor. This happens even when running empty tests on a blank activity! Please see code attached I am running Android

问题 What happens in memory when there is a class with 50 methods and we create 50 object instances of that class? What is the best solution for having an object with a lot of functionality and less memory usage? 回答1: Yes, C#/.Net methods require memory on per-AppDomain basis, there is no per-instance cost of the methods/properties. Cost comes from: methods metadata (part of type) and IL. I'm not sure how long IL stays loaded as it really only needed to JIT so my guess it is loaded as needed and

问题 What happens in memory when there is a class with 50 methods and we create 50 object instances of that class? What is the best solution for having an object with a lot of functionality and less memory usage? 回答1: Yes, C#/.Net methods require memory on per-AppDomain basis, there is no per-instance cost of the methods/properties. Cost comes from: methods metadata (part of type) and IL. I'm not sure how long IL stays loaded as it really only needed to JIT so my guess it is loaded as needed and

问题 In more detail, the question is: without root permission , is it possible for a process to read (not only write) the memory of another process? (eg. by somehow reading /proc/gcore or /proc/[PID]/mem. I'm not sure their permission requirements yet.) I do understand that virtual address is implemented and each process has its own space. I did a quick search but find neither strong guarantees nor approaches to hack. This article says: Each process in the system has its own virtual address space.

问题 package main import ( "fmt" "unsafe" ) type A struct { a bool b int64 c int } type B struct { b int64 a bool c int } type C struct { } func main() { // output 24 fmt.Println(unsafe.Sizeof(A{})) // output 16 fmt.Println(unsafe.Sizeof(B{})) // output 0 fmt.Println(unsafe.Sizeof(C{})) } Struct A and B have the same fields, but if specified in different order they result in different size. why? Size of struct C is zero. How much memory is allocated by the system for a := C{} ? Thanks. 回答1: 1.

问题 I have created a sample application like below. I have a requirement to create 1024*1024 structs. Before calling the new operator my application is consuming some amount of memory (say 0.3mb). After calling the new operator the memory is increased (say 175mb). After calling the delete operator the memory is decreased (say 15mb). So finally there is a difference in the memory. I observed all these memory details from Task Manager. I am confused whether it should be considered as a memory leak,

问题 I am trying to speed up a script that I have written in Matlab that dynamically allocates memory to a matrix (basicallly reads a line of data from a file and writes it into a matrix, then reads another line and allocates more memory for a larger matrix to store the next line). The reason I did this instead of preallocating memory using zeroes() or something was that I don't know the exact size the matrix needs to be to hold all of the data. I also don't know the maximum size of the matrix, so

问题 I can't seem to find a definitive answer for this one. When invoking a shell command using exec() from PHP, does the memory that shell command uses count towards the memory limit that the PHP script is given? I realise that if the command generates a lot of output, and that output is captured in the $ouput (second) parameter of exec() , then that returned data could blow the PHP memory limit. However, assuming all output is sent to a file, if the exec() command requires 128M of memory to run,

问题 This question already has answers here : Is ((void *) -1) a valid address? (3 answers) Closed 3 years ago . I was looking at the documentation of sbrk system call and found this: On success, sbrk() returns the previous program break. (If the break was increased, then this value is a pointer to the start of the newly allocated memory). On error, (void *) -1 is returned, and errno is set to ENOMEM . Now, What's the significance of (void *) -1 ? What is the exact memory address it points to? (if

问题 I installed Jenkins on my vserver. When I had a look at htop Jenkins was running with 30 thread, each was allowed to allocate 247MB memory and up to 1181MB virtual memory. Because I've only a small vserver I tried to change the number of threads. But I could not find any configuration file. I installed jenkins via aptitude install jenkins and in htop I can see that Jenkins is running from: /usr/bin/java -jar /usr/share/jenkins/jenkins.war Tomcat isn't installed as well as jetty isn't