loops

问题 This code scrapes the HTML table from https://www.asx.com.au/asx/statistics/prevBusDayAnns.do and downloads PDF files for specific ASX Codes and Headlines. When the for loop iterates over the ASX Codes found in 'data', it iterates over the first ASX Code five times which creates five duplicate of the same PDF. For example, in the code below there would be five copies of TWD. The amount of times the for loop iterates over the first ASX code is equal to the amount of ASX Codes in 'data'. For

问题 So I need to write a program which generates random numbers from 100 to 999, and the tricky part is that the digits in the number can't be the same. For example: 222 , 212 and so on are not allowed. So far, I have this: import random a = int (random.randint(1,9)) <-- first digit b = int (random.randint(0,9)) <-- second digit c = int (random.randint(0,9)) <-- third digit if (a != b and a != b and b != c): print a,b,c As you can see, I generate all three digits separately. I think it's easier

问题 So I need to write a program which generates random numbers from 100 to 999, and the tricky part is that the digits in the number can't be the same. For example: 222 , 212 and so on are not allowed. So far, I have this: import random a = int (random.randint(1,9)) <-- first digit b = int (random.randint(0,9)) <-- second digit c = int (random.randint(0,9)) <-- third digit if (a != b and a != b and b != c): print a,b,c As you can see, I generate all three digits separately. I think it's easier

问题 My data sample : <table id = "history"> <tr class = "printCol"> <td class="name">Google</td><td class="date">07/11/2001</td><td class="state"> <span>CA</span> </td> </tr> <tr class = "printCol"> <td class="name">Apple</td><td class="date">27/08/2001</td> </tr> <tr class = "printCol"> <td class="name">Microsoft</td><td class="date">01/11/1991</td> </tr> </table> Beautifulsoup code : table = soup.find("table", id = "history") rows = table.findAll('tr') for tr in rows: cols = tr.findAll('td')

问题 What I am trying to do is pretty simple, but I couldn't find how to do it. Starting with 1st element, put every 4th element into a new list. Repeat with the 2nd, 3rd, and 4th elements. From: list = ['1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b'] To: list1 = ['1', '5', '9'] list2 = ['2', '6', 'a'] list3 = ['3', '7', 'b'] list4 = ['4', '9'] In other words, I need to know how to: Get the Nth element from a list (in a loop) Store it in new arrays Repeat 回答1: The specific solution is to

问题 What I am trying to do is pretty simple, but I couldn't find how to do it. Starting with 1st element, put every 4th element into a new list. Repeat with the 2nd, 3rd, and 4th elements. From: list = ['1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b'] To: list1 = ['1', '5', '9'] list2 = ['2', '6', 'a'] list3 = ['3', '7', 'b'] list4 = ['4', '9'] In other words, I need to know how to: Get the Nth element from a list (in a loop) Store it in new arrays Repeat 回答1: The specific solution is to

问题 I have a data frame as shown below. which is doctors appointment data. B_ID No_Show Session slot_num Cumulative_no_show 1 0.4 S1 1 0.4 2 0.3 S1 2 0.7 3 0.8 S1 3 1.5 4 0.3 S1 4 1.8 5 0.6 S1 5 2.4 6 0.8 S1 6 3.2 7 0.9 S1 7 4.1 8 0.4 S1 8 4.5 9 0.6 S1 9 5.1 12 0.9 S2 1 0.9 13 0.5 S2 2 1.4 14 0.3 S2 3 1.7 15 0.7 S2 4 2.4 20 0.7 S2 5 3.1 16 0.6 S2 6 3.7 17 0.8 S2 7 4.5 19 0.3 S2 8 4.8 From the above when ever u_cumulative > 0.8 create a new row just below that with No_Show = 0.0 and its Session

问题 Suppose I have n number of data frames df_1 , df_2 , df_3 , ... df_n , containing respectively columns named SPEED1 , SPEED2 , SPEED3 , ..., SPEEDn , for instance: import numpy as np df_1 = pd.DataFrame({'SPEED1':np.random.uniform(0,600,100)}) df_2 = pd.DataFrame({'SPEED2':np.random.uniform(0,600,100)}) and I want to make the same changes to all of the data frames. How do I do so by defining a function on similar lines? def modify(df,nr): df_invalid_nr=df_nr[df_nr['SPEED'+str(nr)]>500] df

问题 (Print a table) Write a program that displays the following table. Cast floating point numbers into integers. a b pow(a, b) 1 2 1 2 3 8 3 4 81 4 5 1024 5 6 15625 I am having trouble conceptualizing how I can make this code simpler using loops. public class Exercise_02_eighteen { public static void main(String[] args) { float a, b; System.out.println("a b pow(a, b)"); a = 1; b = 2; System.out.println((int)a + " " + (int)b + " " + (int)Math.pow(a, b)); a++; b++; System.out.println((int)a + " "

问题 (Print a table) Write a program that displays the following table. Cast floating point numbers into integers. a b pow(a, b) 1 2 1 2 3 8 3 4 81 4 5 1024 5 6 15625 I am having trouble conceptualizing how I can make this code simpler using loops. public class Exercise_02_eighteen { public static void main(String[] args) { float a, b; System.out.println("a b pow(a, b)"); a = 1; b = 2; System.out.println((int)a + " " + (int)b + " " + (int)Math.pow(a, b)); a++; b++; System.out.println((int)a + " "