logout

Logout from http_basic auth in Symfony2

隐身守侯 提交于 2019-12-22 04:58:13
问题 Whenever I go to /admin/logout , I'm correctly redirected to the root of my project but still logged in when I visit /admin/ as I'm not prompted for credentials. Here is my configuration: security.yml security: firewalls: admin_area: pattern: ^/admin http_basic: ~ stateless: true switch_user: { role: ROLE_SUPER_ADMIN, parameter: _want_to_be_this_user } logout: { path: /admin/logout, target: / } AdminBundle/Resources/config/routing.yml logout: pattern: /logout app/config/routing.yml admin:

Logout functionality in android

﹥>﹥吖頭↗ 提交于 2019-12-21 20:19:24
问题 I am making a kind of social networking app. I am implementing log-out functionality in it. On Logout button click it should navigate to login screen but instead it is now navigating to the home page screen.I am using the following code for logout.. IntentFilter intentFilter = new IntentFilter(); intentFilter.addAction("com.package.ACTION_LOGOUT"); registerReceiver(new BroadcastReceiver() { public void onReceive(Context context, Intent intent) { System.out.println("onReceive Log out in

OpenID. How do you logout

橙三吉。 提交于 2019-12-21 07:07:20
问题 On a website I have implemented the login using OpenID (based on StackOverflow). But I can't seem to logout. On my host I can logout but when the user tries to login again (especially with google) the authentication goes through without requiring the user to type in name and password. How can I indicate to the OpenID Provider that a user is no longer logged into the site? 回答1: OpenID authenticates users to your site, when then starts a session on your site. You destroy or invalidate your site

How to implement Logout functionality for Facebook graph API

折月煮酒 提交于 2019-12-21 06:06:08
问题 I implemented Facebook Graph API in my iPhone App and I successfully post it in a wall. But each time I end my application and come back it stores my credentials (in Safari I guess as a cookie). It asks my permission with my previous credentials. But at this point I want my Facebook API should prompt for a new username and password login for requesting permission. In simple I want to logout of my Facebook when i select a button in my App. 回答1: How did you log in to facebook in the first place

Redirecting the django built-in logout view after successfull logout

匆匆过客 提交于 2019-12-21 05:25:19
问题 I am using django to build a login and logout page , below are my codes urls.py from django.conf.urls.defaults import * from django.conf import settings from django.core.urlresolvers import reverse urlpatterns = patterns('', url(r'^$', 'learn_django.views.home_page'), url(r'^login/$', 'learn_django.views.login'), url(r'^logout/$', 'django.contrib.auth.views.logout', {'template_name': 'logout.html'}), ) views.py from django.shortcuts import render_to_response from django.template import

Logout clear SharedPreferences

强颜欢笑 提交于 2019-12-21 03:57:04
问题 I have login page that save username and password to Shared Preferences. I have another Activity class that include logout button. I want to clear Shared Preferences when click logout button. Problem is I dont get the SharedPreferences from this class. How can I get the SharedPreferences ? LoginPage public class MainActivity extends Activity { public SharedPreferences.Editor loginPrefsEditor; public SharedPreferences loginPreferences; private Boolean saveLogin; @Override protected void

MembershipUser.IsOnline is true even after logout

本秂侑毒 提交于 2019-12-21 03:41:10
问题 I'm currently creating a website using Visual Studio 2010. I'm using the default membership schema in SQL Server 2008 for user authentication. Now I'm facing the following problem. When a user logs out, the membership.IsOnline property of that user should be set to false. However that it is not happening; membership.IsOnline property of that user is still true. I'm using the LoginStatus control to provide a logout link to the user. I have tried to follow User.IsOnline = true even after

show logout button along with the name of user after successfull login

余生长醉 提交于 2019-12-20 07:41:19
问题 I am a yiibie, and i am stuck at a point. I have three roles in my project. 1.Admin. 2.Owner 3. Authenticated User. I have a header and a footer widget.In header widget which is the top section has a signup and login link. i want to show my user name and a logout link after his successful login. I do not want to make another widget. i Know the logic, we can use if else. If a user has been logged in, show his name and logout link at the top section(header widget). else if he is a normal user

Sessions get messed up on external host

僤鯓⒐⒋嵵緔 提交于 2019-12-20 04:06:19
问题 The problem sounds like this: The log-in using sessions works perfect on my localhost, but when the EXACTLY same files are uploaded to my host (hostgator), the sessions don't or, or they get messed up. Also the log-out feature doesn't work on the host. I've checked and every page has the session_start(); inside it. The session is not destroyed, even if my logout.php looks like this: <?php session_start(); $_SESSION = array(); session_unset(); session_destroy(); header("location:index.php");

forcefully log out a specific user among all online users

有些话、适合烂在心里 提交于 2019-12-20 03:05:17
问题 In my site administrator can view list all other online users. Administrator can also disable any account from that list. Everything was going fine so far. But now I decided to log out the user which is being disabled. How can I do a log out operation for a particular user from the above specified online user list? NOTE: I'm using default membership schema for my SQL Server database. 回答1: You cannot logout a user from outside of their session. See Programatically logout an ASP.NET user for a