long-integer

This is my Sender entity @Entity public class Sender { @Id @GeneratedValue(strategy = GenerationType.AUTO) private long senderId; ... ... public long getSenderId() { return senderId; } public void setSenderId(long senderId) { this.senderId = senderId; } } When I try to execute following query: StringBuilder query = new StringBuilder(); query.append("Select sender.* "); query.append("From sender "); query.append("INNER JOIN coupledsender_subscriber "); query.append("ON coupledsender_subscriber.Sender_senderId = sender.SenderId "); query.append("WHERE coupledsender_subscriber.Subscriber

The book The C Programming Language talks about "the most restrictive type" in section 8.7, Example — A Storage Allocator : Although machines vary, for each machine there is a most restrictive type: if the most restrictive type can be stored at a particular address, all other types may be also. On some machines, the most restrictive type is a double ; on others, int or long suffices. In their code, the union header is aligned using the type long . What is meant by the most restrictive type? Is it perhaps the largest type (e.g., double ), or is there another approach? CPUs often require that

I am running the exact same code on both windows and mac, with python 3.5 64 bit. On windows, it looks like this: >>> import numpy as np >>> preds = np.zeros((1, 3), dtype=int) >>> p = [6802256107, 5017549029, 3745804973] >>> preds[0] = p Traceback (most recent call last): File "<pyshell#13>", line 1, in <module> preds[0] = p OverflowError: Python int too large to convert to C long However, this code works fine on my mac. Could anyone help explain why or give a solution for the code on windows? Thanks so much! You'll get that error once your numbers are greater than sys.maxsize : >>> p = [sys

How do I find the modulo (%) of two long values in Java? My code says 'Integer number too large' followed by the number I'm trying to mod. I tried casting it to a long but it didn't work. Do I have to convert it to a BigInteger and use the remainder method? Thanks. The % operator does work for longs. It sounds like you may have forgotten to stick L at the end of a numeric literal, as in 123456789L . Can we see your code? You can only have an integer up to 2 147 483 647. If you want to go bigger than that, say 3 billion, you must specify it to be a long class Descartes { public static void main

So I have recently written the following code: import java.util.Scanner; public class TrainTicket { public static void main (String args[]) { Scanner money = new Scanner(System.in); System.out.print("Please type in the type of ticket you would like to buy.\nA. Child B. Adult C. Elder."); String type = money.next(); System.out.print("Now please type in the amount of tickets you would like to buy."); int much = money.nextInt(); int price = 0; switch (type) { case "A": price = 10; break; case "B": price = 60; break; case "C": price = 35; break; default: price = 0; System.out.print("Not a option ;

Resolution: It turns out there is (probably) "nothing wrong" with the code itself; it is just inefficient. If my math is correct, If I leave it running it will be done by Friday, October 14, 2011. I'll let you know! Warning: this may contain spoilers if you are trying to solve Project Euler #3. The problem says this: The prime factors of 13195 are 5, 7, 13 and 29. What is the largest prime factor of the number 600851475143 ? Here's my attempt to solve it. I'm just starting with Java and programming in general, and I know this isn't the nicest or most efficient solution. import java.util

I am trying to understand arithmetic overflow. Suppose I have the following, unsigned long long x; unsigned int y, z; x = y*z; y*z can lead to an integer overflow. Does casting one of the operands to an unsigned long long alleviate this issue. What is the expected result of the multiplication of a 64-bit operand with a 32-bit operand? unsigned long long x; unsigned int y, z; x = y*z; The evaluation of the expression y*z is not affected by the context in which it appears. It multiplies two unsigned int values, yielding an unsigned int result. If the mathematical result cannot be represented as