location

JavaScript_BOM对象

╄→尐↘猪︶ㄣ 提交于 2020-01-10 21:56:21
BOM(浏览器对象模型),它可以对浏览器窗口进行访问和操作,使用BOM,我们可以移动窗口、改变状态中的文本及执行其他与页面内容不直接相关的动作。 简而言之:BOM对象的功能就是使JavaScript有能力与浏览器’对话’,以便达到我们想要的效果。 一.Window对象 1.简单说明 所有的浏览器都支持window对象; 从概念上来讲,一个HTML文档对应一个window对象; 从功能上来说,它可以控制浏览器的窗口; 从使用上讲,window对象不需要创建对象,直接使用即可。 2.window对象方法 2.1.alert():页面弹框提醒 var s =window.alert("hi"); //返回结果为undefined,即无返回值 console.log('s='+s); 2.2.confirm():页面弹框让进行选择,返回值为布尔值(选择'确认",则返回true;选择'取消'返回false) var res= window.confirm("this is a person ?") console.log('res='+res); 2.3.prompt():页面弹框让用户进行输入,点击'确定'后返回值为用户输入的字符串值,点击'取消'后,返回值为null var name = window.prompt("pelase input your name:"); console

JavaScript Window Location

心不动则不痛 提交于 2020-01-10 21:30:26
window.location对象可用于获取当前页面地址(url)并把浏览器重定向到新页面。 window.location 对象可不带 window 前缀书写。 一些例子: window.location.href 返回当前页面的 href (URL) window.location.hostname 返回 web 主机的域名 window.location.pathname 返回当前页面的路径或文件名 window.location.protocol 返回使用的 web 协议(http: 或 https:) window.location.assign 加载新文档 window.location.assign() 方法加载新文档。 实例 加载新文档: <!DOCTYPE html> <html> <body> <h1>window.location 对象</h1> <input type="button" value="加载新的文档" onclick="newDoc()"> <script> function newDoc() { window.location.assign("http://www.w3school.com.cn") } </script> </body> </html> 来源: 站长资讯平台 来源: https://www.cnblogs.com

Nginx Rewrite相关功能

和自甴很熟 提交于 2020-01-10 18:03:09
Nginx服务器利⽤ngx_http_rewrite_module 模块解析和处理rewrite请求,此功能依靠 PCRE(perl compatible regularexpression),因此编译之前要安装PCRE库,rewrite是nginx服务器的重要功能之⼀,⽤于实现URL的重写,URL的重写是⾮常有⽤的功能,⽐如它可以在我们改变⽹站结构之后,不需要客⼾端修改原来的书签,也⽆需其他⽹站修改我们的链接,就可以设置为访问,另外还可以在⼀定程度上提⾼⽹站的安全性。 1 ngx_http_rewrite_module模块指令 官方文档:https://nginx.org/en/docs/http/ngx_http_rewrite_module.html 1.1 if指令 # ⽤于条件匹配判断,并根据条件判断结果选择不同的Nginx配置,可以配置在server或location块中进⾏配置,Nginx的if语法仅能使⽤if做单次判断,不⽀持使⽤if else或者if elif这样的多重判断,⽤法如下: if (条件匹配) { action } # 使⽤正则表达式对变量进⾏匹配,匹配成功时if指令认为条件为true,否则认为false,变量与表达式之间使⽤以下符号链接: = #⽐较变量和字符串是否相等,相等时if指令认为该条件为true,反之为false。 != #

where is the actual data in a mysql db stored on a linux machine? [closed]

醉酒当歌 提交于 2020-01-10 17:46:50
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 7 years ago . Which files are the actual files holding the data in the tables in a mysql db? I went to /var/lib/mysql/ and I can see there a bunch of relatively small directories corresponding to my tables, and a lot of files named servername-bin.0000001 etc. Is the data stored in those files? 回答1: It is installation specific

