for-loop

问题 I know this was asked a lot but I can not work with/understand the answers so far. I want to change the suffix of variables in a for loop. I tried all answers the stackoverflow search provides. But it is difficult to understand specific codes the questioner often presents. So for clarification I use an easy example. This is not meant as application-oriented. I just want to understand how I can change the suffix. var_1 = 10 var_2 = 100 var_3 = 1000 for i in range(1,4): test_i = var_i + 1 print

问题 trying to filter a stream against data within a different list: It works, but I use a for loop in the middle of the stream. I cannot find any information of how to convert the for loop to a stream. I could just .stream() the selction.getItems() than .forEach() and have a new .stream() of DATA.accounts, but that is poor code as it would have to restream on every .forEach. y=1; DATA.accounts.stream() .flatMap(estimate -> estimate.getElements().stream()) .filter( ele-> { // different list; for

问题 I made a variable and added new values with the push attribute but when the for-loop calls it one-by-one it only prints the last value(name) that is "Pranav". Can you help me to know how to fix it and print all the values one-by-one. function tryme() { var names = new Array(); names.push("Bhavesh", "Ajay", "Rahul", "Vinod", "Bobby", "Pranav"); var tryit = document.getElementById("tryit"); for (i = 0; i < names.length; i++) { tryit.innerHTML = "The values are " + names[i] + " . <br>" }; }; 回答1

问题 I have a df that contains one line per item with a range of dates, and I need to expand it to contain one row per day per item. It looks like this: from to id 1 25/02/2019 27/02/2019 A 2 15/07/2019 16/07/2019 B And I want this: date id 1 25/02/2019 A 2 26/07/2019 A 3 27/07/2019 A 4 15/07/2019 B 5 16/07/2019 B I managed to write a code that works but it takes over one hour to run, so I am wondering if there is a more efficient way to do it. My code: df_dates = pd.DataFrame() for i in range(len

问题 I have a df that contains one line per item with a range of dates, and I need to expand it to contain one row per day per item. It looks like this: from to id 1 25/02/2019 27/02/2019 A 2 15/07/2019 16/07/2019 B And I want this: date id 1 25/02/2019 A 2 26/07/2019 A 3 27/07/2019 A 4 15/07/2019 B 5 16/07/2019 B I managed to write a code that works but it takes over one hour to run, so I am wondering if there is a more efficient way to do it. My code: df_dates = pd.DataFrame() for i in range(len

问题 I am creating a mailing label generator for school and am having an issue with a few problems. My program is to take the full name, address, city, state, and zip code for individuals from 0 to 10. When running my program I am having two major problems. The for loop skips the full name "safergets()" and moves on to the address safergets. I moved on to see if everything else works, but my verification for the zip code would not work correctly. I added a printf to see if the input was the same

问题 This question already has answers here : Select N rows above and below match (3 answers) Closed 1 year ago . I'm trying to select 100 rows before and after a marker in a relatively large dataframe. The markers are sparse and for some reason I haven't been able to figure it out or find a solution - this doesn't seem like it should be that hard, so I'm probably missing something obvious. Here's a very small simple example of what the data looks like: timestamp talking_yn transition_yn 0.01 n n

问题 Could someone help with a logical scheme in for loop statement in Python? I try to be more clear: i want to build a for loop cycle where if a condition is TRUE i want to append the same value for the next cells until another condition become TRUE. For example: i have a dataframe called df with 3 columns. The first column is the closing price of a stock (close_price), the second column contains the fast exponential moving average (fast_ema) and the third column contains the slow exponential

问题 I'm writing a program to scrape article title, date and body text from each article on this website's archive and export to a csv file. The website seems to block me at some point and I get this error: HTTPError: Service Unavailable. I believe this is because I am trying to access their website too many times in a short amount of time. I want my code to be able to read where the error happened and pick up where it left off. I've tried adding delays to delay 2 seconds after going through 10

问题 I want to fill a new data frame called hd5 based on a conditions from a old data frame called dfnew1 . Can I do it without a nested for loop ? for( j in 2 : length(hd6) ) { for( i in 1: length(hd5$DATE) ) { abcd= dfnew1 %>% filter( (Date == hd5$DATE[i]) , (StrikePrice== hd6[j]) , (OptionType== "CE")) %>% arrange( dte ) hd5[i,j]= abcd[1,9] } } hd6= [13900,14000,14100,14200] dfnew1 looks like this Date expiry optiontype strikeprice closeprice dte 1/1/2019 31/1/2019 ce 13900 700 30 1/1/2019 31/1