malformedurlexception

URL u=new URL("telnet://route-server.exodus.net"); This line is generating : java.net.MalformedURLException: unknown protocol: telnet And i encounter similar problems with other URLs that begin with "news://" These are URLs extracted from ODP , so i dont understand why such exceptions arise.. Ben S Issue Java throws a MalformedURLException because it couldn't find a URLStreamHandler for that protocol. Check the javadocs of the constructors for the details. Summary: Since the URL class has an openConnection method, the URL class checks to make sure that Java knows how to open a connection of

I have url from the user and I have to reply with the fetched HTML. How can I check for the URL to be malformed or not ? For Example : url='google' // Malformed url='google.com' // Malformed url='http://google.com' // Valid url='http://google' // Malformed How can we achieve this ? cetver django url validation regex: regex = re.compile( r'^(?:http|ftp)s?://' # http:// or https:// r'(?:(?:[A-Z0-9](?:[A-Z0-9-]{0,61}[A-Z0-9])?\.)+(?:[A-Z]{2,6}\.?|[A-Z0-9-]{2,}\.?)|' #domain... r'localhost|' #localhost... r'\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})' # ...or ip r'(?::\d+)?' # optional port r'(?:/?|[/?]\S