Rewrite跳转场景

血红的双手。 提交于 2020-01-10 17:34:15
Rewrite跳转场景 URL看起来更规范,合理 企业会将动态URL地址伪装成静态地址提供服务 网址换新域名后,让旧的访问跳转到新的域名上 服务端某些业务调整 Rewrite跳转实现 Rewrite实用场景 Nginx跳转需求的实现方式 使用rewrite进行匹配跳转 使用if匹配全局变量后跳转 使用location匹配再跳转 rewrite放在server{},if{},location{}段中 对域名或参数字符串 使用if全局变量匹配 使用proxy_pass反向代理 常用的正则表达式元字符 字符 说明 ^ 匹配输入字符串的起始位置 $ 匹配输入字符串的结束位置 * 匹配前面的字符零次或多次 + 匹配前面的字符一次或多次 ? 匹配前面的字符零次或一次 . 匹配除\n之外的任何单个字符,使用诸如"[.\n]"之类的模式,可匹配包括"\n"在内的任意字符 \d 匹配纯数字 [0-9] {n} 重复多次 {n,} 重复n次或更多次 [c] 匹配单个字符c [a-z] 匹配a-z小写字母的任意一个 [a-zA-Z] 匹配a-z小写字母或A-Z大写字母的任意一个 Rewrite命令 语法: rewrite <regex> <replacement> [flag]; 正则 跳转后的内容 rewrite支持的flag标记 flag标记说明: 标记 说明 last 相当于Apache的[L

How to find postcode by latitude and longitude for UK

一个人想着一个人 提交于 2020-01-10 15:40:10
问题 I am working on a android app in which i came across a situation in which i need to get the current user postcode, so i am getting the current latitude and longitude but is there any way to find the current postcode by providing latitude and longitude. If any web service or database to provide this information is available then please let me know about it. 回答1: If you are talking about PostalCode then, use this.. Geocoder geoCoder = new Geocoder(getApplicationContext(), Locale.getDefault());

unity对接百度地图(显示地图和自身位置)

蓝咒 提交于 2020-01-10 13:11:05
我是将unity工程导出为android工程,将定位脚本和需要的jar包依赖等加入,如下 LocationCustomDemo package com . baidu . map . demo . layers ; import android . app . Activity ; import android . content . Context ; import android . content . Intent ; import android . os . Bundle ; import android . util . Log ; import android . widget . Toast ; import com . baidu . location . BDAbstractLocationListener ; import com . baidu . location . BDLocation ; import com . baidu . location . LocationClient ; import com . baidu . location . LocationClientOption ; import com . baidu . map . R ; import com . baidu . map . UnityPlayerActivity ;

Getting surrounding zip codes from a location using Apple Map Kit

99封情书 提交于 2020-01-10 06:12:46
问题 I'm getting started on Map Kit for my job and I have a IOS project I am working on where it involves Map Kit, I know how to search for a location and pin point it but my issues is that part of my project involves getting the next 10-15 zip codes of the surrounding areas of my central location and receive the cities that are in each zip code, i really don't know how to implement it and I need help. an explanation or a snippet of code would be much appreciated. 回答1: Zip codes like this aren't

map.setmylocationenabled(true) not working

六眼飞鱼酱① 提交于 2020-01-10 03:47:04
问题 I'm working with Google Maps in my android app. I need to recenter the map to the client's current location. I used the following statement - map.setmylocationenabled(true); This displays a button on the top right but clicking that doesn't work. The button click listener: mMap.setOnMyLocationButtonClickListener(new GoogleMap.OnMyLocationButtonClickListener() { @Override public boolean onMyLocationButtonClick() { mMap.addMarker(new MarkerOptions().position(myLatLng).title("My Location")); mMap

Redirect in PHP without use of header method

家住魔仙堡 提交于 2020-01-10 01:03:28
问题 This contact.php form was working to handle a submit and then redirect to a new page and then all of a sudden just stopped working. I have tried adding error handling and also moving header to the top in front of all other, but neither works. The form is still submitting the data as expected, it's just the redirect that doesn't work. Any ideas would be appreciated. <?php include 'config.php'; $post = (!empty($_POST)) ? true : false; if($post) { $email = trim($_POST['email']); $subject =