long-integer

class LongDiv{ public static void main(String [] args){ final long x = 24*60*60*1000*1000; final long y = 24*60*60*1000; System.out.println(x/y); } } although the expected answer is 1000, but the javac gives it as 5. Reason? The long x you are creating isn't the value you expected. It is in the integer range. To create longs, use: final long x = 24L*60L*60L*1000L*1000L; final long y = 24L*60L*60L*1000L; System.out.println(x/y); The x you computed, in the integer range, was 500654080 . This divided by the y ( = 86400000 ), results in 5.794607407407407... . Java truncates the decimal part which

The hibernate named query returns a BigDecimal for a column that has datatype NUMBER. select col1 as "col1" from table1 union select col2 as "col1" from table2 On client side, I expect the datatype of col1 to be long (primitive) I do this: <return-scalar column="col1" type="java.lang.Long" /> or <return-scalar column="col1" type="long" /> In both cases, I get : java.lang.ClassCastException: java.math.BigDecimal incompatible with java.lang.Long How can I fix this? My suspiscion, something wrong with the aliasing? Oracle NUMBER maps to BigDecimal in Hibernate by default. Try setting the type to

In C on a 32-bit system, which data type will store (and can therefore print) the largest integer? Is it long long or unsigned long ? Is there an unsigned long long ? And which is the most precise and politically correct? wnoise Your question is a bit unclear, but intmax_t is the largest signed integer-valued type (and uintmax_t is the largest unsigned integer type). These are typedefs defined in <stdint.h> , but if you are printing them, you need <inttypes.h> instead, and the PRInMAX macros for various values of n . Without beating around the bush I would like to say that sometimes not in

I have an Object obj that I know is actually a long . In some Math code I need it as double . Is it safe to directly cast it to double? double x = (double)obj; Or should I rather cast it first to long and then to double. double x = (double)(long)obj; I also found another (less readable) alternative: double x = new Long((long)obj).doubleValue(); What are the dangers/implications of doing either? Solution Summary : obj is a Number and not a long . Java 6 requires explicit casting, e.g.: double x = ((Number)obj).doubleValue() Java 7 has working cast magic: double x = (long)obj For more details on

I am using Javas UUID and need to convert a UUID to a byte Array. Strangely the UUID Class does not provide a "toBytes()" method. I already found out about the two methods: UUID.getMostSignificantBits() and UUID.getLeasSignificantBits() But how to get this into a byte array? the result should be a byte[] with those tow values. I somehow need to do Bitshifting but, how? update: I found: ByteBuffer byteBuffer = MappedByteBuffer.allocate(2); byteBuffer.putLong(uuid.getMostSignificantBits()); byteBuffer.putLong(uuid.getLeastSignificantBits()); Is this approach corret? Are there any other methods

Python is more strongly typed than other scripting languages. For example, in Perl: perl -E '$c=5; $d="6"; say $c+$d' #prints 11 But in Python: >>> c="6" >>> d=5 >>> print c+d Traceback (most recent call last): File "<stdin>", line 1, in <module> TypeError: cannot concatenate 'str' and 'int' objects Perl will inspect a string and convert to a number, and the + - / * ** operators work as you expect with a number. PHP is similar. Python uses + to concatenate strings so the the attempted operation of c+d fails because c is a string, d an int. Python has stronger sense of numeric types than does

I have a bunch of hex strings, one of them, for example is: d1bc4f7154ac9edb which is the hex value of "-3333702275990511909". This is the same hex you get if you do Long.toHexString("d1bc4f7154ac9edb"); For now, let's just assume I only have access to the hex string values and that is it. Doing this: Long.parseLong(hexstring, 16); Doesn't work because it converts it to a different value that is too large for a Long. Is there away to convert these unsigned hex values into signed longs? Thanks! You can use BigInteger to parse it and get back a long : long value = new BigInteger(