main

问题 There is main application with logic and we extend app to Apple Watch. After adding target xCode creates 2 more applications: extension with code and watch kit application. Question: How code from extension can reuse logic of ready and already made main iOS app? How extension app can communicate with main App and send commands. 回答1: To communicate to the containing iPhone app you can use (BOOL)openParentApplication:(NSDictionary *)userInfo reply:(void (^)(NSDictionary *replyInfo, NSError

问题 Consider following program: #include <iostream> int main = ( std::cout << "C++ is excellent!\n", 195 ); Using g++ 4.8.1 (mingw64) on Windows 7 OS, the program compiles and runs fine, printing: C++ is excellent! to the console. main appears to be a global variable rather than a function; how can this program execute without the function main() ? Does this code conform to the C++ standard? Is the behavior of the program is well defined? I have also used the -pedantic-errors option but the

问题 I know there are many duplicates of this question, but I have looked at them all, and none of them have solved the issue. I am trying to run a class that has a main function. I have cleaned the project, checked the classpath for '.', added the bin folder to the classpath under run configurations. I'm not sure what else to try because the class is certainly in the source folder. Could someone please help me with this issue? package testIt; public class MemoryVisualizerApp extends Application{

问题 package com.valami; public class Ferrari { private int v = 0; private void alam() { System.out.println("alam"); } public Ferrari() { System.out.println(v); } public static void main(String[] args) { Ferrari f = new Ferrari(); f.v = 5; System.out.println(f.v); } } Hi all! I have one simple question.... WHY can I reach a private variable from the main method ? I know, I'm in the containing class, but it is main. I believed the main is NOT part of the class which is containing it... Then I would

问题 Using Python, reverse an integer and determine if it is a palindrome. Here is my definition of reverse and palindrome. Do I have a correct logic? def reverse(num): s=len(num) newnum=[None]*length for i in num: s=s-1 newnum[s]=i return newnum def palindrome(num): a=str(num) l=len(z)/2 if a[:1]==a[-1:][::-1]: b=True else: b=False I am having some trouble to write def main . 回答1: def palindrome(num): return str(num) == str(num)[::-1] 回答2: Integer numbers don't have len(). Testing if a number is

问题 It seems that the argv[argc] is always NULL , so I think we can traverse the argument list without argc . A single while loop will do this. If there is always a NULL at the end of argv , why do we need an argc ? 回答1: Yes, argv[argc]==NULL is guaranteed. See C11 5.1.2.2.1 Program startup (my emphasis) If they are declared, the parameters to the main function shall obey the following constraints: The value of argc shall be nonnegative. argv[argc] shall be a null pointer. Providing argc

问题 I can't figure what's my wrong with my code below. When I try to compile I get the message: does not contain a static 'main' method suitable for an entry point. This is my code: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; namespace RandomNumberGenerator { public partial class Form1 : Form { private const int rangeNumberMin = 1; private const int

问题 (I'm using Visual C++ 2008) I've always heard that main() is required to return an integer, but here I didn't put in return 0; and and it compiled with 0 errors and 0 warnings! In the debug window it says the program has exited with code 0. If this function is named anything other than main(), the compiler complains saying 'blah' must return a value. Sticking a return; also causes the error to appear. But leaving it out completely, it compiles just fine. #include <iostream> using namespace

问题 class NewClass{ public static void main(String a){ System.out.print("Hello"); } } When I'm trying to execute above code, then it shows an error, main method not found . But when I changed public static void main(String a) to public static void main(String... a) or public static void main(String a[]) . Then, it works..!! So, My question is how many different ways we can write legal main method signature and what this signature public static void main(String... a) means ? 回答1: Simply because

问题 class NewClass{ public static void main(String a){ System.out.print("Hello"); } } When I'm trying to execute above code, then it shows an error, main method not found . But when I changed public static void main(String a) to public static void main(String... a) or public static void main(String a[]) . Then, it works..!! So, My question is how many different ways we can write legal main method signature and what this signature public static void main(String... a) means ? 回答1: Simply because