matrix

问题 I wanted to know, if it's possible to print a string followed by a matrix, written in the classic form, for example: 5 5 9 >>your matrix is M = 1 4 2 2 1 3 using fprintf / sprintf . 回答1: If your matrix doesn't have to be on the same line as the text, you can do something as simple as replacing ; with \n in the output of mat2str: A=[1 2 3; 4 5 6; 7 8 9]; intro_str = 'Your matrix is:\n'; sprintf([intro_str strrep(mat2str(A),';','\n ')]) Your matrix is: [1 2 3 4 5 6 7 8 9] If, however, you want

问题 I have combined two lists using zip syntax. When I saved it in csv format, whole data are stayed in one cell of excell. what's that i want is: each element of zipped file should be stay on each row. This is my code: list_of_first_column=["banana","cat","brown"] list_of_second_column=["fruit","animal","color"] graph_zip_file=zip(list_of_first_column,list_of_second_column) with open('graph.csv', 'w') as csv_file: writer = csv.writer(csv_file) writer.writerow(graph_zip_file) what I want in csv

问题 Are there built-in libraries to multiply a vector of points by an SVGMatrix? I have an SVG drawing that has been scaled, and I want to annotate that drawing in its original coordinate system with a line that has a fixed width in screen space. (I.e. the line should not change width when zooming in or out, but lines in the image do, of course.) So, my approach is to transform the image inside a , and then take my array of points and apply the same transformation, then create a new path object

问题 Are there built-in libraries to multiply a vector of points by an SVGMatrix? I have an SVG drawing that has been scaled, and I want to annotate that drawing in its original coordinate system with a line that has a fixed width in screen space. (I.e. the line should not change width when zooming in or out, but lines in the image do, of course.) So, my approach is to transform the image inside a , and then take my array of points and apply the same transformation, then create a new path object

问题 Please see the picture. In the matrix pictured, an entry is considered "New Business" from the leftmost value + the next 11 columns (so 12 months total). I've highlighted this "window" in yellow. Anything to the right of that window is "Return Business". For each column/month, I need to calculate both the New & Return Business. I need a formula or some method to derive these two sums from one column. I only need to be able to get one of these, because then I could just subtract it from the

问题 Please see the picture. In the matrix pictured, an entry is considered "New Business" from the leftmost value + the next 11 columns (so 12 months total). I've highlighted this "window" in yellow. Anything to the right of that window is "Return Business". For each column/month, I need to calculate both the New & Return Business. I need a formula or some method to derive these two sums from one column. I only need to be able to get one of these, because then I could just subtract it from the

问题 I'm using the camera intrinsic (fx, fy, cx, cy, width, hight) to store a depth image of TangoXyzIjData.xyz buffer. Therefore I calculate for each point of xyz the corresponding image point and store its z value x' = (fx * x) / z + cx y' = (fy * y) / z + cy depthImage[x'][y'] = z Now I would like to store the corresponding pose data as well. I'm using the timestamp of TangoXyzIjData.timestamp and the following function getPoseAtTime(double timestamp, TangoCoordinateFramePair framePair) with

问题 I am trying to translate some Matlab code I have into Python (using numpy). I have the following Matlab code: (1/x)*eye(2) X is simply 1000000. As I understand, * in Matlab indicates matrix multiplication, and the equivalent is .dot in numpy. So in Python, I have: numpy.array([(1/x)]).dot(numpy.identity(2)) I get the error "shapes (1,) and (2,2) not aligned: 1 (dim 0) != 2 (dim 0)" when I try to run the numpy code. Apparently I'm not understanding something. Anybody know what the proper numpy

问题 I'm working in PyCharm on Windows. In the project I'm currently working on I have "large" matrices, but when i output them Pycharm automatically adds linebreaks so that one row occupys two lines instead of just one: [[ 3. -1.73205081 0. 0. 0. 0. 0. 0. 0. 0. ] [-1.73205081 1. -1. -2. 0. 0. 0. 0. 0. 0. ] [ 0. -1. 1. 0. -1.41421356 0. 0. 0. 0. 0. ] [ 0. -2. 0. 1. -1.41421356 0. -1.73205081 0. 0. 0. ] [ 0. 0. -1.41421356 -1.41421356 0. -1.41421356 0. -1.41421356 0. 0. ] [ 0. 0. 0. 0. -1.41421356

问题 I have a matrix like this: I would like to sum every value of a single row but weighted. Example: Given a specific row, the sum would be: S = x1 * loan + x2 * mortdue + x3 * value + ... x1, x2, x3, ... are predefined values. I tried rowSums() and things like that but I have not been able to figure out how to do it properly. 回答1: You are looking for a matrix-vector multiplication. For example, if you have a matrix: set.seed(0) A <- matrix(round(rnorm(9), 1), 3) # [,1] [,2] [,3] #[1,] 1.3 1.3