long-integer

I want to convert Long value to String or Date in this format dd/mm/YYYY. I have this value in Long format: 1343805819061. It is possible to convert it to Date format? AAnkit You can use below line of code to do this. Here timeInMilliSecond is long value. String dateString = new SimpleDateFormat("MM/dd/yyyy").format(new Date(TimeinMilliSeccond)); Or you can use below code too also. String longV = "1343805819061"; long millisecond = Long.parseLong(longV); // or you already have long value of date, use this instead of milliseconds variable. String dateString = DateFormat.format("MM/dd/yyyy", new

I'm consolidating code written by two different people and notice that casting a String value into a Long has been done in two different ways. Coder #1 has done this: String strId = "12345678"; ... Long lId = new Long(strId); While coder #2 has done this: String strId = "12345678"; ... Long lId = Long.valueOf(strId); Functionally, the code operates exactly the same. There's a try/catch block around each bit to handle any NumberFormatException that is thrown. The incoming string value is an 8 digit string that represents a decimal: "12345678" and in both cases it is correctly converted into

This question already has an answer here: How to convert String to long in Java? 8 answers how do you convert a string into a long. for int you int i = 3423; String str; str = str.valueOf(i); so how do you go the other way but with long. long lg; String Str = "1333073704000" lg = lg.valueOf(Str); This is a common way to do it: long l = Long.parseLong(str); There is also this method: Long.valueOf(str); Difference is that parseLong returns a primitive long while valueOf returns a new Long() object. The method for converting a string to a long is Long.parseLong . Modifying your example: String s

Here's my code: #include <stdio.h> int main(int argc, char *argv[]) { unsigned long int x = 0; // trying to make x = 2,147,483,648 x = 1 << 31; printf("%lu", x); } It's returning that x = 18446744071562067968. I read that unsigned long int should go up to 4,294,967,296, so why can't I use 1 << 32 to set x equal to 2,147,483,648? 1 << 31 causes undefined behaviour, if your system has 32-bit ints. The literal 1 is a signed int. You need to do an unsigned shift instead of a signed shift: x = 1UL << 31; I added L so that the code is still correct even on a 16-bit system, and it doesn't hurt to do

I am at the last step to finalize my program, however whenever I enter my integer (long) I get a input mismatch: Compiler message: "Exception in thread "main" java.util.InputMismatchException: For input string: "4388576018402626" at java.util.Scanner.nextInt(Scanner.java:2097) at java.util.Scanner.nextInt(Scanner.java:2050) at CreditCardValidation.main(CreditCardValidation.java:12)" My code is as follows: import java.util.Scanner ; //import Scanner public class CreditCardValidation { public static void main (String[] args){ Scanner kbd = new Scanner(System.in) ; System.out.println("Please