math

问题 This question already has answers here : why Integer.MAX_VALUE + 1 == Integer.MIN_VALUE? (8 answers) Closed 1 year ago . I’m seeing some strange behavior multiplying integers with Java. I was doing some coding exercises and came upon the following fizz buzz type of exercise. The requirements: Given an integer, write a function that finds the product of every multiple of 3 which is smaller than the given integer, except any multiple of 5. Eg, given 17 we want to return 12*9*6*3 (= 1944). I

问题 Closed. This question needs debugging details. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 4 months ago . Improve this question I have a ckeditor where we can create math equation when I am fetch equation from database it look like a+b2 but I want like (a+b)^2 . So, How can I do this? Please help me. html_entity_decode($post->answer) I am using html_entity_decode but it not look exactly I want. 回答1:

问题 Since factoring a quadratic equation in my head just happens, and has done that since I learned it - how would I go about starting to write a quadratic factorer in Python? 回答1: Improving Keiths's answer: Start with a polynomial P(x) = a*x^2 + b*x + c . Use the quadratic formula (or another another method of your choice) to find the roots r1 and r2 to P(x) = 0 . You can now factor P(x) as a*(x-r1)(x-r2) . If your factor (3x - 4)(x - 9) the solution will be 3*(x - 4/3)(x - 9). You might want to

问题 Why doesn't math order [PEMDAS] within functions work right in R? These work fine: -27^(1/3) == -3 # TRUE -27^0.3333333333333333 == -3 # TRUE But these result in errors? foo <- function(x, y){return(x^(1/y))} foo(x = -27, y = 3) # NaN bar <- function(x, y){ a = 1 / y b = x^a return(b) } bar(x = -27, y = 3) # NaN Thanks in advance for the explanation. 回答1: Because of the surprisingly low precedence of the "unary minus" ( - ) operator, combined with R's convention for raising negative numbers

问题 My problem is limited to unsigned integers of 256 bits. I have a value x , and I need to descale it by the ratio n / d , where n < d . The simple solution is of course x * n / d , but the problem is that x * n may overflow. I am looking for any arithmetic trick which may help in reaching a result as accurate as possible. Dividing each of n and d by gcd(n, d) before calculating x * n / d does not guarantee success. Is there any process (iterative or other) which i can use in order to solve

问题 I need to generate all combinations of a matrix in Python. The input will be two integers n and m, and I need to generate all possible states of that matrix with 1 and 0 as possible values. For example: n = 3 m = 2 [[0 0 0] [1 0 0] [1 1 0] [0 0 0] [0 0 0] [0 0 0] [0 0 0],[0 0 0],[0 0 0] . . . . . ] Is there a clean and efficient way to do this given I will not know the values for n and m until runtime? The highest value used will be n = 16 m = 16. 回答1: One way is by generating all binary

问题 I need to generate all combinations of a matrix in Python. The input will be two integers n and m, and I need to generate all possible states of that matrix with 1 and 0 as possible values. For example: n = 3 m = 2 [[0 0 0] [1 0 0] [1 1 0] [0 0 0] [0 0 0] [0 0 0] [0 0 0],[0 0 0],[0 0 0] . . . . . ] Is there a clean and efficient way to do this given I will not know the values for n and m until runtime? The highest value used will be n = 16 m = 16. 回答1: One way is by generating all binary

问题 I'm trying to create a function with the following signature: function weightedRandom (target, probability) { // calculate weighted random number that is more likely to be near target value return value; // number from 0 to 1 } It should do the following: Generate random number from 0 to 1, but not including 1 The probability of any given number being picked in that range is NOT evenly distributed There is a greater chance that the number picked is near the target value (target is also a

问题 I have a class called Time , and I need to implement a Frequency class. How can I implement dividing int s or float s by an instance of Time to get an instance of Frequency ? I already know about __div__ , __truediv__ , __floordiv__ and other Python special methods, and I already use them in my code to divide instances of classes by numbers or instances of other classes, but I cannot find a way to divide a number by an instance of my class. Is it possible to implement dividing a number by an

问题 I have a class called Time , and I need to implement a Frequency class. How can I implement dividing int s or float s by an instance of Time to get an instance of Frequency ? I already know about __div__ , __truediv__ , __floordiv__ and other Python special methods, and I already use them in my code to divide instances of classes by numbers or instances of other classes, but I cannot find a way to divide a number by an instance of my class. Is it possible to implement dividing a number by an