loops

How to assign random values from a list to a column in a pandas dataframe?

由 a 夏天 提交于 2020-05-23 13:12:11
问题 I am working with Python in Bigquery and have a large dataframe df (circa 7m rows). I also have a list lst that holds some dates (say all days in a given month). I am trying to create an additional column "random_day" in df with a random value from lst in each row. I tried running a loop and apply function but being quite a large dataset it is proving challenging. My attempts passed by the loop solution: df["rand_day"] = "" for i in a["row_nr"]: rand_day = sample(day_list,1)[0] df.loc[i,"rand

Bash: loop through files that DO NOT match extension

由 一世执手 提交于 2020-05-23 10:06:11
问题 I'm writing a bash script that needs to loop files inside a directory that do not match a specific extension. So far, I've found that the following code loops all files that matches the given extension: for f in *.txt ; do echo $f; done How could insthead loop through files that do not match the specified extension? 回答1: You can pattern-match with the == operator. for f in *; do [[ $f == *.txt ]] && continue # [[ $f != *.txt ]] || continue ... done If this might run in an empty directory,

JavaScript - Map() increment value

由 纵然是瞬间 提交于 2020-05-23 05:48:06
问题 I have a map as follows: let map = new Map(); map.set("a", 1); //Map is now {'a' => 1} I want to change the value of a to 2, or increment it: map.get("a")++; Currently, I am using the following: map.set("a", (map.get("a"))+1); However, this does not feel right. Does anyone know a cleaner way of doing this? Is it possible? 回答1: The way you do it is fine. That is how you need to do it if you are working with primitive values. If you want to avoid the call to map.set , then you must revert to a

JavaScript - Map() increment value

由 柔情痞子 提交于 2020-05-23 05:47:22
问题 I have a map as follows: let map = new Map(); map.set("a", 1); //Map is now {'a' => 1} I want to change the value of a to 2, or increment it: map.get("a")++; Currently, I am using the following: map.set("a", (map.get("a"))+1); However, this does not feel right. Does anyone know a cleaner way of doing this? Is it possible? 回答1: The way you do it is fine. That is how you need to do it if you are working with primitive values. If you want to avoid the call to map.set , then you must revert to a

For each in XSLT loops through only first record

由 不羁岁月 提交于 2020-05-18 19:38:29
问题 Trying to convert XML to CSV for the XML Below: <?xml version="1.0" encoding="UTF-8"?> <Envelope xmlns="http://schemas.microsoft.com/dynamics/2011/01/documents/Message"> <Header> <MessageId>{70BF3A9B-9111-48D8-93B4-C6232E74307F}</MessageId> <Action>http://tempuri.org/example/find</Action> </Header> <Body> <MessageParts> <Document xmlns="urn:iso:std:iso:20022:tech:xsd:pain.001.001.02" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <pain.001.001.02> <GrpHdr> <MsgId>AB01029407</MsgId>

For each in XSLT loops through only first record

由 Deadly 提交于 2020-05-18 19:38:29
问题 Trying to convert XML to CSV for the XML Below: <?xml version="1.0" encoding="UTF-8"?> <Envelope xmlns="http://schemas.microsoft.com/dynamics/2011/01/documents/Message"> <Header> <MessageId>{70BF3A9B-9111-48D8-93B4-C6232E74307F}</MessageId> <Action>http://tempuri.org/example/find</Action> </Header> <Body> <MessageParts> <Document xmlns="urn:iso:std:iso:20022:tech:xsd:pain.001.001.02" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <pain.001.001.02> <GrpHdr> <MsgId>AB01029407</MsgId>

For each in XSLT loops through only first record

由 笑着哭i 提交于 2020-05-18 19:38:13
问题 Trying to convert XML to CSV for the XML Below: <?xml version="1.0" encoding="UTF-8"?> <Envelope xmlns="http://schemas.microsoft.com/dynamics/2011/01/documents/Message"> <Header> <MessageId>{70BF3A9B-9111-48D8-93B4-C6232E74307F}</MessageId> <Action>http://tempuri.org/example/find</Action> </Header> <Body> <MessageParts> <Document xmlns="urn:iso:std:iso:20022:tech:xsd:pain.001.001.02" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <pain.001.001.02> <GrpHdr> <MsgId>AB01029407</MsgId>

How would I put a pause in a .forEach interation

由 一个人想着一个人 提交于 2020-05-17 11:28:11
问题 I am attempting to put in a pause between a forEach loop for a list. I would have thought the timeout would cause a pause for the loop but it just seems to start 3 timers all at once. (In very quick succession.) startTimeout(int seconds) async { print('Timer Being called now'); var duration = Duration(seconds: seconds); Timer(duration, doSomething()); } startDelayedWordPrint() { List<String> testList = ['sfs','sdfsdf', 'sfdsf']; testList.forEach((value) async { await startTimeout(30000);

How would I put a pause in a .forEach interation

由 大兔子大兔子 提交于 2020-05-17 11:27:22
问题 I am attempting to put in a pause between a forEach loop for a list. I would have thought the timeout would cause a pause for the loop but it just seems to start 3 timers all at once. (In very quick succession.) startTimeout(int seconds) async { print('Timer Being called now'); var duration = Duration(seconds: seconds); Timer(duration, doSomething()); } startDelayedWordPrint() { List<String> testList = ['sfs','sdfsdf', 'sfdsf']; testList.forEach((value) async { await startTimeout(30000);

How would I put a pause in a .forEach interation

由 ♀尐吖头ヾ 提交于 2020-05-17 11:27:03
问题 I am attempting to put in a pause between a forEach loop for a list. I would have thought the timeout would cause a pause for the loop but it just seems to start 3 timers all at once. (In very quick succession.) startTimeout(int seconds) async { print('Timer Being called now'); var duration = Duration(seconds: seconds); Timer(duration, doSomething()); } startDelayedWordPrint() { List<String> testList = ['sfs','sdfsdf', 'sfdsf']; testList.forEach((value) async { await startTimeout(30000);
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