long-integer

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed last year . I am experiencing something weird. I have a big ArrayList of Long numbers. It contains about 200k numbers in ascending order. These numbers are always distinct; they are not necessarily consecutive, but some groups of them usually are. I want to extract a sorted sample of 5k from this list, so basically this is my

问题 Do literal expressions have types too ? long long int a = 2147483647+1 ; long long int b = 2147483648+1 ; std::cout << a << ',' << b ; // -2147483648,2147483649 回答1: Yes, literal numbers have types. The type of an unsuffixed decimal integer literal is the first of int , long , long long in which the integer can be represented. The type of binary, hex and octal literals is selected similarly but with unsigned types in the list as well. You can force the use of unsigned types by using a U

问题 Let's say I have an array that is long enough to access any of its index with int , is there any way to access the index of such an array with long ? And how the Java handle this kind of array? Example: int[] a = new int[]{1,5,2,4........9,2,1} Assume in the above array that 9,2,1 are at indices that are beyond the range of int (2 31 ). How would I access these elements? 回答1: You wouldn't - array indexes are always int values in Java. It doesn't allow for an array with more than Integer.MAX

问题 I am trying to display numbers in a string dynamically, so if the number has decimal's display them but if not don"t show the .0 example: display 5.5 as 5.5 and 5.0 as 5 This is what I have so far: (answer is a double) double temp = answer; long temp2 = (long) temp; if (temp == temp2) { output = String.valueOf(temp2); System.out.println(output); this work's fine up to about 1e18 then will error out because of the maximum size of a Long. So how would I achieve this on bigger numbers like 5

问题 I have long integer value ( ex: 2705758126 ) in NSString. When i try to show it: NSLog(@"%i", [myValue integerValue]); it return: 2147483647. How to show, compare and etc. this long integer 回答1: Try with NSLog(@"%lld", [myValue longlongValue]); 回答2: The documentation recommends using @"%ld" and @"%lu" for NSInteger and NSUInteger, respectively. Since you're using the integerValue method (as opposed to intValue or longLongValue or whatever), that will be returning an NSInteger. 回答3: You should

问题 I am using Javas UUID and need to convert a UUID to a byte Array. Strangely the UUID Class does not provide a "toBytes()" method. I already found out about the two methods: UUID.getMostSignificantBits() and UUID.getLeasSignificantBits() But how to get this into a byte array? the result should be a byte[] with those tow values. I somehow need to do Bitshifting but, how? update: I found: ByteBuffer byteBuffer = MappedByteBuffer.allocate(2); byteBuffer.putLong(uuid.getMostSignificantBits());

问题 I want the following records (currently displaying as 3.200000e+18 but actually (hopefully) each a different long integer), created using pd.read_excel(), to be interpreted differently: ipdb> self.after['class_parent_ref'] class_id 3200000000000515954 3.200000e+18 3200000000000515951 NaN 3200000000000515952 NaN 3200000000000515953 NaN 3200000000000515955 3.200000e+18 3200000000000515956 3.200000e+18 Name: class_parent_ref, dtype: float64 Currently, they seem to 'come out' as scientifically

问题 I need a Hash function with a 256bit output (as long int). First I thought I could use SHA256 from the hashlib but it has an String Output and I need a number to calculate with. Converting the 32 Byte String to a long would work also but I didn't find anything. In struct there is a unpack function but this only works for 8 Byte long types and not for longer longs. 回答1: How about: >>> import hashlib >>> h = hashlib.sha256('something to hash') >>> h.hexdigest()

问题 I have problem writing an unsigned 4 bytes int in java. Either writing a long value in java has different result on 64 bit MacOS and 32 bit Linux (Ubuntu) OR Writing to network a 4 byte unsigned int has a problem. The following call works perfectly on my local OSX writeUInt32(999999,outputstream) Reading it back gives me 999999 However when the application is deployed to a network writing a long value results in some other random number (I assume the endian has been switched?) and reading it

问题 I have a Python version 3.3.0 and I am not sure why it does not let me do long for b and m here... I tried to look up the answers on here and but nothing helped...thanks im getting an error saying NameError: global name 'long' is not defined power = long(b) % long(m) 回答1: In Python 3.x, use int instead of long . From What’s New In Python 3.0, Integers: PEP 237: Essentially, long renamed to int . That is, there is only one built-in integral type, named int ; but it behaves mostly like the old