for-loop

Async/await inside for…of vs. map

∥☆過路亽.° 提交于 2020-12-12 10:31:30
问题 I'm trying to figure out why promises seem to work differently inside of for...of vs. map() . data is an array of objects of the form {app: MY_APP, link: MY_LINK} . I'm trying to convert it to the form {app: MY_APP, status: true OR false}} . The function checkLink() is async because it uses node-fetch and basically returns whether the given link is 200. Using for...of , I get the desired object: let objToSend = []; for (obj of data) { objToSend.push({ app: obj.app, status: await checkLink(obj

Can end statement replace endfor statement in Octave?

二次信任 提交于 2020-12-12 07:09:53
问题 This link illustrates that we should use endfor statement to close the scope of for loop. But replacing it with end results into the same behavior. Does using end rather than endfor have any unexpected side effects? 回答1: end is synonymous with endfor when closing a for loop. The only side effect of using end is that your code will also be compatible with MATLAB, as endfor is an extension of the language invented by Octave. I recommend that you do not use endfor and the like ( endif ,

Can end statement replace endfor statement in Octave?

牧云@^-^@ 提交于 2020-12-12 07:05:15
问题 This link illustrates that we should use endfor statement to close the scope of for loop. But replacing it with end results into the same behavior. Does using end rather than endfor have any unexpected side effects? 回答1: end is synonymous with endfor when closing a for loop. The only side effect of using end is that your code will also be compatible with MATLAB, as endfor is an extension of the language invented by Octave. I recommend that you do not use endfor and the like ( endif ,

Can end statement replace endfor statement in Octave?

|▌冷眼眸甩不掉的悲伤 提交于 2020-12-12 07:04:04
问题 This link illustrates that we should use endfor statement to close the scope of for loop. But replacing it with end results into the same behavior. Does using end rather than endfor have any unexpected side effects? 回答1: end is synonymous with endfor when closing a for loop. The only side effect of using end is that your code will also be compatible with MATLAB, as endfor is an extension of the language invented by Octave. I recommend that you do not use endfor and the like ( endif ,

beginner Python program using count-based iteration structure

懵懂的女人 提交于 2020-12-09 06:42:53
问题 I am in a beginner Python programming class and we were to write a program that generates an item description, it's price, and the total. The program I originally wrote used LISTS which landed me a fat 0 for the assignment because apparently we were not to use lists on this assignment. Fortunately for me I get to rewrite it. SO, I am supposed to use a count-based iteration structure, I can use the “for” statement, or both the “for” and “while” statements. But NOT just the “while” statement

beginner Python program using count-based iteration structure

心不动则不痛 提交于 2020-12-09 06:42:19
问题 I am in a beginner Python programming class and we were to write a program that generates an item description, it's price, and the total. The program I originally wrote used LISTS which landed me a fat 0 for the assignment because apparently we were not to use lists on this assignment. Fortunately for me I get to rewrite it. SO, I am supposed to use a count-based iteration structure, I can use the “for” statement, or both the “for” and “while” statements. But NOT just the “while” statement

Cycling values of a list [duplicate]

让人想犯罪 __ 提交于 2020-12-08 06:03:37
问题 This question already has answers here : Python list rotation [duplicate] (4 answers) Closed 13 days ago . I'm new to coding and am trying to write a simple code that will take a list, say [1,2,3] and cycle the elements n number of times. So if n=1, I should get A=[3,1,2]. If n=2, I should get A=[2,3,1].The code I have written is: n=1 j=0 A = [1,2,3] B = [None]*len(A) while j<=n: for i in range(0,len(A)): B[i] = A[-1+i] j=j+1 print(B) The problem is that no matter what the value of n is I get

Cycling values of a list [duplicate]

孤人 提交于 2020-12-08 05:56:06
问题 This question already has answers here : Python list rotation [duplicate] (4 answers) Closed 13 days ago . I'm new to coding and am trying to write a simple code that will take a list, say [1,2,3] and cycle the elements n number of times. So if n=1, I should get A=[3,1,2]. If n=2, I should get A=[2,3,1].The code I have written is: n=1 j=0 A = [1,2,3] B = [None]*len(A) while j<=n: for i in range(0,len(A)): B[i] = A[-1+i] j=j+1 print(B) The problem is that no matter what the value of n is I get

Replace Nested For Loops… or not

五迷三道 提交于 2020-12-05 07:13:25
问题 I have a script that loops through a series of four (or less) characters strings. For example: aaaa aaab aaac aaad If have been able to implement it with nested for loops like so: chars = string.digits + string.uppercase + string.lowercase for a in chars: print '%s' % a for b in chars: print '%s%s' % (a, b) for c in chars: print '%s%s%s' % (a, b, c) for d in chars: print '%s%s%s%s' % (a, b, c, d) Is this sort of loop nesting a bad thing, and if so, what would be a better way of accomplishing

Replace Nested For Loops… or not

情到浓时终转凉″ 提交于 2020-12-05 07:13:21
问题 I have a script that loops through a series of four (or less) characters strings. For example: aaaa aaab aaac aaad If have been able to implement it with nested for loops like so: chars = string.digits + string.uppercase + string.lowercase for a in chars: print '%s' % a for b in chars: print '%s%s' % (a, b) for c in chars: print '%s%s%s' % (a, b, c) for d in chars: print '%s%s%s%s' % (a, b, c, d) Is this sort of loop nesting a bad thing, and if so, what would be a better way of accomplishing