location

js 跳转链接的几种方式

由 ﹥＞﹥吖頭↗ 提交于 2019-12-24 04:00:03
1、跳转链接 在当前窗口打开 window.location.href="http://www.baidu.com" 等价于 <a href="baidu.com" target="_self">go baidu</a> 2、跳转链接 在新窗口打开 window.open("http://www.baidu.com") 等价于 <a href="baidu.com" target="_blank">go baidu</a> 3、跳转链接 返回上一页 window.history.back(-1); 4 、跳转链接 self.location.href="baidu.com" self 指代当前窗口对象，属于window 最上层的对象。 location.href 指的是某window对象的url的地址 self.location.href 指当前窗口的url地址，去掉self默认为当前窗口的url地址， 一般用于防止外部的引用 　top.location.href:为引用test.html页面url的 父窗口对象的url 如果你的网页地址是: http://www.a.com， 别人的是 http://www.b.com , 他在他的页面用iframe等框架引用你的 http://www.a.com ,那么你可以用: if(top.location.href!=self

location.getspeed() update

由 被刻印的时光 ゝ 提交于 2019-12-24 03:24:27
问题 I have a litte problem. I located a location.getSpeed() method on the onLocationChanged() method, and .getSpeed() usually doesn't update/change to 0km/h when I stay in same place. Where should I locate a location.getGpeed() method, that the update showed 0km/h when I stay in place? And another question. This is my locationListener : private final LocationListener locationListener = new LocationListener() {public void onLocationChanged(Location location) { boolean var = false; float distance;

Cannot resolve symbol 'FusedLocationProviderClient'

由 纵然是瞬间 提交于 2019-12-24 03:21:11
问题 I having a error Cannot resolve symbol 'FusedLocationProviderClient' while declaring private FusedLocationProviderClient mFusedLocationClient; The same is asked here Cannot Resolve Symbol: FusedLocationProviderClient. Google play services version used 11.0.1 . But still am having the error while using the latest play services. 回答1: FusedLocationProvider is part of play-services-location. You are using play-services-maps. Add dependency : compile 'com.google.android.gms:play-services-location

NullPointerException while fetching current GPS

由 左心房为你撑大大i 提交于 2019-12-24 02:42:55
问题 I have a test screen where there is a button - where it is pressed it calls the service. I'm trying to implement a way to get the current gps location of the current user and it is crashing when it tries to call. Can anyone tell what the problem is? package com.example.whereyouapp; import java.util.Arrays; import android.app.AlarmManager; import android.app.PendingIntent; import android.app.Service; import android.content.ContentValues; import android.content.Context; import android.content

What is default settings to reffer to file location in xcode project?

由 那年仲夏 提交于 2019-12-24 02:17:01
问题 What is default settings to reffer to file location in xcode project ? i have doubts between them relative to build project relative to project relative to enclosing group relative to source path Absolute path 回答1: This doesn't seem to be well documented. As I read "How Files are Referenced" in the "Xcode Project Management Guide": If the file is in the project's folder, you get a reference relative to an enclosing group. If the file is created by one of the targets, you get a reference

Convert a 3D location to a 2D on-screen point. (XYZ => XY)

由 家住魔仙堡 提交于 2019-12-24 02:08:08
问题 I am wondering how exactly I can convert a location (X Y Z) to a point on screen (X Y). I have a player (the player you control) who is in (X Y Z) co-ordinates and another player who is also in (X Y Z) co-ordinates. How exactly can I convert the other player's X Y Z to X Y on screen so that I can draw a name above him/it using the X Y. Hope that makes sense... Edit: Here is my gluProject code: IntBuffer viewport = GLAllocation.createDirectIntBuffer(16); FloatBuffer modelview = GLAllocation

Fully-qualified urls in HTTP Location header. Why it is important?

由 心不动则不痛 提交于 2019-12-24 01:23:46
问题 So I've got some warnings from Fiddler that I have bad urls in HTTP Location header and they are should be fully-qualified. Why it's so important and what issues that can lead to? 回答1: The old standard for HTTP/1.1 (RFC 2616 § 14.30) required that Location be an absolute URI. Implementation experience showed that this was not important, and many implementations allowed relative URIs in Location , so the current standard (RFC 7231 § 7.1.2) allows relative URIs. 来源： https://stackoverflow.com

LocationManager gives NETWORK_PROVIDER disabled

由 核能气质少年 提交于 2019-12-24 00:48:45
问题 I need to retrieve user's location by 3G or WIFI. This is what I'm trying to do: LocationListener locationListener = new LocationListener() { public void onLocationChanged(Location location) { manageLocation(location); } public void onStatusChanged(String provider, int status, Bundle extras) { } public void onProviderEnabled(String provider) { } public void onProviderDisabled(String provider) { } }; locationManager.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0,

nginx配置文件root和alias区别

由 让人想犯罪 __ 提交于 2019-12-23 22:20:43
总结： alias指定的目录是准确的，root是指定目录的上级目录，并且该上级目录要含有location指定名称的同名目录 root的处理结果是：root路径＋location路径 + http后面的地址 alias的处理结果是：使用alias路径替换location路径 + http后面的地址 关于 / 的使用： alias虚拟目录配置中，location匹配的path目录如果后面不带"/"，那么访问的url地址中这个path目录后面加不加"/“不影响访问，访问时它会自动加上”/"； 但是如果location匹配的path目录后面加上"/"，那么访问的url地址中这个path目录必须要加上"/"，访问时它不会自动加上"/"。如果不加上"/"，访问就会失败！ root目录配置中，location匹配的path目录后面带不带 “/”，都不会影响访问 为了避免不必要的困扰可以都以 “/” 结尾 示例： 我在linux 服务器上有一个 html， 路径如下 /app/test/index.html 我想通过 http://ip/test/index.html 来进行访问： 可以在Nginx 的conf 中 nginx.conf 中加入配置： location /test/ { root /app/; } 或者 location /test/ { alias /app/test/; }

Not gettting accurate location in some android phones

由 允我心安 提交于 2019-12-23 22:03:58
问题 I have used below code. It work fine but in some devices like Redme,Asus not getting accurate location.It shown me too far from my current location aprox 20 km away.Not getting where is problem somebody have idea please share there ideas.Thanks in advance. public class Currentlocation extends Service implements LocationListener { private final Context mContext; // flag for GPS status boolean isGPSEnabled = false; // flag for network status boolean isNetworkEnabled = false; // flag for GPS
订阅 location