lubridate

问题 Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . Improve this question I'm trying to convert my datetime from a csv to POSIXct for data analysis. I've tried multiple codes but either get NA or a wrong format. The code I'm currently using is GRS$datetimelocal<- GRS$`datetime` %>% ymd_hms(tz="UTC") %>% # first convert the `Date and

问题 Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . Improve this question I'm trying to convert my datetime from a csv to POSIXct for data analysis. I've tried multiple codes but either get NA or a wrong format. The code I'm currently using is GRS$datetimelocal<- GRS$`datetime` %>% ymd_hms(tz="UTC") %>% # first convert the `Date and

问题 I have a large data set with individual columns for event times and dates. I ended up creating a master dttm object with both the times and dates together, but have had trouble when I try to filter based on the date. Here is a sample data set that reflects my own: library(tidyverse) d<- structure(list(date = structure(c(1530921600, 1531008000, 1530403200, 1530489600, 1530576000, 1530489600, 1530576000, 1531008000, 1530921600, 1530662400, 1530748800, 1531180800, 1530748800, 1531526400,

问题 I have a large data set with individual columns for event times and dates. I ended up creating a master dttm object with both the times and dates together, but have had trouble when I try to filter based on the date. Here is a sample data set that reflects my own: library(tidyverse) d<- structure(list(date = structure(c(1530921600, 1531008000, 1530403200, 1530489600, 1530576000, 1530489600, 1530576000, 1531008000, 1530921600, 1530662400, 1530748800, 1531180800, 1530748800, 1531526400,

问题 library(tidyverse) library(lubridate) library(padr) df #> # A tibble: 828 x 5 #> Scar_Id Code Type Value YrMo #> <chr> <chr> <chr> <date> <date> #> 1 0070-179 AA Start_Date 2020-04-22 2020-04-01 #> 2 0070-179 AA Closure_Date 2020-05-23 2020-05-01 #> 3 1139-179 AA Start_Date 2020-04-23 2020-04-01 #> 4 1139-179 AA Closure_Date 2020-05-23 2020-05-01 #> 5 262-179 AA Start_Date 2019-08-29 2019-08-01 #> 6 262-179 AA Closure_Date 2020-05-23 2020-05-01 #> 7 270-179 AA Start_Date 2019-08-29 2019-08-01

问题 DF1: structure(list(X = c(113.8577674, 113.8577537, 113.8577403), Y = c(22.19537297, 22.19537222, 22.1953723), Date = c("7/1/2016", "7/1/2016", "7/1/2016"), Time = structure(c(9474, 9484, 9494 ), class = c("hms", "difftime"), units = "secs"), TrackTime = structure(c(38274, 38284, 38294), class = c("hms", "difftime"), units = "secs")), .Names = c("X", "Y", "Date", "Time", "TrackTime"), row.names = c(NA, -3L), class = "data.frame", spec = structure(list( cols = structure(list(X = structure(list

问题 I have a vector of numerics representing the number of milliseconds since January 1, 1970. I would like to convert these into a date time object using lubridate . A sample of data is below: raw_times <- c(1139689917479, 1139667123031, 1140364113915, 1140364951003, 1139643685434, 1139677091970, 1139691963511, 1140339448413, 1140368308429, 1139686613641, 1139666081813, 1140351488730, 1140346617958, 1141933663183, 1141933207579, 1140360125149, 1140351845108, 1140365079103, 1141933549825,

问题 This question already has an answer here : Outputting difftime as HH:MM:SS:mm in R (1 answer) Closed 3 years ago . I would like to calculate the difference between two time-sets. I can do this, but I only get the difference in decimals and I would like to know how to convert them to format as in "Minutes:Second". So, I have the minutes and the seconds as characters: video_begin <- c("8:14", "4:47", "8:27", "4:59", "4:57", "7:51", "6:11", "5:30") video_end <- c("39:08", "47:10", "49:51", "44

问题 I am using dplyr and lubridate. I am using read_excel to export a data.frame into R from excel. In Excel, I have a column that consists of mdy_hms AM or PM. In R, my code consists of: df$dateTimeEtc And this prints out as an example: "2017-03-07 11:10:37 UTC" "2017-03-22 10:04:42 UTC" "2017-03-08 09:36:49 UTC" However, I have tried to use: df <- df %>% mutate(dateTimeEtc = mdy_hms(dateTimeEtc)) So that R recognizes these data points in a mdy_hms (not sure what to do to include the AM/PM)

问题 I am trying to get both week number and year from a date object in R. Until then, I did it separately : I used isoweek() function to extract week and year() function to extract year. So that my data.frame has 3 variables : date, week, year This is working except for beginning/end of year : for example, 2015 has 53 weeks and January 1st, 2016 belongs to the 53rd week of 2015 ... but with my code, it is such that 1/1/2016 is week 53 but year 2016 whereas I would like it to be week 53 in year